akaMechsmith wrote:Ican, I am assuming, (till I know better) that the three points of the triangle are located thusly.
One point at the center of the sun
One point at Earths orbit
One point located at the point in space where a line drawn from the other two points intersect at an angle of one second.
Ok, now I understand. The mystery is solved! I employed a different but also valid definition of a parsec. Here's the picture I meant to communicate --
One point, S, at the center of the sun.
One point, E, at the center of the earth.
One point, O, on the earth's orbit.
akamechsmith wrote: if the base of the triangle is the radius of Earths orbit then the point of intersection is very neatly located.
You are correct. Your guage model works, if (as you implied) S--E is the base and O represents the point in space one parsec distant from both S and E. In that case, the angle between O--S and O--E would be 1 second and the length of both O--S and O--E would be one parsec or 206,265 times S--E.
HERE'S HOW MY GUAGE PRODUCES THE SAME RESULT AS YOURS
Both of the legs, S--E and S--O extend from S, the apex of my isoceles triangle. E--O is the base. The length of S--E = the length of S--O. The lengths of S--E and S--O equal the radius of the earth's orbit which
allegedly =
92,911,164.75 miles. The angle between S--E and S--O equals 1 second.
The circumference of a circle, whose radius is = S--E = S--O = 92,911,164.75 miles, is equal to 583,778,065.2 miles.
There are 360 x 60 x 60 = 1,296,000 one-second angles in a circle. So, 583,778,065.2 miles divided by 1,296,000 one-second angles = E--O =
450.446038 miles = 450.45 miles.
A
parsec = 3.26 times the distance that light is
alleged to travel in one year = 3.26 x 186,282.4231 miles per second x 365.25 days per year x 24 hours per day x 3600 seconds per hour =
19,164,321,400,000 miles.
The length of a
parsec (19,164,321,400,000 miles) divided by the
alleged radius of the earth's orbit (
92,911,164.75 miles) = the factor
F = 206,265 .
Also, the length of E--O = a parsec / (F x F) =
19,164,321,400,000 /(206,265 x 206,265) =
450.4456148 = 450.45.
So, in summary F x F x the length of E--O = a parsec.
In your guage S--E is the base and Om is your point in space. So F x S--E = S--Om = E--Om = a parsec.
Note: From a source other than my college dictionary, the lengths S--E and S--O in my model = 1.495985 x 10^13 centimeters / (2.54 centimeters per inch x 12 inches per foot x 5280 feet per mile) = 92,956,198.3 miles. I cannot explain why there is the difference [92,956,198.3 -
92,911,164.75 = 45,033.5517 miles]. Possibly, the
actual size of the radius of the earth's orbit is less important to the definition of a parsec than is the seemingly arbitrary relationship:
parsec / 206,265 = the alleged radius of earth's orbit.