Next, go on with normal scientific research on most basic level.
(Below is some materials in previous post or in other thread, piggy reorganized them and put it here for reference to those guys who are willing to touch the elephant in an alternative angle)
The energy – momentum equation vs the energy – mass equation, touchy and feely:
First, introduce the energy – momentum equation E² = p²c² + (m0c²)².
Next, just think it in natural way.
1. If the energy – momentum equation reflects the stationary situation, then, momentum p naturally equals to zero. Then, we got E² = 0 + (m0c²)², namely: E = m0c². It can be denoted exactly as E0 = m0c². This is the energy - mass equation in stationary situation;
2. If the energy – momentum equation reflects the dynamic situation, then, momentum p ≠ 0.
Transform the energy – momentum equation E² = p²c² + (m0c²)² into p² – E² / c² = - m0²c²,
- m0²c² = m0²v² / (1 – v² / c²) – m0²c² / (1 – v² / c²),
As the analysis ahead demonstrated, dynamic mass or say relativistic mass in SR should be reasonable, then:
Because m² = m0² / (1 – v² / c²), then, - m0²c² = m²v² – m²c² = p² – E² / c²,
Because m²v² = p², then, – m²c² = – E² / c²,
Then E² = m²c ^4, namely: E = mc². This is the energy – mass equation in dynamic situation.
Below is the transformation in counter way:
E = mc² is Dynamic energy - mass relationship in nature. It’s a basic natural relationship. (“Dynamic” means the particle is moving and hints it has momentum);
Next square both sides: E² = m²c ^4, namely: m²c² = E² / c², then, add a negative mark on both side: – m²c² = – E² / c²;
Add two “redundant” items m²v² on both sides: m²v² – m²c² = m²v² – E² / c²;
Because m²v² = p², then, m²v² – m²c² = p² – E² / c²;
Because m = γm0, (pay attention here, it just means that you can consider the magnitude of the moving dynamic mass m is γm0, but not means the particle be rest), square both sides: m² = m0² / (1 – v² / c²);
Then, m0²v² / (1 – v² / c²) – m0²c² / (1 – v² / c²) = p² – E² / c²;
A mathematical calculation: m0²v² / (1 – v² / c²) – m0²c² / (1 – v² / c²) = - m0²c²;
Then, - m0²c² = p² – E² / c²;
Transform it in math, then, E² = p²c² + (m0c²)².
It’s the so called energy – momentum equation.
If it’s the stationary situation, v = 0, then, no math game can be played. Then, it’s just an energy - mass equation in stationary situation: E0 = m0c².
Liqiang Chen
陈力强
Dec 24, 2021
Now piggy doubts whether the pig head understands physics or not as the what coffin box from what CN said in PHF in 2020:
https://physicshelpforum.com/threads/the-game-of-match-sticks.16181/post-50090
In fact, shortly after piggy left PHF in 2020, a local guy stopped piggy on the street and insisted he had a physics question to ask me. Piggy just replied to that guy: “I know nothing about physics”. Bounce…
给他江门地方黑恶势力钟永康集团及新会一中九一四班谁谁一个超文革赛阎王光荣称号快快全世界全宇宙打靶啦。当今时代，全世界没有什么人能够值得如此殊荣。呵呵
