Rap:
(If they gave prizes for a beautifully crafted answer, then you would have them by the sack full.)
Step 1
Putting responses into base 10
-------trios-----septos
41------13----------29
22-------8----------16
101-----10---------50
122-----17---------65
Step 2 finding numbers of possible desks and chairs
North
Trios 13=1*7+2*3 so d=1 c=2
Septos 29=2*7+5*3 so d=2 c=5
East
Trios 8---not possible
Septos 16=1*7+3*3 so d=1 c=3
South
Trios 10=1*7+1*3 so d=1 c=1
Septos 50=2*7+13*3=5*7=5*3 so d=(2 or 5) c=(12 or 5)
West
Trios 17=2*7+1*3 so d=2 c=1
Septos 65=2*7+17*3=5*7+10*3 so d=(2 or 5) c=(17 or 10)
Step 3 finding corners
Corners (three possibilities) Septos can only be at East
Case----A---------B----------C
North-Trios-----Trios----Septos
East---Septos---Septos---Septos
South-Trios-----Septos---Trios
West--Septos---Trios-----Trios
Step 4 potential solutions
Case A d=1n+1e+1s+2/5w=5/8 c=2n+3e+3s+17/10w=23/16
Case B d=1e+1e+2/5s+2w=6/9 c=2n+3e+12/5s+1w=18/13
Case C d=2n+1e+1s+2w=6 c=5n+3e+1s+1w=8
Step 5 assumption and conclusion
Knowing how an actuarial likes unique solutions I'd choose
Case C
Septos facing North seeing 2 desk and 5 chairs (2*7+5*3=29 in base 7=41)
Septos facing East* seeing 1 desk and 3 chairs (1*7+3*3=16 in base 7=22)
Trios facing South seeing 1 desk and 1 chair (1*7+1*3=10 in base 2=101
Trios facing West seeing 2 desks and 1 chair (2*7+3=17=122)
* this is given in step 2
Answer:
We know that two of the students are counting in base 3 and two in base 7, but we don't know which ones. The answers in base 10 must also be divisible by a combination of 7 and 3.
Equivalent in base 10 if a Septo. Equivalent in base 10 if a Trio
North 41 29 n/a
East 22 16 8
South 101 50 10
West 122 65 17
North must therefore be able to see 2 desks (worth 7) and 5 chairs (worth 3). Noting that 8 is not divisible by any combination of 7 and 3, East must be a Septo and can see 1 desk and 3 chairs (totalling 16). South and West must therefore be Trios. South can therefore see 1 desk and 1 chair. West can see 2 desks and 1 chair.
Thus in total there are 6 desks and 10 chairs.
Rap:
Seasons, seconds, centuries and minutes---n
16 pencils-5
He makes four pencils from the sixteen nubs and then makes a fifth when he's done using those pencils.
full-jar- 11:59
prisoner response - "You will shoot me."
"You will hang me."
Mark:
SEASONS, ETC.
n
PENCILS
5
AMOEBAS
11:59 a.m.
PRISONER
You'll hang me.
ACTUARIES
North and East are Septos (North because 41 isn't a valid base 3 n umber, East because 8 doesn't produce a valid desk/chair combination)
Therefore, South and West are Trios
After that, there is only one valid desk/chair combination per person.
North: 2 desks, 5 chairs
East: 1 desk, 3 chairs
South: 1 desk, 1 chair
West: 2 desks, 1 chair
Total: 6 desks

, 10

chairs
100!
2: 97
5: 24
The number of factors divisible by 2 is 50 (2 x 50 = 100)
The number of factors divisible by 4 is 25 (4 x 25 = 100)
The number of factors divisible by 8 is 12 (8 x 12 = 96)
The number of factors divisible by 16 is 6 (16 x 6 = 96)
The number of factors divisible by 32 is 3 (32 x 3 = 96)
The number of factors divisible by 64 is 1 (64 x 1 = 96)
So the number of 2s is 50+25+12+6+3+1 = 97
The number of factors divisible by 5 is 20 (5 x 20 = 100)
The number of factors divisible by 25 is 4( 25 x 4 = 100)
So the number of 5s is 20+4 = 24
Dadpad:
seasons seconds etc = N
Nubs= 5, 4 from first 16 and 1 from nubs resulting from those 4
Just in! From our scientific correspondent:
"amoebas (Slippery little suckers)

= 11.59am
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