Stormy:
ATCOMBION= combination
CASE
^
^
^
v
v
v
case = upper case/ lower casen
PEAK
II = pecan pie
TTH:
"I don't agree"
"I don't like pecan pie"
Negative; always you are making with the negative waves. Llama
Ommmmmmmm.....
Thoh:
8 13 24 25 34 34 81 101
1. 101 - 8 = 93
2. abundant numbers are 12 18 20 24 30... so 24 is between 21 and 25
3. 8 = 2^3 and < 10
4. sum of #s is 320 and 320/8 = 40
5. 1st 2 perfect numbers are 6 and 28. 6+28=34. 34 is most frequent
6. median is (25+34)/2=59/2=29.5
7. 101 is smallest 3 digit palindrome
8. sqrt(81)=9=8+1
Too clever by far!
upper case
lower case
But not fast enough to beat Stormy!
Clue 7. The largest number is the smallest 3 digit palindrome: 101
Clue 1. The range, maximum - minimum, is 101 - 8 =93, so the smallest number must be 8.
Clue 3. A cube less than 10: that would have to be 8=2^3 or 1=1^3. This clue is not really needed because of Clue 1.
Clue 4. The arithmetic mean of 8 numbers is 40, so the sum of the numbers is 8*40=320.
Clue 2. The first few abundant numbers (numbers such that the sum of the divisors less than the number is greater than the number) are 12, 18, 20, 24, 30, ... hence the abundant number between 21 and 25 would have to be 24.
Clue 5. The mode of the list is the sum of the first two perfect numbers, numbers such that the sum of the proper divisors equal the ,number. The first two are 6 and 28, hence the mode is 34. Since a mode would not be defined unless at least two numbers in the list are the same, we assume two number 34s.
Clue 6. The median is 29.5=mean of two successive entries, one of which is the maximum of the lower four numbers and one of which is the minimum of the upper four numbers, e.g., 29 and 30, or 28 and 31, or 27 and 32, or 26 and 33, or 25 and 34. Aha! We've got it: 25 and 34.
Clue 8. Looking at a table of squares, the only one under 121 such that the sum of its digits is the root is 81. . . "Summing up"; from least to greatest we have:
8, x, 24, 25, 34, 34, 81, 101. x is a slack variable, chosen so that the sum of the numbers is 320, that is x=13. There they are!
In Thoh's Calculus class, all the students gave each of the other students a gift. The women received a total of 798 gifts and the men got 684.
How many students were in Thoh's class, how many women and how many men
You may assume there were no transsexuals or gender benders in the group.
SPR ING
MATHTHE