14
   

Why in the world would Einstein suggest....

 
 
FBM
 
  2  
Reply Fri 6 Mar, 2015 05:24 pm
@layman,
layman wrote:

Quote:
Then knowledge is impossible and chaos ensues.


I swear you're an unusual case, FBM. Generally speaking, people who are truly "new" to SR have a great deal of trouble accepting its (inherently conflicting) premises. You appear to be the exact opposite. It appears to me that you try to INSIST that SR is "somehow" right, even to the point of interpreting experiments in an idiosyncratic fashion, fully accepting illogical assertions such as "both are correct," and denying every day "common sense" (e.g., that it is the guy on the train or plane, rather than the guy on the ground that is (the one) relatively moving).

Maybe the ignorance and chaos you fear is caused by the acceptance (rather than the rejection) of SR as in any way representative of "reality." Ever think of that?


No, and I'm not going to think about this topic again, either. Adios, amigo.
0 Replies
 
cicerone imposter
 
  1  
Reply Fri 6 Mar, 2015 09:09 pm
@layman,
To begin with, traveling twins has no bearing on anything that's connected with time. It's their perception that counts. Even twins have different realities; that's the nature of the beast we call subjective perception - especially when people do not wear a watch or is not in site of one. Clocks (and wrist watches) can also show the wrong time.

layman
 
  -1  
Reply Fri 6 Mar, 2015 09:49 pm
@cicerone imposter,
Quote:
To begin with, traveling twins has no bearing on anything that's connected with time.


Who knew?
0 Replies
 
parados
 
  2  
Reply Sat 7 Mar, 2015 10:47 am
@layman,
Quote:
But that same theory would say that his measurement, though carefully and accurately made within that frame, could still be wrong. In fact such a theory would say that the person doing the measuring IS wrong, if he fails to take his own relative motion into account before arriving at his "final" conclusion.

His own relative motion into account? Relative to what?

Since you can't point to the one true motionless frame of reference, your argument would mean EVERY measurement in every reference frame in AST must be wrong because none can be shown to be the motionless one.
0 Replies
 
parados
 
  2  
Reply Sat 7 Mar, 2015 10:50 am
@layman,
layman wrote:

Quote:
In fact such a theory would say that the person doing the measuring IS wrong, if he fails to take his own relative motion into account before arriving at his "final" conclusion


Note that this does NOT require an absolute rest frame, just as it did not require an absolute rest frame to determine that the travelling twin was the one really moving (and hence aging more slowly) in the twin paradox. It does, however, require one to resort to a "preferred" frame (which needn't be "absolute").

So the preferred frame is the correct time?

Since you have decided that one need only RESORT to the preferred frame to tell correct time that means that everyone can select a different frame and they must all be correct. If you don't allow them to select their own frame then you must be arguing that there is an absolute frame in spite of you just claiming there needn't be one.
layman
 
  -1  
Reply Sat 7 Mar, 2015 02:25 pm
@parados,
Quote:
Since you can't point to the one true motionless frame of reference, your argument would mean EVERY measurement in every reference frame in AST must be wrong because none can be shown to be the motionless one.


You are assuming that an ABSOLUTE frame is required. I will address this more below. But, if you want to apply your own reasoning to SR, then "EVERY measurement in every reference frame in SR must be wrong because none can be shown to be the motionless one." So, at best, your argument, assuming that it proves anything, "proves too much."

But the question is not even a matter of THE (one and only, true for the whole universe) time--it's about the DIFFERENCE in time between two or more frames. The GPS works just fine and it uses an AST. It establishes a preferred frame, i.e., the ECI (earth-centered inertial frame) which is not ABSOLUTE, in the sense of being valid for the entire universe. It uses the frame of a non-rotating "master" clock located at the center of the earth as the "standard" time against which all other clocks are compared. Relative to it, moving objects are NOT in a frame where the speed of light is c. The ECI frame DOES measure the speed of light to be c, regardless of direction. Hence it is, by definition, the "preferred frame," even though non-absolute.

Quote:
So the preferred frame is the correct time?


Yes. As I said, a "preferred frame" need not be absolute. To quote wiki on the subject:

Quote:
In theoretical physics, a preferred or privileged frame is usually a special hypothetical frame of reference in which the laws of physics might appear to be identifiably different (simpler) from those in other frames.....Although there is no preferred inertial frame under Newtonian mechanics or special relativity, the set of all inertial frames as a group may still be said to be "preferred" over noninertial frames in these theories, since the laws of physics derived for inertial motion only work exactly in this special category of frames.


http://en.wikipedia.org/wiki/Preferred_frame

A "preferred frame" is also one that gives you the "right" answer, as opposed to the wrong one. So, in the twin problem the EARTH TWIN is in the preferred frame. It is HIS frame which correctly predicts who will age more. The travelling twin, calculating from HIS frame, is WRONG. He thinks the earth twin is the one aging slower, but he is wrong. He is using the wrong (the non-preferred) frame as his base.



layman
 
  -1  
Reply Sat 7 Mar, 2015 02:37 pm
@parados,
Quote:
If you don't allow them to select their own frame then you must be arguing...


Once again, you pick an argument which, even assuming it proved anything, would prove too much. SR does NOT allow any "selection" of frames either. As spelled out, at some length, above, It MANDATES that you calculate from one, and only one, frame, which frame is treated as being ABSOLUTELY motionless--i.e., the frame you are in.
parados
 
  2  
Reply Sat 7 Mar, 2015 02:56 pm
@layman,
If both frames can choose their own reference then both must be correct.
0 Replies
 
parados
 
  2  
Reply Sat 7 Mar, 2015 03:00 pm
@layman,
Quote:
You are assuming that an ABSOLUTE frame is required. I will address this more below. But, if you want to apply your own reasoning to SR, then "EVERY measurement in every reference frame in SR must be wrong because none can be shown to be the motionless one." So, at best, your argument, assuming that it proves anything, "proves too much."

That isn't my argument. It is yours. My argument is that both are correct for their own frame.

Blah, blah, blah. Then you choose a frame and insist that the frame you chose is the correct one. You could just as easily choose the other frame and insist that one is correct.
layman
 
  0  
Reply Sat 7 Mar, 2015 03:10 pm
@parados,
Quote:
Then you choose a frame and insist that the frame you chose is the correct one. You could just as easily choose the other frame and insist that one is correct.


WRONG. Not in SR you can't. SR does NOT allow you to choose the other's frame and "insist that it is correct."

To say "both are correct in their own frame" is to say absolutely NOTHING about what is actually correct. As a matter of physical fact, BOTH CANNOT POSSIBLY be correct (as the twin paradox demonstrates). Only one of the two could possibly be correct (although BOTH could be wrong).
parados
 
  2  
Reply Sat 7 Mar, 2015 03:19 pm
@layman,
You keep making the same mistake over and over and over and over and over and over.
layman
 
  0  
Reply Sat 7 Mar, 2015 03:21 pm
@parados,
Parados, you never respond to any particular posts of mine, you just come back with some vague non sequitur. I proposed an $10,000 bet to you. You have yet to tell me if we are "on" with that bet. Are we?

Do you dispute anything that I said in this post (just for one example of a post you refuse to confront)?

http://able2know.org/topic/265997-51#post-5902650


layman
 
  0  
Reply Sat 7 Mar, 2015 03:33 pm
@parados,
Quote:
You keep making the same mistake over and over


For there to be a "mistake" there would have to be a contrasting proposition which is "correct." Do you have such a proposition? If so, what is it?

Are you claiming, for example, that "SR is right, and an AST is wrong?"

Is THAT your claim? If not what is it? What is the alleged "mistake?"
parados
 
  2  
Reply Sat 7 Mar, 2015 03:37 pm
@layman,
You insist that you can only use one frame of reference. You fail to see that you are using that one frame even though that error has been pointed out to you repeatedly.
parados
 
  2  
Reply Sat 7 Mar, 2015 03:39 pm
@layman,
layman wrote:

Parados, you never respond to any particular posts of mine, you just come back with some vague non sequitur. I proposed an $10,000 bet to you. You have yet to tell me if we are "on" with that bet. Are we?

Do you dispute anything that I said in this post (just for one example of a post you refuse to confront)?

http://able2know.org/topic/265997-51#post-5902650




I will be happy to take the bet. However it will be impossible to prove either of us right. You will still insist you are right without evidence.
layman
 
  0  
Reply Sat 7 Mar, 2015 03:40 pm
@parados,
1. IF I define 2 + 2 as "equal to 4," THEN 2 + 2 = 4

2.IF I define 2 + 2 as "equal to 5," THEN 2 + 2 = 5

BOTH of those statements are, BEYOND QUESTION, correct. So what?

Neither tells me whether 2 +2 is 4 or 5.

Your tautologies do NOT address any matter of substance.
layman
 
  0  
Reply Sat 7 Mar, 2015 03:46 pm
@parados,
Quote:
. However it will be impossible to prove either of us right


You think? OK, then we're ON!

Quote:
You will still insist you are right without evidence.


The "evidence" has already been collected and confirmed by Hafele-Keating, the GPS, and other experments.

Do YOU have ANY evidence for the proposition that two clocks, moving relative to the other, WILL EACH BE SLOWER THAN THE OTHER? If I showed you where Albert Einstein himself said that was not possbile, would that be "evidence" for you, or would you just stick to your denialist pattern?
layman
 
  0  
Reply Sat 7 Mar, 2015 03:52 pm
@parados,
Let me repeat the question which you yourself just posted, but are still ducking:

Quote:
Do you dispute anything that I said in this post (just for one example of a post you refuse to confront)?

http://able2know.org/topic/265997-51#post-5902650
0 Replies
 
layman
 
  0  
Reply Sat 7 Mar, 2015 04:30 pm
@parados,
Quote:
You insist that you can only use one frame of reference. You fail to see that you are using that one frame even though that error has been pointed out to you repeatedly.


Not even sure what you mean by "only one frame of reference," but whatever you mean, you are WRONG, on both counts:

1. You insist that you can only use one frame of reference.<---I never said that. Obviously, you "can" do anything you want. I'm not saying that SR "can't" do what it does, and never have. I have, in fact, explicitly said just the opposite.

2. "You fail to see that you are using that one frame.." I don't "fail to see" anything. I just don't agree with your erroneous claims. I have noted, for example, that in the twin paradox solution, SR itself DOES indeed resort to "using one frame" as a preferred frame.

I don't "fail to see that," nor do I "fail to see" what would happen if SR DIDN'T select a preferred frame in the twin hypothetical. In that case, the theory would predict that "each clock is slower than the other" which virtually every physicist (and every other person who can comprehend simple logic) acknowledges is impossible.
parados
 
  2  
Reply Sat 7 Mar, 2015 04:44 pm
@layman,
Your evidence is based on ONE frame of reference. Geez. How many times do you have to be told that. Of course one frame of reference is different from the other frame. When you select which frame you are going to use you have already determined your outcome. We are going in circles because you are tied to one spot and can't seem to get past it.
 

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