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The worlds first riddle!

 
 
thoh13
 
  1  
Reply Fri 29 Dec, 2006 07:10 pm
markr was right on the money:

thoh13's quiz:
1. D - It is the same as to the right of 0, but the signs alternate (..., 5, -3, 2, -1, 1, 0, 1, 1, 2, 3, 5, ...)
2. A - Let x = the expression. Then x^2 = a*x; so x = a.
3. B - (2007 + 20007) * (20007 - 2007 + 1) / 2 = 198,137,007


and i thought c) Private homes in America. was a joke answer HA...iwonder how many tigers belong to sigfried and roy



1. Calendar vendor e. $3.65 (365 days/yr)
2. Casino worker f. $7.11 (7-11-21)
3. Deer hunter n. $99.44 (99/44 deerfield)
4. Electrician c. $1.20 (120V american voltage)
5. Golf instructor a. $.18 (18 holes)
6. History teacher j. $14.92 (in 1492 columbus sailed the ocean blue)
7. IRS agent i. $10.40 (form 1040)
8. Jet pilot g. $7.47 (boeing 747)
9. Mathematician d. $3.14 (pi)
10. Paramedic h. $9.11 (call 911)
11. Piano tuner b. $.88 (88 keys on piano)
12. Soap maker m. $30.30 (dirty dirty)
0 Replies
 
markr
 
  1  
Reply Fri 29 Dec, 2006 07:28 pm
[size=8]CHECKS
1. e
2. f
3. m
4. c
5. a
6. j
7. i
8. g
9. d
10. h
11. b
12. n
[/size]
0 Replies
 
Tryagain
 
  1  
Reply Sat 30 Dec, 2006 05:12 pm
"markr was right on the money"

Yeah! I saw the DVD… great shot Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Laughing Mr. Green


Thoh:

1. Calendar vendor e. $3.65 (365 days/yr) Cool
2. Casino worker f. $7.11 (7-11-21) Cool
3. Deer hunter n. $99.44 (99/44 deerfield)
4. Electrician c. $1.20 (120V american voltage) Cool
5. Golf instructor a. $.18 (18 holes) Cool
6. History teacher j. $14.92 (in 1492 columbus sailed the ocean blue) Cool
7. IRS agent i. $10.40 (form 1040) Cool
8. Jet pilot g. $7.47 (boeing 747) Cool
9. Mathematician d. $3.14 (pi) Cool
10. Paramedic h. $9.11 (call 911) Cool
11. Piano tuner b. $.88 (88 keys on piano) Cool
12. Soap maker m. $30.30 (dirty dirty)



Mark:

CHECKS
1. e Cool
2. f Cool
3. m Cool
4. c Cool
5. a Cool
6. j Cool
7. i Cool
8. g Cool
9. d Cool
10. h Cool
11. b Cool
12. n Cool



e Days in the year
f "Natural" rolls in craps
m Rifle caliber
c Voltage
a Holes on a golf course
j Date that Columbus sailed for America
i Tax form
g Type of plane
d First three digits of pi
h Emergency phone number
b Keys on a piano
n Percentage that Ivory Soap claims to be pure




There are 1580 solutions to the puzzle as stated. Of course half of them are 180 degree rotations leaving 790 unique solutions. Shocked (Why did it take me so long!) Embarrassed


Place the numbers 1 to 10 in place of the ten ?'X'. So that NO two consecutive numbers are touching (diagonally, vertically, or horizontally) Question

XX
XXX
XXX
_XX
0 Replies
 
markr
 
  1  
Reply Sat 30 Dec, 2006 05:31 pm
[size=8]1580 SOLUTIONS
I started with 1 and 10 in the middle. It was easy from there.

Note: T = 10

2 4
8 T 6
5 1 3
_ 7 9
[/size]
0 Replies
 
Tryagain
 
  1  
Reply Sun 31 Dec, 2006 12:05 pm
Mark:
1580 SOLUTIONS
I started with 1 and 10 in the middle. It was easy from there. Cool Cool

Note: T = 10

2 4
8 T 6
5 1 3
_ 7 9


That's just great, only 1579 to go…Do me a favor will ya buddy, don't make it look too easy, it will only encourage others. Laughing


Fifteen hunky Riddle forum members and fifteen soppy Trivia students were competing for the fifteen spots on the New Year Math Team.
Since all participants were equally qualified, the following plan was devised for choosing the team:

The thirty members would be placed in a circle, and starting the count from a specific member, every ninth person would be disqualified. The counting would continue until only 15 students were left and they would comprise the team.

Where should the fifteen riddle hunks stand so that all of them would be picked for the team Question

Please use R and S to represent the Riddle and Softy contestants and give the order of the 30 students beginning with the position of the first one to count off.


Happy and healthy New Year to ALL!
0 Replies
 
markr
 
  1  
Reply Sun 31 Dec, 2006 02:28 pm
[size=8]NEW YEAR MATH TEAM

RRRRSSSSSRRSRRRSRSSRRSSSRSSRRS

Trivia wimps equally qualified??? I think not.
[/size]
0 Replies
 
TTH
 
  1  
Reply Sun 31 Dec, 2006 03:37 pm
Trivia wimps equally qualified, I think so.
Sorry to break this to you, but I was done before you were. The time is in a pm.

Not that you asked me but (IMO) if I were one of the hunks and the count started at the 1st hunk in spot #1. I would be in spots # 1, 2, 3, 4, 10, 11, 13, 14, 15, 17, 20, 21, 25, 28 & 29. If the count started at another number I would want to be one of the 1st 4, then in the next 6th & 7th spot, then 2 away from them and the 2 others standing next to them. I wouldn't want to be next so I would skip 1 and be the next. Then skip 2 and be the next 2. Then skip 4 to be that person. Then 3 over from them and lastly right next to that person. But, like I said you didn't ask me.

Happy New Year from a trivia wimp aka soppy trivia student aka tth Very Happy
0 Replies
 
markr
 
  1  
Reply Sun 31 Dec, 2006 10:09 pm
"Sorry to break this to you, but I was done before you were. The time is in a pm." Confused

"Not that you asked me..."
Well, not by name, but by association with A2K...

Based on your post rate (40+ per day), I'd say A2K is your first home!
0 Replies
 
Tryagain
 
  1  
Reply Mon 1 Jan, 2007 08:26 am
Mark: Posted: Sun Dec 31, 2006 1:28 pm


NEW YEAR MATH TEAM

RRRRSSSSSRRSRRRSRSSRRSSSRSSRRS Cool Cool Cool




TTH: By PM: Sun Dec 31, 2006 12:22 pm


If I were one of the hunks and the count started at the 1st hunk in spot #1. I would be in spots # 1, 2, 3, 4, 10, 11, 13, 14, 15, 17, 20, 21, 25, 28 & 29. Cool Cool Cool



"Sorry to break this to you, but I was done before you were. The time is in a pm."


I do believe TTH is referring to a PM (Private Message) and not pm (post meridian). However, good answers are not restricted as to time and are always welcome - take that wimps… Laughing




G'day possums, I trust ya'll are recovering and still have some unbroken resolutions left. One of my New Years resolutions is not to be so nice this year, no easy peasy questions, only ones to shake the foundations. Like this little beast:

If

………...x - 1
F (x) = -------
………...x + 1



How the heck can you express f(2x) in terms of f(x) Question Twisted Evil Drunk



BTW What is the only word in the English language that ends in mt Question
0 Replies
 
markr
 
  1  
Reply Mon 1 Jan, 2007 02:10 pm
[size=8]MT
dreamt
[/size]
0 Replies
 
Tryagain
 
  1  
Reply Mon 1 Jan, 2007 02:25 pm
What do a racecar and kayak have in common, whereas a pickup and kayak do not Question
0 Replies
 
markr
 
  1  
Reply Mon 1 Jan, 2007 02:39 pm
f(2x)

Can x be used in the expression, or only f(x)?
0 Replies
 
markr
 
  1  
Reply Mon 1 Jan, 2007 02:40 pm
[size=8]KAYAK
racecar and kayak are palindromes
[/size]
0 Replies
 
Tryagain
 
  1  
Reply Mon 1 Jan, 2007 03:48 pm
I have it as: f(2x) =

?f(x)?
_____
_f(x)?




A man drove from Detroit to Chicago, leaving at 8 in the morning. The next day he leaves Chicago at 8 and drives the same highway back to Detroit.

If his speed varies, will there be any spot along the route that he passes at exactly the same time each day Question
0 Replies
 
markr
 
  1  
Reply Mon 1 Jan, 2007 09:26 pm
[size=8]DETROIT
There will be exactly one spot. If two people made the trips on the same day, they would pass each other once.
[/size]
0 Replies
 
TTH
 
  1  
Reply Mon 1 Jan, 2007 10:21 pm
Tryagain wrote:

A man drove from Detroit to Chicago, leaving at 8 in the morning. The next day he leaves Chicago at 8 and drives the same highway back to Detroit.

If his speed varies, will there be any spot along the route that he passes at exactly the same time each day Question


Well, coming from one who races a car the answer is yes. Even if you have one driver, one car traveling from Detroit to Chicago leaving at 8 am. Then the next day the same driver leaves Chicago at 8 drives the same highway back to Detroit. That driver can have many spots along the route that he passes at exactly the same time each day.
0 Replies
 
thoh13
 
  1  
Reply Mon 1 Jan, 2007 10:30 pm
f(2x)=[1+3f(x)]/[3+f(x)]

f(x) = (x-1)/(x+1)
solve for x
x=[1+f(x)]/[1-f(x)]

f(2x) = (2x-1)/(2x+1)
plug in expression for x and simplify
f(2x) = [1+3f(x)]/[3+f(x)]
0 Replies
 
markr
 
  1  
Reply Tue 2 Jan, 2007 10:32 am
Nice job, thoh13.
0 Replies
 
Tryagain
 
  1  
Reply Tue 2 Jan, 2007 03:45 pm
Mark:


MT
Dreamt Cool

KAYAK
racecar and kayak are palindromes Cool

(Yeah! Not only that; they read the same backwards) Laughing


DETROIT
There will be exactly one spot. If two people made the trips on the same day, they would pass each other once. Cool


Tryingtohelp aka: TTH

Well, coming from one who races a car the answer is yes. Even if you have one driver, one car traveling from Detroit to Chicago leaving at 8 am. Then the next day the same driver leaves Chicago at 8 drives the same highway back to Detroit. That driver can have many spots along the route that he passes at exactly the same time each day.


(Even I can see where you are coming from)

To see it as clearly as TTH, imagine two women driving the route on the same day, one leaving Detroit at 8 and the other leaving Chicago at 8. They have to pass each other at some point, and they'll be there at the same time.



Thoh:


(2x)=[1+3f(x)]/[3+f(x)]

f(x) = (x-1)/(x+1)
solve for x
x=[1+f(x)]/[1-f(x)]

f(2x) = (2x-1)/(2x+1)
plug in expression for x and simplify
f(2x) = [1+3f(x)]/[3+f(x)]

Cool Cool Cool


WOW! That is hot. Razz


Mark, "Nice job"

To put that into context:- When Einstein came up with: Mc2. Mark was heard to remark: "Whatever"




My new (Made in China) desk calendar consists of two cubes and cards with the names of the months (such as: Jin/Fob/Mer) on them. The day was indicated by arranging the two cubes so that their front faces gave the date.

The face of each cube bore a single digit, 0 through 9, and one could arrange the cubes so that their front faces indicated any date from 01, 02, 03, .... to 31.

The cheap paint has come off, leaving one cube with a 1 and a 2 on it, and the other cube has a 3, 4, and a 5 on it.

Can you assist in determine the missing four numbers on the first cube and the missing three digits on the second cube Question

Thank you, or as they say in China, ?'What you had for breakfast?'





When is this sentence true: There are eleven letters in the alphabet. Question
0 Replies
 
Stormwatch
 
  1  
Reply Tue 2 Jan, 2007 04:31 pm
Tryagain wrote:

When is this sentence true: There are eleven letters in the alphabet. Question


It is always true. When the 3 letters in 'the' are added to the 8 letters in 'alphabet', there are always eleven letters.
0 Replies
 
 

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