The worlds first riddle!

Rap:

At least one means that all three can be defective
P(E)=(0.1)^3
Two can be defective
P(E)=3*(0.9)*(0.1)^2
One can be defective
P(E)=3*(0.9)^2*(0.1)
You can add all three of these expectations up OR
you can do it the easy way and determine of three good parts
P(E)=(0.9)^3
and subtract it from 1

So

P(E)=1-(0.9)^3=1-0.729=0.271



Yes; you would have thought so. However, the truth is:


10nCr3(.1)^3(.9)^7 = .0574 probability of finding 3 defective
10nCr2(.1)^2(.9)^8 = .1937probability of finding 2 defective
10nCr1(.1)^1(.9)^9 = .3874 probability of finding 1 defective

The probability of at least one defective is therefore 0.6385 or 63.85% :wink:


"Sos OK Try anything you want"

If that is an SOS you are sending out; then a place in the lifeboat would be good to start.



Mismi wrote, "What of it? I gave birth to him and I am pretty sure that I gave him a good many of my brain cells. So really - it's the same thing"

Indeed it is; what a pity there is no female baby to inherit your soft brown eyes and random procrastinations.


What ^ said…

Hiya Jove etc, where have you been; I was beside myself with worry. Are you well, do you have exciting adventures to narrate? Have a nice day!



SELED

GBDAT

DREKD

linseed

dingbat

kindred

(you are a romantic) :wink:

Miss mi:

SELED = linseed

GBDAT = dingbat

DREKD = kindred

You rock! Nice bunns too!





Of cause I don't look busy…I did it right first time! Well, that's not strictly true; but if you are determined:

Determine the number of collected terms in the expansion of (2a-7c)^n

Determine the value of the coefficient R in the collected term Ra^5bc^12 resulting from the expansion of (a+b+c)^18

Well, I thought it was pretty obvious you haven't been looking at my eyes (blue) :wink:

10nCr3(.1)^3(.9)^7 = .0574 probability of finding 3 defective
10nCr2(.1)^2(.9)^8 = .1937probability of finding 2 defective
10nCr1(.1)^1(.9)^9 = .3874 probability of finding 1 defective

This makes no sense to me. Where does C(10,3), C(10,2), and C(10,1) come from? The problem doesn't state that we pick 3 from a group of 10.

Try wrote:
"Hiya Jove etc, where have you been; I was beside myself with worry. Are you well, do you have exciting adventures to narrate? Have a nice day! "

At home trying to figure out how to get a job during a recession. I would write more so people don't get worried but me (main frame) can be quiet at times.

I just ate a lemon candied fruit slice and ended up in Egypt as well as The Shaw.

I had a dream year's ago that my daughter's dad worked for you when you were living in Concord, Ma. and i told him recently. I think my Mersca disease makes me tired and blasa'.

I'm drawing another picture of Raphael in pencil, it's comming out o.k. This is what i am using as a markr ~
http://a1055.g.akamai.net/f/1055/1401/5h/images.barnesandnoble.com/images/9790000/9799794.jpg


Last year on the 4th of July, i watched fireworks from the Haverhill stadium,,, one of the fireworks display had gold in it,,, it was unbelievable looking,,, beautiful i think i will do that again.

I wish you could see it the way i am going to!~


Do you know what country Dracula would have lived in if he resided in Transylvania?

I think it would be Romania Jove...but that is just me thinking. And that doesn't always turn out so good! :wink:

Aoccdrnig to a rscheearch at Cmabrigde Uinervtisy, it deosn't mttaer in what oredr the ltteers in a wrod are, the olny iprmoetnt tihng is taht the frist and lsat ltteer be at the rghit pclae. The rset can be a total mses and you can sitll raed it wouthit porbelm. This is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the word as a wlohe.



Mark raised a query, "The problem doesn't state that we pick 3 from a group of 10."with replacement.'

Agreed, the wording could have been made a little clearer; but does the answer make sense with the choice always being; one from ten?



Jove wrote a jolly little critique; may your illnesses be transferred to your enemies, may your drawing be as enchanting as the original and that all your dreams come true.

As for Dracula; didn't he live in a castle?


Miss mi, your eyes; those limpid pools:

Mine eyes have seen the glory of the coming of the Lord;
He is trampling out the vintage where the grapes of wrath are stored;
He hath loosed the fateful lightning of His terrible swift sword;
His truth is marching on.
Glory! Glory! Hallelujah! Glory! Glory! Hallelujah!
Glory! Glory! Hallelujah! His truth is marching on…



FKOLK

CESRE

DUPWS

FKOLK = kinfolk

CESRE = sincere

DUPWS = I haven't a clue

thanks Try

WIND UPS!

Try just following the wind.

But I prefer this definition:

To convince somebody that something is true, especially when it is not, often for humorous purposes (windup).

where does that "s" go?

Wind Ups..... our BabyBlue is good at them hun

Don't you play windups on friends?

Or Mismi just upwinds?

being upwind is a good thing right Francis?

I have never heard of windups...except in baseball or long conversations...but if that is the definition then I think Tryagain is indeed quite good at them. :wink:

Please post in humour section next time

Try wrote: "As for Dracula; didn't he live in a castle?"

I was Vlad The Impaler ( Draculas' kid) and i became happier!

A look at Thee LanD

http://www.bootsnall.com/images/eu/nov02dracula2.jpg

"Poienari Castle perched high on a steep precipice of rock"

http://www.bootsnall.com/images/eu/nov02dracula4.jpg

"Standing in triumph on the castle's tower"

I have Thee urge to live in Europe Altenburg, Germany stands out.

Hello; has this thread closed down? By Jove is there a problem getting to your point!

Well. If I can't answer a question, let me post one…


Wimbledon Tennis in England is being played, and your job is to store the remaining tennis balls in buckets.

The storage area will only hold rows of three buckets, but will hold an undetermined number of rows.

You must follow three inviolable rules in storing the tennis balls:

• Each bucket must have a different positive number of balls.
• Each row must have the same total number of balls in its three buckets.
• The total number of balls in each row is as small as possible.


For example, if you were given only two rows of buckets, the setup:

1/3/7
2/4/5

Achieves a row total of 11. This is the best possible arrangement for two rows. (Take my word; it is!)



Can you give a construction that gives an optimal arrangement that works for an arbitrary number k of rows?

By the grace of Jove, Roman god of gods, if this thread closes down, it will be only on a Thursday

Using the numbers 2, 4, 4, 4 and 5 with mathematical operators can you make 51?