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Slpoe intercept form in Algebra 2

 
 
tiny07
 
Reply Wed 21 Sep, 2005 01:21 pm
ok i have these conditions i have to use to come up with a problem in slope intercept form

slope=4/5
passes through (10,-3)

would the equation be y=4/5x-3?
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Type: Discussion • Score: 1 • Views: 639 • Replies: 5
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ebrown p
 
  1  
Reply Wed 21 Sep, 2005 01:31 pm
You have got the slope fine.

The question is does this line pass through the point 10, -3 ?

The way you find out if this is the case is to plug in the value 10 for "x". This would be

y = (4/5)(10) -3

Does this give you -3?

If not what value for X would give you -3?
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tiny07
 
  1  
Reply Wed 21 Sep, 2005 01:40 pm
thanks...so it it doesn't equal -3 then i have to figure out what x would equal?
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ebrown p
 
  1  
Reply Wed 21 Sep, 2005 03:08 pm
The equation you are using for the line is

y = Mx + B

You know M (the slope) so the problem must be with B.

You also know that this equation must be -3 when X is equal to 10.

So you can write the equation

-3 = (4/5) (10) + B

(It is very important that you understand how I got this equation. Please ask more questions if you don't get it).

... or it may help to think of B as a "Blank" (you need to find the number that goes there

-3 = (4/5)(10) + ________

What number makes this equation true?
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tiny07
 
  1  
Reply Thu 22 Sep, 2005 10:51 am
thanks now i underrstand the answer would have to be -5
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Milfmaster9
 
  1  
Reply Sun 25 Sep, 2005 04:21 pm
well y=mx+c
so y= -3, x= 10, c= ? , m=4/5
Therefore -3= 4/5(10) + c
c= -11,

Equation of line y= 4/5x -11
or if you prefer 4x -5y -55= 0

I've never seen the constant repressented by a B.
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