1
   

I hope you're good at Math!

 
 
zex
 
  1  
Reply Wed 26 Nov, 2003 09:57 pm
Yes, that is what was meant. Laura's answer is correct. Perhaps you should read the replies before making your own.
0 Replies
 
andrewcarlin
 
  1  
Reply Fri 28 Nov, 2003 11:46 am
i'd appreciate it if there was less cheek!!
zex wot the hell did i ever do to you??
u guys r far to sensitive!! lol
0 Replies
 
alonblue
 
  1  
Reply Wed 4 Feb, 2004 10:35 am
Another solution
upper integer value ( square root (22) )

Alon
0 Replies
 
Relative
 
  1  
Reply Wed 4 Feb, 2004 01:13 pm
Here's another : using exactly five 5 digits, plus any number of math. symbols, excluding symbols representing numbers and variables, can you get all numbers from 1 to 10?
How about 10-20?

And for the most fun, try with five 6 digits.

I say no number symbols because one other solution to 2's problem is
2+2+x/x ; x is a natural number.
As a matter of fact, you can get 1 in many ways in math..

Relative
0 Replies
 
OCCOM BILL
 
  1  
Reply Wed 4 Feb, 2004 02:05 pm
.2 Divided by .2 squared = 5 I don't know where to find the symbols on my keyboard.
0 Replies
 
chaossoldiermsc
 
  1  
Reply Thu 5 Feb, 2004 07:39 am
[(1+2)-3]divide by 4=0
1*2+3-4=1
1+2+3-4=2
1+2-3+4=4
(1+2)*3-4=5
(1-2)+3+4=6
1+2+3+4=10
0 Replies
 
Relative
 
  1  
Reply Thu 5 Feb, 2004 09:24 am
Uh, i meant you can use digit 5 , five of them, like

5*5+5+5-5 = 30
0 Replies
 
Iacomus
 
  1  
Reply Fri 6 Feb, 2004 12:05 pm
Relative

(5+5+5)^(5-5) = 1
((5 + 5 )* 5/5)/ 5 = 2
((5+5)/5)+5/5 = 3
(5 - 5/5)*5/5 = 4
(5*5*5)/(5*5) = 5
((5+5)/(5+5)) + 5 = 6
(sq rt5* sq rt5 )+ ((5+5)/5) = 7
((5+5+5)/5)+5 = 8
(5+5)-((sq rt5*sq rt5)/5) = 9
((sq rt5*sq rt5)/5)*(5+5) = 10

To do it with five 6's, the first three can be arrived at merely by replacing each 5 in this 'fives' solution with a 6.
6-6/6-6/6 = 4
6*6/6 - 6/6 = 5
(6+6)/(6+6) *6 =6
((6/6) *(6/6)) + 6 = 7
(6/6) +(6/6)+6 = 8
((6+6+6)/6)+6 = 9
(6+6)- ((6+6)/6) = 10
0 Replies
 
Relative
 
  1  
Reply Fri 6 Feb, 2004 12:35 pm
Iacomus : that is correct.
Also : 55/55 + 5 =6


There is another, more elegant riddle: do the same using digit 4, and you can use 4 of them.

I don't see what is wrong with your post or why should I disregard it?
0 Replies
 
Iacomus
 
  1  
Reply Fri 6 Feb, 2004 12:58 pm
Relative

Your original question asked for 'one to ten' and my original post only gave 'one to five'. I have now edited it - after quickly finding the answers I had not included first time - and I think it now is a better response to the question as asked.
0 Replies
 
Iacomus
 
  1  
Reply Fri 6 Feb, 2004 01:18 pm
1 to 10 using four 4's:

(4/4) * (4/4) =1
(4/4) + (4/4) = 2
(sq rt4*sq rt4)-(4/4) = 3
(sq rt4*sq rt4)*(4/4) = 4
(sq rt4*sq rt4)+(4/4) = 5
((4+4)/4) +4 = 6
(4+4)-(4/4) = 7
(4+4)*(4/4) = 8
(4+4)+(4/4) = 9
(4! /4)+(sq rt4 * sq rt 4) = 10

I didn't want to use numbers such as '44' because I felt that this was just a shade dishonest in that there is a hidden '4*10 + 4' in there and it is no longer using '4'. The same would be true of using a decimal point as this is a hidden 'divide by ten'. IMHO of course.
0 Replies
 
Relative
 
  1  
Reply Fri 6 Feb, 2004 01:42 pm
Very good, Iacomus!
The original author uses

0 = 44-44
1 = 44/44
2 = 4/4+4/4
3=(4+4+4)/4
4=4+(4-4)/4
5=(4*4+4)/4
6=(4+4)/4+4
7=44/4-4
8=4+4+4-4
9=4+4+4/4
10=(44-4)/4

It is possible go get even more numbers Smile
0 Replies
 
Iacomus
 
  1  
Reply Fri 6 Feb, 2004 02:38 pm
Relative

I'm sure that you are right and that many more numbers could be arrived at. However, this type of problem is a devourer of time and I will save it for the nights when I can't sleep, or when I am stuck in an airport without reading material (or in solitary confinement maybe! Sad )
0 Replies
 
Relative
 
  1  
Reply Fri 6 Feb, 2004 02:54 pm
Iacomus wrote:
Relative

I'm sure that you are right and that many more numbers could be arrived at. However, this type of problem is a devourer of time and I will save it for the nights when I can't sleep, or when I am stuck in an airport without reading material (or in solitary confinement maybe! Sad )
Uh, I hope not!
0 Replies
 
Relative
 
  1  
Reply Fri 6 Feb, 2004 04:02 pm
A tough problem, an oldie
I am going to repeat an old problem that first appeared in a weekly newspaper, where riddles were posted by no other than the great M. Gardner. A prize of 100$ was later promised for a solution.

"Five men Cool find themselves shipwrecked on an island, with
nothing edible in sight but coconuts, plenty of these, and
a monkey Shocked . They agree to split the coconuts into five equal
integer lots, any remainder going to the monkey.
Man 1 suddenly feels hungry in the middle of the night
and decides to take his share of coconuts at that very
moment. He finds the remainder to be one after division
by five, so he gives this remaining coconut to the monkey
and takes his fifth of the rest, lumping the coconuts that
remain back together. A while later, Man 2 wakes up
hungry too, and does exactly the same - takes a fifth of the
coconuts, gives the monkey the remainder, which is again
one, and leaves the rest behind. So do men 3, 4, and 5.
In the morning they all get up, and no one mentions anything
about his coconut-affair the previous night. So they share
the remaining lot in five equal parts finding, once again, a
remainder of one left for the monkey. Find the initial number
of coconuts.
"

The problem is HARD, so don't think there's something wrong with you if you can't solve it. The first solution was hard labour. Allegedly, it was Paul Dirac himself who provided the clever solution which is in fact very elegant and simple. Also allegedly, this had to do with his then current work on anti-electrons. Now there's a clue in there.. Idea
0 Replies
 
Iacomus
 
  1  
Reply Fri 6 Feb, 2004 05:48 pm
Relative

Then it is now established for certain that I am no Dirac but I am one of the monsters (I was hoping I'd be somewhere in the middle :-( )

So far I have this monstrosity.

Where x is the number they started with and y is how many coconuts each man received in the final share out:

4^5x - 5^6y = A

And A is where the monstrosity creeps in, because:

A = 5 + 4^1 * 5 + 4^2 * 5 + 4^3 * 5 + 4^4 * 5 + 4^5 = 11529
[To save writing in the parenthesis - the '+' and '*' operations are carried out in sequence starting from the left]

If it wasn't for that darn monkey getting one coconut each time this would be quite easy! But this has just ceased to be relaxation. This is WORKING!! Sad
0 Replies
 
Relative
 
  1  
Reply Fri 6 Feb, 2004 08:39 pm
Hm, I spelled it out on paper and it seems to me that my monster is the same Shocked Laughing


All we have to do now is run this on a decent excel , khm..uh I mean paper sheet.

But, you still have a chance at Dirac, while I don't Cool !
0 Replies
 
Iacomus
 
  1  
Reply Sat 7 Feb, 2004 03:59 pm
Relative

After walking away from this problem, and with the help of a few beers, I now suspect that I am doing this the hard way.

Clue: The monkey - I never did like that monkey anyway! - falls into the water and is eaten by a shark. As is the way of belief on that island he returns as four ghost coconuts, which snuggle with the 'real' coconuts in the original pile.

I will have another look at this after my usual weekend of riotous and ribald excesses (I wish!)
0 Replies
 
Tryagain
 
  1  
Reply Sun 8 Feb, 2004 11:21 am
0 Replies
 
Relative
 
  1  
Reply Sun 8 Feb, 2004 02:05 pm
I am sorry to have been a bit slow over last two days.

Iacomus : your thinking is very interesting!

Tryagain : I just wonder how you solved
1024x - 15625y=11529 ?
And congrats on the correct answer Smile

However, there is still a competition for the generalized problem:

We have N men on the island, blah blah, and the monkey that gets one coconut on every iteration!
0 Replies
 
 

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