The Derivation of the Mass – Space Equation from “Spherical Electromagnetic Wave”
Next, I will analyze and derive the “mass – space equation” from my own physics model of elementary particle (simplified model).
We shift temporarily to another topic: What Einstein’s energy – mass equation E = m c² reflects is neither kinematic energy nor potential energy but internal energy. What’s internal energy and how it’s deposited?
Just set out from the experiment of the annihilation of the positron – electron pair releases energy: released photon(s) travelling in straight line. No residue left. Seems that the elementary particle such as electron is “confined electromagnetic wave”? How can electromagnetic wave be confined?
The “mass point” is just an abstract conception in theoretical physics. There is no such thing in nature. The real internal energy should not be deposited in an abstract “mass point”. We must construct a feasible model with effective mathematical – physical method.
At this moment, we imagine something: we can understand the sea waves in the Pacific, Atlantic, Indian Oceans, which travelling on the spherical surface of the Earth and they can’t shock the moon…
Then, the conception of “spherical electromagnetic wave” generated. (Why light can travel in a circle without the help of gravity? My consideration is it should be the affair of the “mechanism of formation of matter”, which should be natural rules more fundamental than the fundamental natural force.)
Thinking in this way, I initiated my “physics model of elementary particle”: elementary particles can be divided into two big categories depending on matter state:
Matter state 1: Spherical electromagnetic wave. It’s the physics model for such elementary particles as electron, proton, etc. Construct a model of spherical electromagnetic wave in this way: circle type of standing electromagnetic wave on any normal cutting plane of the small sphere. Then, the energy of the electromagnetic wave is confined on the small spherical surface (deposited).
Matter state 2: A section of electromagnetic wave travels in straight line in the speed of light c. It is the physics model of a released photon.
The elementary particles have an inherent property of spiral chirality. The corresponding anti - elementary particles have an inherent property of contrary spiral chirality. Either left – handed or right – handed. The electric interaction or charge is directly reflected by the spiral chilarity of spherical electromagnetic wave. If an elementary particle is neutral, it should have no spiral chirality. (This point is not the emphasis in this context. So, the details would not be provided.)
But for intuition sake, the “circle type of standing wave” can serve as a simplified model. And for convenience in calculation in this context, the simplified model is applied. And it’s considered that the energy on the spherical surface be converted entirely into the “circle type of standing wave”.
There is a question, why the energy equation for a released photon is E = hγ (here “γ” is frequency) in Quantum theory and need not to take the number of crests (n of λ, here n is a natural number) into account?
In my physics model, a released photon is just a section of electromagnetic wave, its energy E should ∝ the number of crests (n of λ).
It implies that all released photons have the same number of crests (n of λ)? Temporarily suppose it is and see what will happen.
Next, we refer to the simplified physics model (circle type of standing wave). Unfold the standing wave, it turns into two released photons (for simplicity sake, just consider that it’s one released photon).
We watch the game in counter way, it’s one released photon turn into a standing wave.
And we got: standing wave which constitute all kinds of elementary particles have the same number of crests (note: nt of λt, when referring to travelling waves; and ns of λs, when referring to standing waves. The lower index “t” means travelling wave while “s” means standing wave in this context).
Next, we try to use the physics model for elementary particle and the temporary conclusion of same number of crests in this chapter to calculate the radius of elementary particle of “matter state 1”.
Below, we calculate the central line of the helical track instead of the helical track itself because the speed of light should be calculated on the central line. And the wave length λt should be the projective wavelength on the central line.
E = Mc² = 2hγt = 2hc / λt then:
λt = 2h / Mc then:
The radius of elementary particle is:
r = ntλt / 2π = nth /πcM
Because nt, h, π, c are all constants, we use a constant “a” for simplicity and a = nth/πc, then:
r = a / M ③
Namely, r ∝1/ M. In fact, it’s the same meaning as L ∝ 1 / M ahead.
The existence of the mass – space equation does not depend on reference frame / movement.
Liqiang Chen
Feb 27, 2023
Now piggy doubts whether the pig head understands physics or not as the what coffin box from what CN said in PHF in 2020:
https://physicshelpforum.com/threads/the-game-of-match-sticks.16181/post-50090
In fact, shortly after piggy left PHF in 2020, a local guy stopped piggy on the street and insisted he had a physics question to ask me. Piggy just replied to that guy: “I know nothing about physics”. Bounce…