NeoPets Riddles (Lenny Conundrums) and Answers Here

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Please add new riddles as replies to this thread.

OK, here's the latest one I've seen (12/31/04):

An Acara traveled from Meridell to Brightvale, 50 miles away, with his pet Pawkeet. When he arrived in Brightvale, he let the pawkeet fly free while he traveled back to Meridell, at a speed of 10 miles per hour. The pawkeet, who flies at 25 miles per hour, arrived at Meridell and promptly turned around until he got to the Acara. Once he got to the Acara, he turned around and returned to Meridell. He continued to fly back and forth between the Acara and Meridell until the Acara reached Meridell.

How many miles total did the Pawkeet travel on this trip?

Answer: 175 miles. (50 miles to Brightvale + 5 hours @ 25 mph while Acara returns to Meridell)

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Type: Discussion • Score: 605 • Views: 2,924,574 • Replies: 15,632

I wish I could walk at 10mph for 5 hrs! It would be great!

Of course I also wish I could fly at 25mph, but that would just be silly!!

Rolling Eyes

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The writer of the Lenny Conundrums decided, as a New Year's resolution, to make the Lenny Conundrums a little more challenging, because it seemed like everyone was complaining abut how easy the puzzles were.

His second New Year's resolution was to learn a new hobby. The hobby he chose was structural engineering. So he enrolled in the Brightvale Institute of Technology and Engineering. While studying there, he observed a new building being constructed.

There was a steel beam 50 feet long. The entire Skeith construction crew (total weight: 6000 pounds) was standing at the center of the beam. Assume the modulus of elasticity is 29,000,000 pounds per square inch, the moment of inertia is 850 inches^4, the beam has simple pin connections at either end, and all loads other than the weight of the crew are disregarded.

How much will the beam deflect? Please round to the nearest tenth of an inch.

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You might be better off posting this in the science/math forum.

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For those of you who might be interested, the formula for calculating deformation is (Deformation)=(P times L)/(A times E) where "P" is the load in pounds, "A" is the cross-sectional area of the member in square inches, "L" is the length of the member in inches and "E" is the Modulus of Elasticity.

As an example, a steel bar which has an area of one square inch and is ten feet long, loaded with 10,000 pounds stretches... (10000)(120)/(1)(29000000) = 0.04138 inches. Shocked

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Tryagain wrote:

For those of you who might be interested, the formula for calculating deformation is (Deformation)=(P times L)/(A times E) where "P" is the load in pounds, "A" is the cross-sectional area of the member in square inches, "L" is the length of the member in inches and "E" is the Modulus of Elasticity.

As an example, a steel bar which has an area of one square inch and is ten feet long, loaded with 10,000 pounds stretches... (10000)(120)/(1)(29000000) = 0.04138 inches.

thanks,

i did what you said and i got 2.378092811^-13 is that right?

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What a surprise, despite having this lovely forum to post in, the Neopet questioners couldn't read and posted FIVE riddles of the same thing!!

Can we say LAZY? BLIND? STUPID?

Of course we can't say those things!

(But I can think them Twisted Evil

)

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Anyone else think that Lenny is having some fun at the expense of his readers?

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Just for those of you who don't know, this is lenny

http://images.neopets.com/games/lennywizard2.gif

lol

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If you rounded to the nearest tenth, you'd get a whopping 0.0 in. Or is this some kind of trick . . . ?

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bizarre wrote:

What a surprise, despite having this lovely forum to post in, the Neopet questioners couldn't read and posted FIVE riddles of the same thing!!

Can we say LAZY? BLIND? STUPID?

Of course we can't say those things!

(But I can think them )

Possibly if you guys quit giving them the answers, cuz it is supposed to be a contest, quite possibly they'd stop filling up the board by asking it over and over again hundreds of times.

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bizarre wrote:

What a surprise, despite having this lovely forum to post in, the Neopet questioners couldn't read and posted FIVE riddles of the same thing!!

Can we say LAZY? BLIND? STUPID?

Of course we can't say those things!

(But I can think them )

hmm.. theres no use in gettin upset over it.. Wink

im not blind but this is way over my head... need answers....

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its not a trick, and really isnt as hard as you are making it out to be...

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heres the answer, simplified.....

14.9 inches...... enjoy your prizes....
consider it a freebie... next time, figure it out yourself... the rest of us work our butts off to figure the riddles out... we dont get points for cheating...

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ok now yall have had your fun laughing at us... Rolling Eyes

ok i worked it but not as you had it....i dont have physics till next semester and my brain is on total meltdown under classes resume on the 18th could you please help me and tell me if i am even in the right direction :wink:

(5/8)*(6000*50^3)/(48*29,000,000)=2.83203125 E 14

dont ask me how i came up with that i really dont know lack of sleep can make you stupid Shocked

....anyways i am asking nicely for some help :wink:

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sorry didnt realize it had been answered... Embarrassed

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Which is the answer? I REALLY want this right.
Hi I always need help with te Lenny Conundrums and I always get my anwsers here so I joined and no I can't firgure them out yet but I will because I'm young and under 13.

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and im only 16!

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14.9 is that to the nearest tenth of an inch? dumb question probably but we dont work in inches over here and i dont intend on starting.. wouldnt the answer be 15? or is that rounding it to the nearest inch? too much for my pretty brains... heeheehee

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Tryagain wrote:

For those of you who might be interested, the formula for calculating deformation is (Deformation)=(P times L)/(A times E) where "P" is the load in pounds, "A" is the cross-sectional area of the member in square inches, "L" is the length of the member in inches and "E" is the Modulus of Elasticity.

As an example, a steel bar which has an area of one square inch and is ten feet long, loaded with 10,000 pounds stretches... (10000)(120)/(1)(29000000) = 0.04138 inches.

There was a steel beam 50 feet long. The entire Skeith construction crew (total weight: 6000 pounds) was standing at the center of the beam. Assume the modulus of elasticity is 29,000,000 pounds per square inch, the moment of inertia is 850 inches^4, the beam has simple pin connections at either end, and all loads other than the weight of the crew are disregarded.

where does the moment of inertia go into the formula??

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