The worlds first riddle!

Miss mi:

52 = C in a D = 52 cards in a deck


Stormy:

54= C in a D with J = 54 cards in a deck with jokers

57 = H V = 57 Heinz Varieties

Variety being the spice of life!


Mark:

REMAINDER
13 (remainder is 4)



If one-half the sum of the length and the width of a rectangle is equal to 3 times the length of the side of an equilateral triangle, then the perimeter of the rectangle is how many times as large as the perimeter of the triangle :wink:

and I thought I missed you......I did until I saw that problem you left
That is a riddle? it looks more like a math problem. I am whining in case you haven't noticed

PERIMETERS
[size=7]4[/size]

yeah mark!!!

Mark:

PERIMETERS
4

TTH (Mark's fan club): Yeah mark!!!



(1/2)(L + W) = 3(side)
3(side) of an equilateral triangle = perimeter of an equilateral triangle since each side of an equilateral triangle has the same length.

Perimeter of a rectangle = 2(L + W). So...(1/2)(L + W) = 3(side) = Perimeter of Equilateral Triangle
4(1/2)(L + W) = 4(Perimeter of Equilateral Triangle)
2(L + W) = 4(Perimeter of Equilateral Triangle)
Perimeter of Rectangle = 4(Perimeter of Equilateral Triangle)
The perimeter of the rectangle is 4 times the perimeter of the triangle.

Yeah! It is.



There are 37 red, green, blue, and yellow marbles in a bag. There are 3 more red marbles than green marbles, 2 more red than blue, and 4 more yellow than blue. How many green marbles are there



60 = S in a M

64 = S on a C B

88 = P K

60 = S in a M = 60 seconds in a minute

64 = S on a C B ?

88 = P K ?

88 = piano keys? I don't play so that is a guess. Now I will google it and see if it is right

Come on Mismi40
We can do it......the last one. Putting on my thinking cap

I think I know. 64 = squares on a checker board? Now I will google both

Edit: to add this....the "c" can also be another word

have serious brain fog today TTH - I can hardly form a sentence

MARBLES
[size=7]There are:
10 red
7 green
8 blue
12 yellow[/size]

I think I have "brain fog" most days
The other "c" word is chess

mark = another YEAH!!!! (marbles)

Miss mi:

60 = S in a M = 60 seconds in a minute


TTH:

88 = piano keys

64 = squares on a checker board


Yes, it is the same for a chess board…But, if you take the 64 and add one for the square board and square division within the board - What is the total number of squares possible


Mark:

MARBLES
There are:
10 red
7 green
8 blue
12 yellow

There are indeed, and this is confirmed by TTH!





Consecutive numbers are whole numbers that follow in order such as 3, 4, 5. Find the smallest of the five consecutive numbers whose sum is 100



90 = D in a R A

200= D for P G in M

365= D in a Y

90 = D in a R A = 90 Degrees in a Right Angle

200= D for P G in M = 200 Dollars for Passing GO in Monopoly - amazing I got this one - we have been playing Monopoly a lot lately though

365= D in a Y = 365 days in a year

A lot, otherwise I would have to think 18, 19, 20, 21 & 22 (it adds up to 100 anyway)

Miss mi:

90 = D in a R A = 90 Degrees in a Right Angle
200= D for P G in M = 200 Dollars for Passing GO in Monopoly
365= D in a Y = 365 days in a year


TTH:18, 19, 20, 21 & 22



Your mission, should you choose to accept; is to obtain 24 using the four numbers 3, 3, 7, and 7. It is possible, using only *, +, -, and / to do this
Use each number exactly once.

If that seems impossible; try 5,5,5,1. With the same limitations



Wow, ponder this:

There are 5 platonic solids, the tetrahedron (4 vertices, 4 triangular faces, 6 edges), the cube (8 vertices, 6 square faces, 12 edges), the octahedron (6 vertices, 8 triangular faces, 12 edges), the dodecahedron (20 vertices, 12 pentagonal faces, 30 edges) and the icosahedron (12 vertices, 20 triangular faces, 30 edges).

Consider open models of these solids with wire edges connecting the vertices. Suppose each wire has unit resistance.

For each case find the total resistance between a pair of adjacent vertices

Give any answer as a rational number.

I get 3/7= .4286 + 3 = 3.4286 x 7 = 24.00
That one didn't. This one does, otherwise I don't know this one

...........and I will just ponder the other one

5, 5, 5, 1
[size=7]5 * (5 - 1/5)[/size]

Now I see it, thanks mark

RESISTANCE
[size=7]I'll take a shot at the simplest case. I get 1/2 for the tetrahedron.[/size]

RESISTANCE (2)
I did a little Googling and found this:

[size=7]tet: 1/2
cube: 7/12
oct: 5/12
dod: 19/30
ico: 11/30

The tet is its own dual. The cube and oct are duals. The dod and ico are duals.

Interestingly, if you add the resistances of duals, you get 1.[/size]