@Albuquerque,
Right, so you don't know the answer. Here it is:
I'll do it by energy, because it's faster and I don't need a diagram.
mgh = (1/2)mv^2 + (1/2)Iw^2
where m = mass, g = acceleration due to gravity, h = height of the cylinder at the start, v = velocity of the center of mass, I = moment of inertia, and w = angular speed of rotation.
mgh = (1/2)mv^2 + (1/2)[(1/2) m r^2](v/r)^2
since the moment of inertia of a cylinder is (1/2)mr^2.
mgh = (1/2)mv^2 + (1/4)mv^2 = (3/4) mv^2
gh = (3/4) v^2
v = SQRT[(4/3) gh]
And that was a very simple problem that any high school physics student in America with decent grades could have solved. I couldn't have given you anything much simpler. Newtonian mechanics not your best area? You specify an area of physics that a high school student might be familiar with and I'll give you an elementary physics problem in that area. Thermodynamics, electrodynamics, gravity, acoustics, fluid mechanics? You pick your best subject and I'll write a basic problem. I know so little about science and am so "dumb," it should be a breeze for you.
Unlike you, I put in the years of study to be awarded college degrees in the subject.