Sun 13 Nov, 2005 07:55 pm - 2x+3y+4z=2
5x-2y+3z=0
x-5y-2z=-2
the equations should be
[b]2x+3y+4z=2
5x-2y+3z=0
x-5y-2z=-4
[color=darkblue][/color][/b]
sorry it was a typo. (view)
Sun 13 Nov, 2005 05:53 pm - the equations are
[b]2x+3y+4z=2
5x-2y+3z=0
x-5y-2z=-2[/b]
i eliminated z first and i did it like this
2x+3y+4z=2
2x-10y-4z=-10
which equaled 4x-7y=-6
then i eliminated z from these... (view)
Tue 27 Sep, 2005 07:12 pm - if a line is horizontal does it have a slope? and also would the answer to this equation put this is standard form with the given slope through the given point: slope=-4 (2,2)
my answer 2x+2y=-4? (view)
