BoGoWo wrote: what possible basis is there 2 infer direction, and moreover, absolutely none 4 'INTELLIGENT' direction; this planet disclaims such thoughts!
(we've been here before)
fact please.
REVIEW
The genome, that thing originally in our personal, individually conceived egg that current data implies specifies all our individual protein configurations, is composed of chromosomes; chromosomes are composed of genes, genes are composed of codons; codons are composed of bases. There are 4 different kinds of bases. Each codon is comprised of 3 bases that specify one of 20 amino acids or one of 44 something elses for a total of 64 different things. te data implies that it is the sequence of this stuff that encodes the sequences of amino acids that in turn specify our protein proteins and our protein configurations then and now.
Current data implies that the difference between the human genome and the mouse genome consists of 300 genes with each composed of an average of 9000 codons containing 3 bases each. I GUESS (insufficient data is currently available to support this guess) that the genome for the common ancestor of mice and humans differs from the human genome by at least 300 genes.
Suppose we had on 1 table in one room 10 different dice labeled, respectively, 0,1,2,3,4,5,6,7,8,and 9 arranged in that sequence. How many different sequences of dice numbers can be obtained from the ten dice so arranged? Each die has 6 possible face values so the total possible number of sequences is 6^10 = 60,466,176. What is the probability P of obtaining a given sequence, say all 6s, in a single roll of each of the ten dice in turn? P = 1/60,466,176. What is P, if we do this 3,155,760 times (one per second, 3600 x 24 x 365.25) in one year? P = 3,155,760/60,466,176 = 0.0521905.
If we roll the whole set of 10 dice at the rate of one per second. The total time required is exactly 1 year: 3,155760 rolls x 1 second per roll divided by 3,155,760 seconds per year = 1 year.
Now, suppose we have 1 trillion such tables in one room with 300 x 9000 = 2,700,000 different dice labeled in sequence, but each die has only four sides (64 sides is a bit much). Now what is the probability of rolling all 4s in 10 billion years, if each roll takes only a Planck Time = 1.3509 x 10^(-43) seconds?
The total number of possible different sequences is 4^(2,700,000) = 10^(1,625,562).
The total number of dice rolls is (10^12) x (10^10) x (3,155,760) / (1.3509 x 10^[-43]) = 2,336,043 x 10^(65) = 2.34 x 10^(71).
Therefore, the probability of getting in one room, containing 1 trillion tables, all 4s in 10 billion years is, P = 2.34 x 10(^71) / (10^[1,625,562]) = 2.34 x 10^(-1,625,491).
What if the number of rooms was increased from 1 to 10? Then P = 2.34 x 10^(-1,625,490).
But what if we increased the number of rooms instead from 1 to 10 trillion? Then P = 2.34 x 10^(-1,625,478).
Let's increase the number of rooms instead from 1 to 10 googol. Then P = 2.34 x 10^(-1,625,390).
One more try
Let's increase the number of rooms from 1 to 10 "troogol" (i.e., 10 x 10^1,000,000). Then P = 2.34 x 10^(-625,490).
And so on