P = N / D
IF
N = 10^99 genome edits (e.g., mutations).
D = D1 x D2 x D3 sequences.
PHASE 1 = EVOLUTION OF FIRST GENOME FROM SCRATCH.
PHASE 2 = EVOLUTION OF FIRST GENOME TO GENOME OF FIRST COMMON ANCESTOR OF MICE AND HUMANS.
PHASE 3 = EVOLUTION OF GENOME OF FIRST COMMON ANCESTOR OF MICE AND HUMANS TO GENOME OF FIRST HUMAN.
ASSUME THAT D1 =D2 =D3.
D3 =(((4^3)^9000)^300) = 10^4,876,685.9.
THEN
D = 10^(3 x 4,876,685.9) = 10^14,630,057.
THEN
P = N/D = 10^99/(10^14,630,057) = 10^(-14,629,158).
OR P = 10^(-14.629158 x 10^1,000,000) = 1 / (425.753 x 10^(12) x 10^1,000,000) = MORE THAN (1 / 425.753) x a TRILLIONTH x a MOOGOLTH.
THEN
P = less than 0.0023 trillionth moogolth.
Note: a trillionth = 10^(-12) and a moogolth = 10^(-1,000,000).
kinda small probability to hang your hat on.
thought you'd like to know.