The worlds first riddle!

Well, April fool to yu'all.


Mark was as correct as ever.


Shari, "WHATEVER"

= THE (purple) WAVER. Was that what she was saying? Oh. That wasn't clear to me at all. Then again, I don't know what a "purple waver" is, and Google doesn't seem to know, either.


There have been a series of instances where someone has been hacking into government computer systems.
Based on evidence gathered from the NSA, CIA and FBI the detectives believe that a pair of hackers, working together, has been performing the crimes. The detectives have been able to identify five suspects, of which
they're sure two of them are the pair of hackers. They have allowed the five suspects to make two statements each.

One of the guilty hackers makes two true statements. The other guilty hacker makes two false statements. Little is known about the truthfulness of the statements made by the other three suspects.

Suspect A:
1. I haven't hacked into any government systems.
2. B is innocent

Suspect B:
1. I am innocent.
2. E's first statement is false.

Suspect C:
1. I have no idea who the guilty ones are.
2. D's statements are both false.

Suspect D:
1. C's second statement is not true.
2. A is not guilty.

Suspect E:
1. A and B are the hackers you're looking for.
2. At least one of D's statements is true.

Which two are the hackers


E
D
I
T


BACKKCAB


BWORIOTK

[size=8]HACKERS
C, D

rising tide
writ'n book?[/size]

Mark:


HACKERS
C, D

C is the lying hacker and D is the truthful hacker


E
D
I
T
rising tide


BWORIOTK
writ'n book




Thirty-two (32) distinct fair dice are rolled. How many ways are there for nineteen 5s to appear



WOW IRAHS KCAB



TRBOUUBSLHE



YOHEUDRGBEGTS

[size=8]DICE
C(32,19)*5^13 = 424,040,039,062,500,000

bush is in trouble (good!)[/size]

Mark:

DICE
C(32,19)*5^13 = 424,040,039,062,500,000



Because the dice are distinct, we must first select 19 of them as those that show a 5. This can be done in C(32,19) ways. Next we look at all ways that the remaining 13 dice can be rolled. There are 5 choices for the first die, 5 for the next, and so on, resulting in 5^13 ways for the remaining 13 dice to appear. Because each of the C(32,19) is a unique set of 19, each is paired with the 5^13 ways for the remaining dice to appear. This results in Marks answer. He sure is one clever guy!




TRBOUUBSLHE
bush is in trouble (I could not possibly comment). :wink:





After administering a new medicine, a collection of 314 lab rats were tested for four diseases.

One-hundred fifty-three (153) of the rats tested positive for Asefachia, 179 tested positive for Bunkeritis, 148 tested positive for Cluenegligencia, and 155 tested positive for Dipchillase.

Among the same 314 rats, 85 tested positive for both Asefachia and Bunkeritis, 71 tested positive for both Asefachia and Cluenegligencia, 75 tested positive for both Asefachia and Dipchillase, 85 tested positive for both Bunkeritis and Cluenegligencia, 90 tested positive for both Bunkeritis and Dipchillase, and 77 tested positive for both Cluenegligencia and Dipchillase.

I hope that is clear to you all.

We also know that 38 tested positive for all three of Asefachia, Bunkeritis, and Cluenegligencia, 41 tested positive for all three of Asefachia, Bunkeritis, and Dipchillase, 34 tested positive for all three of Asefachia, Cluenegligencia, and Dipchillase and 47 tested positive for all three of, Bunkeritis, Cluenegligencia, and Dipchillase.

Do you follow!

Finally, we know that 17 of the 314 lab rats tested positive for all four of the diseases.


How many of the 314 lab rats tested negative for all four of the diseases

It isnt bad Mark!! You should get out more...come join us!!

Come on dude wake up, when are you gonna get an opportunity like that again?

Where would I find this story?

[size=8]RATS
314 - [(153+179+148+155) - (85+71+75+85+90+77) + (38+41+34+47) - 17] = 19[/size]

Mark:


RATS
314 - [(153+179+148+155) - (85+71+75+85+90+77) (38+41+34+47) - 17] = 19


Solution: Use the Inclusion/Exclusion principle:

314 - (153+179+148+155) + (85+71+75+85+90+77) - (38+41+34+47) + 17=19

Nineteen (19) of the 314 rats tested negative for all four diseases.

How can we both arrive at 19 if we have the + & - swapped?




President John F. Kennedy was well known for his heroic efforts in World War II. During his career in politics, including service in Congress and as President, he developed a reputation for using war stories in his speeches. In fact, those who knew him best claim he told exactly four (4) war stories per speech. They also claim that, in the 5004 speeches in which he told exactly four (4) war stories, he never once repeated the same four stories in the exact same order.

What is the minimum number of war stories Kennedy must have had at his disposal in order for those claims to be true



STRWIEANK


FBLIIGRHDT


GLHOAVNDE

Some analogies I need help with...


1. PRO is to por as TI is to ?

2. " colon " is to : as " """" " is to ???????

3. 24531 is to 51423 as 43152 is to ?

I am not sure but here are my guesses:

IT
Apostrophies
12345

Mark, Its in Trivia and words under "Neverending Story"

I think Shari has 1 and 3.
For 2. I have: Speech or quotation marks.

[size=8]KENNEDY
10 stories would allow him to give 5040 speeches.[/size]

RATS
We don't really have our signs swapped. Distribute the minus sign over my expression in brackets and it is the same as yours.

[size=8]win'in' streak (winning streak)
bird in flight
hand in glove[/size]


WHIM'S ANALOGIES
3 makes sense (12345)
I don't see how the others do.


SHARI'S STORY
Yes. I found it and made an entry.

1. I have thought about IT too, but it seems to easy.

2. the answer has seven questionmarks (???????)
I was thinking the answer was:
" apostrofeapostrofeapostrofeapostrofeapostrofe " or
" quotequotequotequotequote "

3 makes sense (12345) Why?

Mark:

"Distribute the minus sign over my expression in brackets and it is the same as yours."

Thank you, I can see that. Wilco, 10.4.


KENNEDY
10 stories would allow him to give 5040 speeches.


We need to determine n so that P(n,4) is greater than or equal to 5004. By trial and error, n=10. I had the trial, although I doubt Mark had any error.



STRWIEANK
win'in' streak (winning streak)

FBLIIGRHDT
bird in flight


GLHOAVNDE
hand in glove



Hi Whim, long time no see. "3 makes sense (12345) Why?"

The way I saw it was:

24531 = 51423

Therefore the order changes from the first set to the second set:2=4 4=3 5=1 3=5 1=2

So the first digit moves to 4th place etc.




Mark wrote;

SHARI'S STORY
"Yes. I found it and made an entry."



Mark, may I remind you a gentleman NEVER brags about his encounters. I hope you were taking precautions.





Is this a Mark stopper?

My home State University surveyed parents/guardians and new students who took part in the universities "preview" activities. If the "preview" office kept track of whether each response was from a male parent/guardian, a female parent/guardian, a male new student, or a female new student, and the "preview" office received a total of 208 responses.

How many different sets of 208 responses were possible, with respect to the gender-parent/student make-up of the respondents



CCOSUTTS


PRCIUCTE

I never was away. I have been giving answers in other topic. Have you missed that? :wink:

Thanks for the explanation, Try. That works fine, I should have seen that. There should be another solution than 12345.

[size=8]SURVEY
C(211,3) = 1,543,465

cut in costs
cut in price[/size]