34
   

The worlds first riddle!

 
 
TTH
 
  1  
Reply Sun 11 Mar, 2007 12:49 pm
thoh13 wrote:
and heres a riddle:

connect the following 9 dots by 4 lines (you cant lift ur hand off the paper, lines cant go back over each other but they can cross)

* * *
* * *
* * *


If the 9 dots are represented by:
123
456
789

then:
Line 1= 159
Line 2= 963#
Line 3= #24#
Line 4= #789

#= going outside the box. I hope that makes sense even though (thoh) lmao2, someone had to help me in how to write it. :wink:
0 Replies
 
thoh13
 
  1  
Reply Sun 11 Mar, 2007 01:08 pm
tryingtohelp wrote:
thoh13 wrote:
and heres a riddle:

connect the following 9 dots by 4 lines (you cant lift ur hand off the paper, lines cant go back over each other but they can cross)

* * *
* * *
* * *


If the 9 dots are represented by:
123
456
789

then:
Line 1= 159
Line 2= 963#
Line 3= #24#
Line 4= #789

#= going outside the box. I hope that makes sense even though (thoh) lmao2, someone had to help me in how to write it. :wink:


yup TTH, that's correct
you have to think outside the box for that one
0 Replies
 
Tryagain
 
  1  
Reply Mon 12 Mar, 2007 11:59 am
0 Replies
 
markr
 
  1  
Reply Mon 12 Mar, 2007 02:01 pm
[size=8]TRACK MEET
Well, I had typed up the whole explanation (factors of 40, etc.), then hit a wrong key and lost it all. Since I don't feel like retyping it, I'll just give the final results:

Event Riddles Trivia History
----------------------------------
SP . . . 2nd/2 . 1st/5 . 3rd/1
HJ . .. . 1st/5 . 3rd/1 . 2nd/2
#3 . . . 1st/5 . 3rd/1 . 2nd/2
#4 . . . 1st/5 . 3rd/1 . 2nd/2
#5 . . . 1st/5 . 3rd/1 . 2nd/2
----------------------------------
. . . . . . . . 22 . . . . 9 . . . . . 9
[/size]
0 Replies
 
Tryagain
 
  1  
Reply Tue 13 Mar, 2007 03:11 pm
0 Replies
 
raprap
 
  1  
Reply Tue 13 Mar, 2007 05:16 pm
[size=7]a+b+c=100
5a+b+1/4c=100
so
20a+4b+c=400
subtracting
4a+4b+4c=400
you get
16a-3c=0
since 16 and 5 are relatively prime
a=3 and c=16
and
b=100-3-16=81
So there are 3 dogs, 81 cats and 16 mice
Check
3*5+1*81+16/4=15+81+4=100.[/size]


Rap
0 Replies
 
Stormwatch
 
  1  
Reply Tue 13 Mar, 2007 07:37 pm
Pet Shop

3 dogs.............$45
41 cats............$41
56 mice...........$14
_________________
100 animals...$100
0 Replies
 
thoh13
 
  1  
Reply Wed 14 Mar, 2007 12:09 am
Speaking of cats...

there's a bunch of cats...
each cat sees three cats...
each cat sits on a cat's tail...
What's the least amount of cats possible?
0 Replies
 
markr
 
  1  
Reply Wed 14 Mar, 2007 02:09 pm
CATS
4
0 Replies
 
raprap
 
  1  
Reply Wed 14 Mar, 2007 03:21 pm
CATZ

Two and a mirror.

Rap
0 Replies
 
Tryagain
 
  1  
Reply Wed 14 Mar, 2007 03:44 pm
CATS:

If a cat can see its self; then 3.




Rap^:

a+b+c=100
5a+b+1/4c=100
so
20a+4b+c=400
subtracting
4a+4b+4c=400
you get
16a-3c=0
since 16 and 5 are relatively prime
a=3 and c=16
and
b=100-3-16=81
So there are 3 dogs, 81 cats and 16 mice
Check
3*5+1*81+16/4=15+81+4=100.

What!
3Dogs=$45
81 Cats=$81
16 Mice=$4
Total = $130 Shocked

You dun only got $100! :wink:


Stormy:

Pet Shop

3 dogs.............$45
41 cats............$41
56 mice...........$14
_________________
100 animals...$100 Cool Cool


Which all goes to show; There is only one way to skin a cat! Laughing





Let D stand for the number of dogs, C for the number of cats, and M stand for the number of mice.

Then you can write two equations:
D + C + M = 100 and
15 D + 1 C + 0.25 M = 100.00.

It wasn't going to be five dogs because five dogs would eat up $75 and then you'd only have $25 with which to buy another 95 animals, and it wasn't going to work.

And you know it wasn't zero dogs because that was one of the conditions of the problem.

So, use trial and error with dogs = 4, then 3, 2, and 1 to see which works. The answer turns out to be 3 dogs, 41 cats and 56 mice.




The following Javascript solves the problem:


for (Dogs=1; Dogs<=6; Dogs++) {
for (Cats=1; Cats<=99; Cats++) {
for (Mice=1; Mice<=399; Mice++) {
Cost=1500*Dogs+100*Cats+25*Mice;
if ((Dogs*1+Cats*1+Mice*1 == 100) && (Cost == 10000))
{alert(Dogs+' '+Cats+' '+Mice);
}}}}





A certain A2K member has 5 daughters: Emily, Jane, Betsy, Abigail, and Nancy.

Their fortunes are as follows:

The first two and the last two have $19,000;
The first four, $19,200;
The last four, $20,000;
The first and the last three, $20,500;
The first three and the last, $21,300.

They all live in CA so they are pretty rich. Razz


What is the fortune of each Question
0 Replies
 
shari6905
 
  1  
Reply Wed 14 Mar, 2007 04:52 pm
Now Try...you know that math is not my strong suit. Where are my wacky word games my dear?
0 Replies
 
raprap
 
  1  
Reply Wed 14 Mar, 2007 05:28 pm
Oops $15 per dog, not $5!

Then its
a+b+c=100
&
15a+b+1/4c=100
so
56a-3c=0
& 56 & 3 are relatively prime
so c=56 & d=3 & a=41
or
56 mice
3 dogs
& 41 cats
$45+$41+$14=$100

BTW my answer was the only one for $5 dogs.

Rap
0 Replies
 
lmur
 
  1  
Reply Wed 14 Mar, 2007 05:57 pm
Tryagain wrote:

.
.
.
A certain A2K member has 5 daughters: Emily, Jane, Betsy, Abigail and Nancy.

Their fortunes are as follows:

The first two and the last two have $19,000;
The first four, $19,200;
The last four, $20,000;
The first and the last three, $20,500;
The first three and the last, $21,300.

They all live in CA so they are pretty rich. Razz


What is the fortune of each Question


Emily, 5,000
Jane, 4,500
Betsy, 6,000
Abigail 3,700
Nancy 5,800

What's the penalty for quigamy in CA? Razz
0 Replies
 
raprap
 
  1  
Reply Wed 14 Mar, 2007 06:59 pm
[size=7]Set it up as a matrix and you can reduce to a=5, b=4.5, c=6, d=3.7 & e=5.8

All I kin K in a way

Emily=$5K
Jane=$4.5K
Betsy=$6K
Abigail=$3.7K
Nancy=$5.8K
[/size]

Rap
0 Replies
 
markr
 
  1  
Reply Wed 14 Mar, 2007 07:04 pm
lmur wrote:
What's the penalty for quigamy in CA? Razz


$25,000, but they all look like Try; so it wouldn't be worth it no matter what their fortunes amounted to!
0 Replies
 
thoh13
 
  1  
Reply Wed 14 Mar, 2007 11:01 pm
markr wrote:
CATS
4


of course
just arrange the cats in four corners of a room and have each cat sit on its own tail
0 Replies
 
Tryagain
 
  1  
Reply Thu 15 Mar, 2007 11:18 am
Sweet Shari, how very nice to see your back, and your front too!
May I wish you everything you would wish for yourself, for your upcoming birthday. Razz

I will be working that day, so I am very sorry to say I will not be able to attend your party.

Have a great time! Drunk



Rap, "BTW my answer was the only one for $5 dogs."


Nice move; writing your own questions to fit the answer! Laughing



Rap2:

Set it up as a matrix and you can reduce to a=5, b=4.5, c=6, d=3.7 & e=5.8

All I kin K in a way

Emily=$5K Cool
Jane=$4.5K Cool
Betsy=$6K Cool
Abigail=$3.7K Cool
Nancy=$5.8K Cool





Imur:

Emily, 5,000 Cool
Jane, 4,500 Cool
Betsy, 6,000 Cool
Abigail 3,700 Cool
Nancy 5,800 Cool


Good to see you dude, where have you been? It's the Irish elections, is that what kept you?


To solve this problem, set up five equations with five variables and solve simultaneously.
The five equations are:


E + J + A + N = 19,000
E + J + B + A = 19,200
J + B + A + N = 20,000
E + B + A + N = 20,500
E + J + B + N = 21,300



"What's the penalty for quigamy in CA?"

I don't know, but it sure would be fun to find out! Razz Shocked Embarrassed



Mark, "$25,000, but they all look like Try; so it wouldn't be worth it no matter what their fortunes amounted to!" Twisted Evil


Oh! So they are all blondanddelicious are they? Laughing Laughing Laughing




Thoh: CATS - "Â…each cat sit on its own tail"


Very clever, I would never have thought of that. Very Happy





Anyhoo, the five chicks mentioned above were supposed to fill in the missing numbers, they have all gone round to Mark's pool. In their absence can anybody assist Question

Determine the missing entries A, B, C, D, and E so the sum of each row, column, and diagonal is the same.


Code:

A B 10.5
6.75 C D
8 E 5.5

0 Replies
 
raprap
 
  1  
Reply Thu 15 Mar, 2007 03:05 pm
The matrix is
13 4.25 10.5
6.75 9.25 11.75
8 14.25 5.5
all sum to 27.75

Rap
0 Replies
 
Tryagain
 
  1  
Reply Fri 16 Mar, 2007 08:32 am
Rap:

The matrix is
13 4.25 10.5 Cool
6.75 9.25 11.75 Cool
8 14.25 5.5 Cool

All sum to 27.75


Yo bro, way tago. Razz



Since the 3 numbers in each row must be the same, equate the middle row and the last column to find C:
6.75 + C + D = 10.5 + D + 5.5

Therefore C = 16 - 6.75 = 9.25
Then the sum must be 8 + 9.25 + 10.5 = 27.75.

A = 13
B = 4.25
E = 14.25 and
D = 11.75






In the snack bar at A2kay towers there five different products: Italian Ices, Cream Ices, Gelati, Misto, and Frozen Custard.

A visitor states that there are so many different choices that they have a difficult time making up their minds.

(Ya, I know the standard of visitor is not up to much, but this is the Wall Street HQ.)

Can you determine how many different choices there are using the information below Question

There are 26 flavors of Italian Ice.
There are 5 flavors of Cream Ice.
Gelati is made by layering either vanilla or chocolate Frozen Custard with the customer's favorite flavor of Italian Ice or Cream Ice.
Misto Shakes are made by blending either vanilla or chocolate frozen custard with the customer's choice of Italian Ice or Cream Ice.
There are two flavors of Frozen Custard.





Due to the festival of Lesbos, I am of to the Virgin Isles to help out. I leave you with a little something for the W/E




Out west, there are long stretches where Interstate 80 runs parallel to the Union Pacific railroad track. Last summer, I set my car on cruise control at 64 m.p.h. It took me 34 seconds to pass a 900 foot long train.

(i.e., it took 34 seconds from the time my car caught up to the end of the train until it pulled even with the front of the train).

If both the train and car moved at constant rates of speed, how fast was the train going Question

How far did the car travel before it overtook the train Question
0 Replies
 
 

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