The worlds first riddle!

1000!:

Mark, your answer is one that is so close. Who is right?



In a local pet store, the cats sold for $10.00 each and the canaries sold for $15.00. The total value was $360.00. One night, the owner forgot to close the door and the animals got loose.

Two cats and half of the canaries disappeared. If the total value was now $220.00, how many of each were present before the escape

Pet store:

if $140 of pets escaped and we know that $20 of cats escaped that means we have $120 in canaries. 8 canaries @ $15 ea = 120 + 20= 140.

Since the amount of canaries escaped = 1/2 total number of canaries that means there were 16 canaries.

16 @ $15 per = 240
240-360= 120
12 cats @ $10 per = 120

12 cats + 16 Canaries = 360
Or did I mismath

1000!: So close? Do you have a different answer?

Mark:


STRICTLY INCREASING
For N digits (0 < N < 10), there are C(9,N) numbers. Therefore, the total number of strictly increasing numbers is 2^9 - 1 because N can't be zero. So, the answer is C(9,5) / 511 = 126/511. /

1000!
1000/5 + 1000/25 + 1000/125 = 200 + 40 + 8 = 248


Every time a number is multiplied by 10 an extra trailing zero is added, and as 10 = 2 × 5, we need only consider the number of factors of 5 present in 1000!; there are an abundance of factors of 2.

There are 1000/5=200 factors of 5, but we must also ensure that we take into account 25 = 5 × 5, which contains two factors of 5; hence there will be 1000/25=40 extra factors of 5. Similarly, 125 = 5^3, contains three factors of 5, and 625 = 5^4.

1000/5 = 200, 1000/25 = 40, 1000/125 = 8, and 1000/625 = 1.6.

Therefore, I submit 1000! Contains, 200 + 40 + 8 + 1 = 249 trailing zeroes.


Ralph:
12 cats + 16 Canaries = 360

You did real fine.


Having not been given clearance by the Pentagon, I am pleased to announce the start of the bi-millennium Mastermind competition.

Grand prize: A peep in the hamsters cage (at the discretion of the management).


Down in a deep diamond mine, a mile or so below the surface of the earth, is there more gravity or less gravity than there is at the entrance to the mine up at ground level

(Assume the Earth has a uniform density, and ignore any centrifugal and centripetal forces).


Even if you stand perfectly still on an accurate scale, the reading keeps oscillating around your average weight.

Why



A man holds a rifle horizontally 6 feet above the ground. At the moment he fires it, another bullet is dropped from the same height, 6 feet.
Ignoring frictional effects and the curvature of the earth, which bullet hits the ground first

Scale: It oscillates because of heart beat and blood flow (I think)


Rifle:
To easy - I taught marksmanship skills for 5 1/2 years:)
The bullets will hit at the same time, albiet in two different locations, because the gravitational pull is still the same. 9.8 ft/sec ^2^2 if I recall.

Enough already with your questions, why not. The boys are OK, don't you know.


The Solution: 533 1/3 bottles.

Explanation: Since there are 3000 bottles and the camel can carry at most 1000 bottles, at least five trips are needed to carry away all bottles from the depot P (three trips away from the depot and two return trips):


The camel can never travel more than 500 kilometres into the desert if it should return to the depot (the camel drinks a bottle every kilometre it travels!). So point A lies somewhere in the desert between the depot and the front line. From point A to the next point, less than five trips must be used to transport the bottles to that next point. We arrive at the following global solution to the problem (P denotes the depot, M denotes the front line):


P (depot)

===forth===>
<===back====
===forth===>
<===back====
===forth===>

A

===forth===>
<===back====
===forth===>


B
===forth===>


M (front line)



Note that section PA must be in the solution (as explained above), but section AB or section BM might have a length of 0. Let us now look at the costs of each part of the route. One kilometre on section PA costs 5 bottles. One kilometre on section AB costs 3 bottles. One kilometre on section BM costs 1 bottle. To save bottles, we should make sure that the length of PA is less than the length of AB and that the length of AB is less than the length of BM. Since PA is greater than 0, we conclude that AB is greater than 0 and that BM is greater than 0.

The camel can carry away at most 2000 bottles from point A. This means the distance between P and A must be chosen such that exactly 2000 bottles arrive in point A. When PA would be chosen smaller, more than 2000 bottles would arrive in A, but the surplus can't be transported further. When PA would be chosen larger, we are losing more bottles to the camel than necessary. Now we can calculate the length of PA: 3000-5*PA=2000, so PA=200 kilometres. Note that this distance is less than 500 kilometres, so the camel can travel back from A to P.

The situation in point B is similar to that in point A. The camel can't transport more than 1000 bottles from point B to the front line M. Therefore, the distance between A and B must be chosen such that exactly 1000 bottles arrive in point B. Now we can calculate the length of AB: 2000-3*AB=1000, so AB=333 1/3. Note that this distance is less than 500 kilometres, so the camel can travel back from B to A. It follows that BM=1000-200-333 1/3=466 2/3 kilometres. As a result, the camel arrives at the market with 1000-466 2/3=533 1/3 bottles.

The full scenario looks as follows: first, the camel takes 1000 bottles to point A. There it drops 600 bottles and returns with 200 bottles. Then the camel takes again 1000 bottles to point A. Again, it drops 600 bottles and returns with 200 bottles. After this, the camel takes the last 1000 bottles from the plantation to point A. From point A, it leaves with 1000 bottles to point B. In point B, it drops 333 1/3 bottles and returns with 333 1/3 bottles. Then it takes the second load of 1000 bottles from point A to point B. Finally, it carries the 1000 bottles from point B to the market, where it arrives with 533 1/3 bottles.


Please pass on the above to The Quartermaster Corps, but tell them they can keep the 1/3 bottle of camel juice. Ugh!



"Rifle: To easy -"

Dang! Just my luck. Well, assuming you know diddly squat about gems:


The owner of a local jewellery store hired 3 watchmen to guard his diamonds, but a thief still got in and stole some diamonds. On the way out, the thief met each watchman, one at a time. To each he gave 1/2 of the diamonds he had then, and 2 more besides. He escaped with one diamond.

How many did he steal originally

diamonds:
(1+2)2 = 6
(6+2)2=16
(16+2)2=36

his original count was 36 diamonds
(36/2-2)-(16/2-2)-(6/2-2)=1

1000/625 = 1.6
Damn! I'm off to a rocky start in 2006.

GRAVITY
less

DIAMONDS
36

Q. Why don't you post the answer straight away when someone gives the correct answer?

A. It has been agreed that folk on the other side of the world should be given a fair chance. So, if anyone in Australia reads a book …


Mark, who I should add tells me he is not from them there parts, although on present form, maybe from Tasmania. "I'm off to a rocky start in 2006." I could not have put it better myself.

Therefore on my scorecard you have 4738 points, and I now have 3.5. Be afraid, you better believe it.




Diamonds:

Mark , Ralph and Try are suspects in a robbery case. Their trial reveals the following facts:

Either Try is innocent or Ralph is guilty. If Ralph is guilty then Try is innocent. Mark and Try never work together and Mark never does a job on his own. Also, if Ralph is guilty, so is Mark.

Who is guilty

DIAMONDS
None of them is a possibility. However, assuming one or more of the three (and nobody else) did it, Mark and Ralph are the guilty parties.

Ralph made me do it. He threatened to kill me if I didn't help. I'd like to be placed in the witness relocation program.

Diamonds:
After reviewing the information, It must me try that is guilty. Since Mark doesn't work alone, and I was nowhere near the scene, It only leaves try. Nice try try.

Mark wrote, "Ralph made me do it. He threatened to kill me if I didn't help."

You better believe it. "I think he's testing the waters for a tag team." :wink:


" I'd like to be placed in the witness relocation program."

I thought that is why you are here! If you can't do the time, don't do the crime.



If 3 dice are thrown, in how many ways can we obtain a sum of 15

(A toss of 6,6,3, is different from a toss of 6,3,6 etc).

[CODE] Dice: If I did my counting correctly there should be 10 combinations

Mark:

GRAVITY
Less

Down a mineshaft, the gravitational effect would be less because some of the earth's mass is above you. That mass pulls you up, so it cancels the effect of some of the mass below your feet that pulls you down.


DIAMONDS
36



DIAMONDS
None of them is a possibility. However, assuming one or more of the three (and nobody else) did it, Mark and Ralph are the guilty parties.


Mark and Ralph sure are guilty.

If Ralph is innocent, then Bash is innocent and Mark is guilty; but Mark never works alone. Therefore, no one is guilty.

So, Ralph cannot be innocent; he must be guilty. If Ralph is guilty, then Try is innocent and Mark is guilty.


Ralph:
Scale: It oscillates because of heart beat and blood flow (I think).

You think, therefore you am!

The fluctuations result from the up-and -down movement of your blood's centre of gravity as your heart pumps.

Rifle:
To easy - I taught marksmanship skills for 5 1/2 years:)
The bullets will hit at the same time, albiet in two different locations, because the gravitational pull is still the same. 9.8 ft/sec ^2^2 if I recall.

Total recall.


Dice: If I did my counting correctly there should be 10 combinations.

You can count on Ralph.

(3,6,6)(6,6,3)(4,5,6)(6,5,4)(4,6,5)(6,4,5)(5,4,6)(6,3,6)(5,6,4)
(5,5,5)


Diamonds




Pour hot water into a thick drinking glass and into a thin wine glass. Which glass in more likely to crack And why



A ball, a disc and a ring, each 5 inches in diameter, sit at the top of an inclined plane. If all three objects start rolling down the incline at the same instant, which one will reach the bottom first

(Assume that they all roll efficiently that is, they are perfectly formed and don't wobble--and ignore any effect of air resistance and friction.)



The speed of sound in air is about 740 miles per hour. Suppose that a police car is sounding its siren and is driving towards you at 60 miles per hour.

At what speed is the sound of the siren approaching you

Ball disc ring........ ball

speed of sound is constant

wine glasses.....thick one is more likely to crack. something to do with heat differential and expansion.

Speed:

Unless I miss my guess, sound will still travel at the same speed no matter how fast the obect producing the noise is traveling.

You guys are way too smart. Got any dumb friends?


Legally married in Boston, my neighbor has reached an age that is a square of some number. The product of the digits of his age is his wife's age. The age of their daughter is the sum of the digits of the mother's age.

How old are they

Legally married:
his age 7^2 = 49
her age 4*9 = 36
Daughters age = 9

Still legal
Him 8^2=64
her 6*4 =24
dau 2+4= 6

Don't you Mojave types ever sleep?


BTW: Still legal

Has she got a sister?



It is an odd number with three digits. All the digits are different and add up to 12. The difference between the first two digits equals the difference between the last two digits.

What are the digits