The worlds first riddle!

oooooooooooooh toughie baduffie....

ohhhhhhhhhhhhhh Mark.... we need the skil we saw last week.... Are you better mate - or have you got "man flu"

will make you a "Lem Sip.... maybe even a hot toddy".... need to figure out ^^^^^^ and keep your neighbour on his toots!

Now I'm afraid to answer...

<meekly> How about 4 and 13?

(I think you may be right ..... but I have no understanding how it figures out.... even with the explanation..... not a clue.... not even a detailed explanation makes any sense....I'll stick to being "hot toddy" maker and general chatterbox)

Once every decade or so I come on and say, “I am sorry I made a mistake.” However, this is not one of those decades, although it may be called an oversight or even careless; no, I think careless is going overboard…

I am sorry for the delay in confirming the answer; I saw Lizzie had posted some days ago and thought there had been no response since then. Had I known that you two had been going at it like Possums in springtime I could have expedited matters " My bad!


Mark:

NUMBERS
How about 4 and 13

First, create a list of all your possible pairs and write them out with their sums and products as well. I believe there are (97*97 + 97)/2 = 4753 such pairs, right? (I am ignoring the "sum < 100" hint.)

2,2,4,4
2,3,5,6
2,4,6,8
2,5,7,10
2,6,8,12
...
3,3,6,9
3,4,7,12
...
4,4,8,16
4,5,9,20
...
etc.


Step 1) We know it is not a pair of primes, or Mr. P would know them immediately from the product.
So eliminate all those from the possibilities, but keep them in a new list of "Prime Pairs" for future reference.

Step 2) We know it is not a pair whose sum could also come from a pair of primes, or S would not be sure that P doesn't know. So check the list of Prime Pairs and get a listing of all the sums. Now eliminate any pairs in the Possibilities that have a sum in that list. So here for example, you lose 3,4 because it has the same sum as the prime pair 2,5.

Step 3) Now, we know that with this information and knowing the product, Mr. P knows the answer, so therefore the product must only have one pair of possible multiplicants whereby their sum cannot be expressed as the sum of a pair of primes. So find the list of products that were eliminated in Step 2. Now find all the remaining Possibilities that share one of those same products and only have one pair left that makes that product. These are the only products Mr. P could have.

Step 4) If there is more than one possibility left, your last step is to go through all the Possibilities eliminated in Step 3, and check their sums. Now find all the remaining Possibilities that share one of those same sums and only have one pair left that makes that sum. These are the only sums Mrs. S could have.

Hopefully at this point you are left with only 1 possible pair, and that is your solution. (4,13)



iwnhg
thpls
tomap

ditto what that^^^^^^^ said Thanks for trying... can't get my head around it tho. My bad a? Hey ho.



mmmmmmmmmmmmm

careless spelling....tsk tsk tsk!!!!!! One of those decades a?



HA HA HA HA HA HA HA HA HA HA!



iwnhg = whining...... never

thpls = plinths..... need cleaning

tomap mmmmmmmmmmmm .......???? maintop pintoma .. looks like a pantomime or a panto of mine .... paint om.... ma point ... what is ma point... there is no point.... into map.... sheesh, draw me a map - I can't see it at all... who knew... not me! NEXT...

mis.... Stormy.... anyone?



<oh gosh... have I gone mad!>

I will be anyone
I vote for maintop (it is a nautical term)

[it may be called an oversight or even careless; no, I think careless is going overboard…]

‘I saw Lizzie had posted some days ago’

Was it a pun, or a typographical malfunction?


Lzzie:

iwnhg = whining

thpls = plinths

tomap = maintop

Way to go gal!



Someone: AKA = TTH (some say; Island Girl)
I vote for maintop (it is a nautical term)

Well, shiver my timbers!



ejors
tefar
cpres

joiners
fainter
princes
......just guessing

Try wrote; "do feel free to post a pic!"

I will post a clothed pic of me , if you will also ,,,you first,,,(chews nail and wonder's if Try will let down his guard for a second to post a pic). There is one draw-back, we might fall in love with you even more, but don't let that stop you,,,o.k?

"can I watch with you?" yes, i'm a sucker for you!

It's been kinda quiet here...what's everyone been up to?

This is what I did today:

fpesutmipvkal

Pumpkin Festival?

Dutchy:
Pumpkin Festival?

...and got rained on

TTH:

ejors = joiners
tefar = fainter
cpres = princes


Congrats TTH you have all bases loaded, now for the home run…

kbled
acgoe
dishg



Ok Jove, I will play trick or treat with you; I have got the picture as far as ‘Flicker’ and if I can figure out how to get it here…It will be done! However, it is only polite to let ladies go first.

Btw: Are you looking for a little succor too?


Stormy; how very nice to see you back, I was getting somewhat anxious for your wellbeing.

Given who I have on my caseload this year ...I worry about my well being too

blinked
coinage
shindig
It's too early in the morning for me. Maybe I shouldn't stay out so late (yawn)
Hi Stormwatch

TTH:

kbled = blinked
acgoe = coinage
dishg = shindig


Wow, TTH; you are the man " in a female kinda way.

Each square of a four by four checkerboard is to be labeled with a zero or a one in such a way that the sum of the entries in the neighborhood of each square is always odd -- the neighborhood being the squares immediately adjacent (up, down, right, left, and diagonally) together with the square itself.

Come up with as many ways of doing this as possible, or show that it can never be done

1010
0101
0101
1011

For example, the checkerboard above fails to satisfy the condition since the square in the top left corner has a neighborhood sum of 2.

1001
0000
0000
1001

is the only solution

Try wrote; " ladies go first."

O.k. i will post a pic, but it will take a day or two,,, and then you,,, so i can ~dream.

Btw: Are you looking for a little succor too?

Maybe.

Jove hun, dump that try guy and come Dance With The Devil…