Mark:
MT
Dreamt
KAYAK
racecar and kayak are palindromes
(Yeah! Not only that; they read the same backwards)
DETROIT
There will be exactly one spot. If two people made the trips on the same day, they would pass each other once.
Tryingtohelp aka: TTH
Well, coming from one who races a car the answer is yes. Even if you have one driver, one car traveling from Detroit to Chicago leaving at 8 am. Then the next day the same driver leaves Chicago at 8 drives the same highway back to Detroit. That driver can have many spots along the route that he passes at exactly the same time each day.
(Even I can see where you are coming from)
To see it as clearly as TTH, imagine two women driving the route on the same day, one leaving Detroit at 8 and the other leaving Chicago at 8. They have to pass each other at some point, and they'll be there at the same time.
Thoh:
(2x)=[1+3f(x)]/[3+f(x)]
f(x) = (x-1)/(x+1)
solve for x
x=[1+f(x)]/[1-f(x)]
f(2x) = (2x-1)/(2x+1)
plug in expression for x and simplify
f(2x) = [1+3f(x)]/[3+f(x)]
WOW! That is hot.
Mark, "Nice job"
To put that into context:- When Einstein came up with: Mc2. Mark was heard to remark: "Whatever"
My new (Made in China) desk calendar consists of two cubes and cards with the names of the months (such as: Jin/Fob/Mer) on them. The day was indicated by arranging the two cubes so that their front faces gave the date.
The face of each cube bore a single digit, 0 through 9, and one could arrange the cubes so that their front faces indicated any date from 01, 02, 03, .... to 31.
The cheap paint has come off, leaving one cube with a 1 and a 2 on it, and the other cube has a 3, 4, and a 5 on it.
Can you assist in determine the missing four numbers on the first cube and the missing three digits on the second cube
Thank you, or as they say in China, ?'What you had for breakfast?'
When is this sentence true: There are eleven letters in the alphabet.