The worlds first riddle!

Plates

[size=7]to figure out which days have the light plates weight the following number of plates from each day:
day 1 - 1 plate
day 2 - 2 plates
day 3 - 4 plates
day 4 - 8 plates
day 5 - 16 plates
day 6 - 32 plates
day 7 - 64 plates
if everything is fine, all the plates should weigh 127...but if there's a deficit, you can figure out from which day(s)...for example, if the plates weigh 125, there's a deficit of 2 units (or 20 plates if each is 0.9 vs 1)...so the only possibility for 20 plates is day 5 + day 3.[/size]

Thoh:

Plates

to figure out which days have the light plates weight the following number of plates from each day:
day 1 - 1 plate
day 2 - 2 plates
day 3 - 4 plates
day 4 - 8 plates
day 5 - 16 plates
day 6 - 32 plates
day 7 - 64 plates
if everything is fine, all the plates should weigh 127...but if there's a deficit, you can figure out from which day(s)...for example, if the plates weigh 125, there's a deficit of 2 units (or 20 plates if each is 0.9 vs 1)...so the only possibility for 20 plates is day 5 + day 3.


I just love it when people post better answers than I can come up with it!

In other words 2(^x-1) for day x.

Wait! Did I say love?


Rap, for some reason I can't enlarge your text. If you have similar or better, do post it full size.




tcomeporeusndt

suauratncoe

auto insurance

My answer is not as good as thoh's but there is something about a binary determination of multiple days.
come up with a binary assignment for each day
mon=1
tues=2
wed=4
thur=8
fri=16
sat=32
sun=32

If you add up the plates and come up with a deficit say 20, write 20 in binary 10100 the friday and wednesday were light. If the deficit is 13, digitally this is 1101 so thursday, wednesday and monday were light. Any deficit, expressed in binary will indicate what days were light.

BTW if the deficit is 2, in binary this is 10, and tuesday was light.

Rap

should be sun=64

Rap

TTH:

suauratncoe = auto insurance


Rap, I think that will do nicely!




Two brothers share a flock of x sheep. They take the sheep to the market and sell each sheep for $x. At the end of the day they put the money from the sales on the table to divide it equally.

All money is in $10 bills, except for less than ten excess $1 bills. One at a time they take out $10 bills. The brother who draws first also draws last. The second brother complains about getting one less $10 bill so the first brother offers him all the $1 bills.

The second brother still received a total less than the first brother so he asks the first brother to write him a check to balance the things out.

How much was the check

[size=7]Label one brother A, the other B
The two brothers get $X^2 for the flock of sheep
Brother A gets $(N+1)*10, Brother B gets $N*10+M where M<10
The total $x^2=$(2N+1)*10+M
Now 2N+1 is odd so N=0,1,2,3,4,....
M<10
Look for perfect squares that meet this criterea
& you get 16,36, 196, 256, 576, .... all end in 6 so M=6
So brother A gets $4 more than brother B, and A owes B $2[/size]

Rap

SHEEP
[size=7]The total amount of money is:
10*(y+1) + 10y + z = 20y + 10 + z = x^2

All squares are equal to 0 or 1 mod 4.
20y + 8 is a multiple of 4
Therefore, 2 + z equals 0 or 1 mod 4
Therefore, z equals 2, 3, 6, or 7.
All squares end in 0, 1, 4, 5, 6, or 9.
Since 6 is the only number in both lists, z = 6.
Therefore, the first brother has 4 more dollars than the second.
The check is for $2.[/size]

Since no one did this one, compound interest

Rap:

Sheep

Label one brother A, the other B
The two brothers get $X^2 for the flock of sheep
Brother A gets $(N+1)*10, Brother B gets $N*10+M where M<10
The total $x^2=$(2N+1)*10+M
Now 2N+1 is odd so N=0,1,2,3,4,....
M<10
Look for perfect squares that meet this criterea
& you get 16,36, 196, 256, 576, .... all end in 6 so M=6
So brother A gets $4 more than brother B, and A owes B $2


Mark:

SHEEP
The total amount of money is:
10*(y+1) + 10y + z = 20y + 10 + z = x^2

All squares are equal to 0 or 1 mod 4.
20y + 8 is a multiple of 4
Therefore, 2 + z equals 0 or 1 mod 4
Therefore, z equals 2, 3, 6, or 7.
All squares end in 0, 1, 4, 5, 6, or 9.
Since 6 is the only number in both lists, z = 6.
Therefore, the first brother has 4 more dollars than the second.
The check is for $2.



You guys are the best! You produce answers on the minimum of detail.



We all say the same thing in slightly different ways, amazingly we all have the same result.

Let the total number of sheep be 10x+y, where y<10. The total money raised is (10x+y)^2 = 100x^2 + 20xy + y^2. Regardless of the values of x and y 100x^2 + 20xy will be divisible by 20.

Because the number of $10 bills is odd y^2 mod 20 must be greater than 10 and less than 20. The only values of y where this is true is 4 and 6, where y^2 is either 16 or 36.

Either way there will be 6 $1 bills left over. Before the check the first brother will have $4 more than the second brother.



ICLC


taacqnucae

Good morning TTH, 24 hours go by and yet we post in the same minute!

tcomeporeusndt = compound interest

Have a nice day!

While I was checking something, I came across this guy:

- Mark Riddle, Yale University, New Haven, CT.

acquaintance

Try

markr's solution is more of a proof, mine is a conjecture. In the great mathematical scheme of things markr's is far more elegant.

Rap

CLINIC

Rap wrote, "In the great mathematical scheme of things Markr's is far more elegant."Lzzie:

ICLC = CLINIC

You are on fire!

When I was checking something, I found:

Saint Francis of Assisi; perhaps the most beloved Catholic saint of all.

What is the chance of that?

When I was looking for Francis Riddle, I found this:

Francis Riddle, male, age 53, b. Bohemia, occupation: miller

there are over 10000 saints, so less than 1/10000

Lzzie:

taacqnucae = Acquaintance


Thoh:

"there are over 10000 saints, so less than 1/10000"

Although the question was hypothetical; I do believe you are correct!


When I was looking for Tryagain Riddle, I found this:
Results 1 - 10 of about 146,000 for Tryagain +riddle




You need to warm milk in a baby bottle from its initial temperature of 15 degrees centigrade to 25 degrees. (Don't ask)

You put the bottle in a pot of boiling water which stays at constant temperature of 100 degrees. The thickness and conductivity of the bottle are such that the initial rate of heat transfer is 85 degrees per minute.

However heat transfer is proportional to the difference between the temperature of the milk and the water.

How many minutes will it take to heat the bottle to 25 degrees