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## What is the probability that sum of outcomes on pair of dice is equal to 8?

So there are 5 pairs of occurence of dice showing up faces when the serial number on the faces adds up 8, as against 36 possible pairs of numbers showing up. So the probability of the event of showing the sum of the numbers on the face equal to 8 is **5/36**.

## What is the probability that the sum is 8 when throwing a dice given that the first die shows a 3?

The total number of ways to roll an 8 with 3 dice is therefore 21, and the probability of rolling an 8 is **21/216**, which is less than 5/36. heads out of 20 is (20 10 ) /220 ≈ 17.6%.

## What is a probability of rolling an 8?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

7 | 6 | 16.67% |

8 | 5 | 13.89% |

9 | 4 | 11.11% |

10 | 3 | 8.33% |

## What is the probability of throwing a total of 8 or 11 in a single throw with two dice?

Hence, The required probability is **5/36** .

## What is the probability of getting a sum of 7 from two throws of dice?

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is **6/36 = 1/6**.

## What is the probability of getting a doublet when two dice are thrown?

Probability of getting a doublet = 6/36 = **1/6**.

## What is the probability of rolling a 1 or 2?

Since there are six possible outcomes, the probability of obtaining any side of the die is 1/6. The probability of rolling a 1 is 1/6, the probability of rolling a **2 is 1/6**, and so on.

## How do you find the probability of at least one?

To find the probability of at least one of something, calculate **the probability of none and then subtract that result from 1**. That is, P(at least one) = 1 – P(none).

## What is the probability of getting at least one 6?

a) Consider the complement problem, there is a 5/6 probability of not rolling a six for any given die, and since the four dice are independent, the probability of not rolling a six is (5/6)4 = 54/64 = 625/1296. The probability of rolling at least one six is therefore **1 − 625/1296 = 671/1296 ≈** .