Are we less heavy at the equator?

I haven't looked it up but as I recall the earth actually bulges at the equator due to centrifugal force which would mean there is more mass attracting you there than at the poles.

Actually, that bulge will decrease your weight (by an insignificant amount). You are slightly further from the Earth's center of gravity, which reduces force.

Also, you experience centripetal force (I won't get into an argument about whether it's and actual "force." It's inertia counteracting some of the downward force exerted by gravity, anyway.)

So yes, a very accurate scale would measure you slightly differently at the pole vs the equator.

There are places in the Earth's crust where massive, dense objects are relatively close to the surface; these spots affect satellites and such.

Indulge me for a moment. If the Earth was uniformly dense throughout and perfectly spherical, then we would be less heavy at the equator than at the poles? Do you have any idea how to go about calculating this? ....anyone ...anyone?

http://www.batesville.k12.in.us/physics/phynet/mechanics/circular%20motion/centforce_and_earth.htm

Calculation for a 60 Kg mass/person:

Thank You.

Yes, the Earth's rotation makes an object weigh slightly less at or near the equator.

No.
Take your scales to equador, stand on them/it, and you'll weigh the same.

You will weigh less by the amount mv^2/r where m is your mass, v is your speed caused by the rotation of the Earth, and r is the distance to the center of the Earth.

I'd say you weigh the same and have the same mass but the centripital force of rotation is counteracting some of your weight on the scale. The difference caused by distance from center of earth's mass is not a big enough factor to measure without very elaborate measuring methods.

Wrong again.
Weight is relative only from the perspective it is observed from.

Almost, Lead...

Did (Imaginary moon-lander) Neil Armstrong (LIAR) weigh any more/less when on (the moon)?
Nope.
He was still a liar of same weight.

The forces attracting him were different - His weight remained the same.

From the NASA website.

Almost Mark.

His MASS remained the same.

Weight = Mass X local gravity + or - any other factor (like centrifugal force)

Gravity doesn't exist.

Weight has nothing to do with mass.

What IS weight relative to then?

Force upon/against (Electro-magnetic)
what weight is a tin can - When (Gravity 'false force') can be undone (Whole Earth's) by a tiny magnet pulling against it?

Gungasnake, is that you?

Your statement is very vague. Please give an example of what you mean. What do you mean when you say it is relative and what do you mean when you talk about the perspective it is observed from?