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Wed 21 Sep, 2005 01:21 pm
ok i have these conditions i have to use to come up with a problem in slope intercept form
slope=4/5
passes through (10,-3)
would the equation be y=4/5x-3?
You have got the slope fine.
The question is does this line pass through the point 10, -3 ?
The way you find out if this is the case is to plug in the value 10 for "x". This would be
y = (4/5)(10) -3
Does this give you -3?
If not what value for X would give you -3?
thanks...so it it doesn't equal -3 then i have to figure out what x would equal?
The equation you are using for the line is
y = Mx + B
You know M (the slope) so the problem must be with B.
You also know that this equation must be -3 when X is equal to 10.
So you can write the equation
-3 = (4/5) (10) + B
(It is very important that you understand how I got this equation. Please ask more questions if you don't get it).
... or it may help to think of B as a "Blank" (you need to find the number that goes there
-3 = (4/5)(10) + ________
What number makes this equation true?
thanks now i underrstand the answer would have to be -5
well y=mx+c
so y= -3, x= 10, c= ? , m=4/5
Therefore -3= 4/5(10) + c
c= -11,
Equation of line y= 4/5x -11
or if you prefer 4x -5y -55= 0
I've never seen the constant repressented by a B.