8
   

Galactic Matyhematics.

 
 
George
 
  1  
Reply Wed 5 Nov, 2014 06:37 am
First step get a common denominator for each side (which will be the
product of the two binomials)

Second step, now that each side is a single fraction, cross multiply
the two fractions (numerator times other side denominator & vice
versa.

Last simplify the fractions.



After following my step 1 you get this equation (note "/" is a fraction bar)

(2x+7)/(x^2+7x+12) = (2x+7)/(x^2+7x+10)

After you cross multiply you get: (note there are no fractions)
2x^3+14x^2+20x+7x^2+49x +70 = 2x^3+14x^2+24x+7x^2+49x+84

After subtracting common values from both sides you get
20x+70 = 24x+84

-14 = 4x, so x=-3.5
0 Replies
 
Quehoniaomath
 
  0  
Reply Wed 5 Nov, 2014 10:23 am
still waiting...
0 Replies
 
Quehoniaomath
 
  0  
Reply Sat 10 Jan, 2015 11:01 am
Well, well, well, despite people having very big mouths here. so far none is come forward to solve the equation.

tells us something, doesn't it?

And no, coming again with a totally another equation is of course not a solution.
That will be a very very dumb reaction , and is always done by someone who feels extremely threatened by this very good, practical and elegant system.

We'll see who is so dumb to come with another equation, so we can have a laugh, again!

0 Replies
 
Quehoniaomath
 
  0  
Reply Sat 25 Jul, 2015 06:18 am
still no one can do this???


Quote:
1 / (x+3) + 1/ (x+4)=1/(x+5) + 1/(x+2)
0 Replies
 
Quehoniaomath
 
  0  
Reply Sat 25 Jul, 2015 06:34 am
Oh and btw Pi=3.14159265359 is factually wrong!
0 Replies
 
 

Related Topics

Oddities and Humor - Discussion by edgarblythe
Let's play "Caption the Photo" II - Discussion by gustavratzenhofer
JIM NABORS WAS GOY? - Question by farmerman
Funny Pictures ***Slow Loading*** - Discussion by JerryR
Caption The Cartoon - Discussion by panzade
Geek and Nerd Humor - Discussion by Robert Gentel
Caption The Cartoon Part Deux - Discussion by panzade
IS IT OK FOR ME TO CHEAT? - Question by Setanta
2008 Election: Political Humor - Discussion by Robert Gentel
 
Copyright © 2024 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.05 seconds on 04/19/2024 at 12:12:23