The worlds first riddle!

This thread contains knowledge, knowledge is power, power corrupts, corruption is a crime, and crime doesn't pay…….So if you keep reading, you'll end up in jail!..... Kapish!

It's actually spelled capisci; but you would have to be Italian to know that.






TTH writes kindly about the magnificent seven…Bon voyage mon ami.



Miss mi touchingly writes, "I will have to add that back to my phraseology!"

OMG; you have an OLOGY! Wow, you must be smart.



Mark: (Leader of the Samurai)

SIXES

April 9
May 14
June 18
November 26

The kings were discarded on:
September 10 and 17
December 17 and 24


Could that be the date Sweet lips was looking for?

The calendar will fit the year 2006. There are 26 fortnights. Each fortnight must reduce the remaining counts by 14, hence must be represented by pairs of Ace-King, 2-Queen, 3-Jack, 4-10, 5-9, 6-8, or 7-7: there will be four of the first six, and two of the 7-7 pair (total 26).

Starting from 364, and working down to zero, the first week of each fortnight must reach a PSC (palindrome, square, or cube) and the second week of the fortnight must reach 14 lower than the previous fortnight.

There are 63 PSC numbers from 1 to 363. I generated all splits (week one, week two) from each of the declining fortnightly remainders, where week one would reduce to a PSC. This gave me 61 combinations. Of these, 10 had only one set of cards which would get to the next lower count, so these were forced.

There were only two cases where consecutive kings appeared, so these four were also forced. Those which were forced eliminated further lines, and extended the iterations.

This left four lines where the value of '6' had been forced, so these must be the four dates requested. It was not necessary to determine all of the fortnightly actions.

The solution is the Sundays of 9 April, 14 May, 18 June, and 26 November.

I bet he has an OLOGY (or two)




milalnumusacrtiepdt



ncesosianste

OMG; you have an OLOGY! Wow, you must be smart.

ass...quit making fun of me. Too busy to be smart.

Miss mi writes, "(Try, you are an) ass"

Hey sweetie, will ya quit sweet talking me.


"Too busy to be smart"

Hmmm……… I'm too smart to be busy!

Mark, Thoh and I each replaced each asterisk with a digit so that the six-digit number that could be read down, the five-digit number that could be read from left to right and the four-digit number that could be read at an angle of 45 degrees to each of the other two were fourth powers.

The four digit number could be read from bottom left to top right, or from top right to bottom left.

No two of our solutions were the same, but Mark and Thoh's solutions had two fourth powers in common.

Which three fourth powers did I use in my solution


…………….*
………..*…*
……*……..*
*….*..*..*…*
…………….*
…………….*

That should be a 4

[size=7]illuminated manuscript
incessant noise[/size]

FOURTH POWERS
[size=7]Mark and Thoh used (1296, 65536, 130321) and (6561, 65536, 130321).
Try used (2401, 20736, 130321).[/size]

Roll call:

TTH on furlough
YKW absent without leave
Thoh brokenhearted

Time to circle the wagons!


FOURTH POWERS
Mark and Thoh used (1296, 65536, 130321) and (6561, 65536, 130321).
Try used (2401, 20736, 130321).


There are two 4-digit numbers which end in 6 - 1296 and 1656 (6561 reversed).
Thus, the 5-digit number is 65536, which fits only with 130321 down.

As this uses up two numbers (65536, 130321) the third 4-digit number must be 2401 or 1042.

2401 would require the 6-digit to be 234256 or 279841. Matching 5-digit would be (in turn) 1xx2x or 1xx8x. None fits.

1042 would require the 6-digit to be 104976, 130321, 160000 or 194481 and the matching 5-digit would be (in turn) 2xx9x, 2xx3x, 2xx0x or 2xx4x. Only 20636 fits.

So, it's 2401 (reversed), 20736, 130321.

Some may say Mark is good; but not I,,,,,,,,,,,,,,He is freekin great!


milalnumusacrtiepdt = Illuminated manuscript
ncesosianste = Incessant noise

See what I mean! Can you see the answer?



Vituend


dceessmaanntd

dceessmaanntd= incessant demand

Stormy:

dceessmaanntd= incessant demand

Amazing!



There are some boxes labelled "the fifties", "the sixties", "the seventies", "the eighties", "the nineties" and "the noughties".

In each box are some loose sheets of paper, one for each year of that decade. On each sheet is a list of numerical dates of the Fridays of that year. As an example, the 2006 sheet reads: 6th 13th 20th 27th 3rd...

One of the earlier boxes is opened and all the numbers on the sheets have faded and the sheets are falling apart. On one scrap the following consecutive entry is shown:

rd nd

However, it is not possible to work out precisely which dates it refers to.

In the same box, there is another scrap showing two consecutive entries, and in this case it is possible to work out the precise dates they refer to.

What are those dates, including the year

DECADES
[size=7]Prior to the oughties, rd nd appears in 1951, 1962, 1973, 1979, 1990.
Since the date couldn't be determined, it must have been in the '70s.
nd st is the only combination that appears once in the '70s.

The consecutive entries are 2/22/74 and 3/1/74.[/size]

uninvited

Mark:

DECADES

Prior to the oughties, rd nd appears in 1951, 1962, 1973, 1979, 1990.
Since the date couldn't be determined, it must have been in the '70s.
nd st is the only combination that appears once in the '70s.

The consecutive entries are 2/22/74 and 3/1/74. / /



Since "one of the earlier boxes" contained the sheets in question, we are limited to the boxes for 1950 thru 1999 (since the example cites the 2006 sheet).

Testing for the ordinal suffixes "RD" followed by "ND" there are five pairs which meet this test: three are unique in a decade, and the other two are in the same decade.
(These are: February 23 and March 2 of 1951, 1962, 1973, 1979, and 1990.)
Since the pairs which are unique would allow the precise dates to be known, they are excluded, leaving 1973 and 1979; this narrows the next step to testing only the 1970s (since "another scrap" was from the same box).

In the 1970s the only unique pairing is for "nd" and "st", for February 22 and March 1 of 1974. Hence these are the dates requested.

To prove Mark knows more than math and logic - check this out…

Vituend = uninvited




RDAYCE


SORIIGALN

If SORIIGALN has to do with Eden, then I would rewrite it as AOLRSIIGN.

If RDAYCE has to do with 500, then I would rewrite it as DRACEY.

Maybe I'm off base with both.

Last Wednesday freewriter420 wrote, "Hey Tryagain. Has anyone answered your riddle?"

Welcome to the forum Tex, apologies for missing your post, but with 944 pages it can happen.
If you have any answers/comment jump right in they are a friendly bunch here.


Mark:

If SORIIGALN has to do with Eden, then I would rewrite it as AOLRSIIGN.

If RDAYCE has to do with 500, then I would rewrite it as DRACEY.

"Maybe I'm off base with both."

You just hit two homers! Cut me some slack buddy, not content with supplying the answers…now you are supplying better questions!!! Still, no one can get them.



A sum has been created by adding a three-digit number consisting of only odd digits to a three-digit number consisting of only even digits to make a three-digit number in which odd and even digits alternate. The nine digits used are all different.

If Mark were to be told any one of the three numbers he could, with certainty, deduce what the other two numbers were.

What are the three numbers of the sum

A SUM
[size=7]I found 15 solutions, one of which had unique numbers:

359 + 402 = 761[/size]

I hope ya'll have a pleasant, relaxed day; don't mind about me as I struggle with imponderables, such as:

If it's true that we are here to help others; then what exactly are the others here for?



Mark:

Wvdioswtas = Windows Vista


RAOCLTE = act in role

Yes, it was knocked out by 317 + 608 = 925.


Half of zero is zero.

Stormy:

Wvdioswtas = Windows Vista

RAOCLTE = act in role

Stormy; you rock!




Mark and Try each replaced each asterisk with a digit in such a way that the three numbers that could be read across and the two numbers that could be read down were five different perfect squares each of which consisted of three different digits (with no leading zero). Try did not use any of the 3-digit squares that Mark used.

Which three 3-digit squares (of three different digits with no leading zero) did neither of them use

* * *
- - *
* * *
*
* * *

(In the diagram above, please ignore the hyphens. They are just there to align the asterisk correctly)

SQUARES
[size=7]324, 729, 784[/size]

HAOGPAE = hope again


BALUDRZZ = Buzz Aldrin