The worlds first riddle!

Hi back solipsister
Why do you think I am studying anything?

Actually, I have 2 Associate degrees and one BA with 2 majors and 1 minor along with a 1 year certificate and one class short of another degree. Most in different subjects. That's all in my past now. So, I don't have to think unless I want to [/quote]

I missed the fine print

Dang due diligence done duped

I really didn't foresee the Internet. But then, neither did the computer industry. Not that that tells us very much of course - the computer industry didn't even foresee that the century was going to end.

"640 K ought to be enough for anybody."
Bill Gates, 1981

To err is human, to moo is bovine!


Mark:

DARTS
34/243

For those of you sans an abacus: 0.139917695


TTH:

Examination
9 correct is 90 and 3 incorrect = -15
leaving a score of 75

Hmm, that seems to simple so what am I missing?

All questions are easy if you know the answer; we cater for all abilities! :wink:


Slippy:

…3rd degree attempted unanswered tautology…

That, in itself, is logically true.

"A group of cohorts split the infinitive."


One of the most famous split infinitives occurs in the opening sequence of the Star Trek television series:

.

Here, the adverb "boldly" splits the full infinitive "to go."




BLPANOYK

DODNGG

solipsister
I am currently not studying anything. I already have those degrees, except for the one I am 1 class short in. I refused to internship for free since I was already going to school full time and working full time. The job I had at the time dealt with the subject matter imo. The college did not agree and would not waive the internship requirement.

ding dong

BLPANOYK

[size=7]If the Y were a T, I'd say point blank.[/color[/size]]

TTH:

DODNGG = ding dong

I thought that one would last forever!


Mark:

BLPANOYK = If the Y were a T, I'd say point blank.

I'd say yet again, "To err is human, to moo is bovine!"…Mooooo!


Does the parabola 3y = x^2 - 17 pass through any lattice points




Find, if you are so minded; the smallest positive integer n such that the product of n and 999 does not contain the digit 9

No

[size=7]112[/size]

LATTICE POINTS

[size=7]no - x^2 - 17 cannot be a multiple of 3 because x^2 = 0 or 1 mod 3, but 17 = 2 mod 3.[/size]

Don't believe everything you read in comic books, you can always get more with a kind word and a 2-by-4 than with just a kind word alone.


TTH:

Lattice points
No


Thoh:

Smallest positive integer

112


Mark:

LATTICE POINTS

No - x^2 - 17 cannot be a multiple of 3 because x^2 = 0 or 1 mod 3, but 17 = 2 mod 3.


A better explanation you will never see!




CEAXAREFMULELY


TTAOLUKGGH

CEAXAREFMULELY = examine carefully


TTAOLUKGGH = talking tough

Uh Try, I really didn't know the answer, but since it was a yes or no question I figured I had a 50% chance of getting it right
So, I have to give you < this thing back

Stormy:

CEAXAREFMULELY = examine carefully


TTAOLUKGGH = talking tough

Well, at least I got all the letters in there!

TTH writes, "I really didn't know the answer, but since it was a yes or no question I figured I had a 50% chance of getting it right"

Statically speaking; when faces with a yea/no question, people answer Yes 66% of the time - so keep your :wink:



Upon solving the system of equations x^5y^17 = r and x^2y^7 = s for x and y, the answers turn out to be of the form:

x = r^a/s^b and y = s^c/r^d, where a, b, c, and d are positive integers.

Calculate if you dare the sum a + b + c + d

[size=7]x^5*y^17=r => x^35*y^(7*17)=r^7
x^2*y^7=s => x^34*y^(7*17)=s^17

x^34/x^34*y^(7*17)/y^(7*17)=x=r^7/s^17
a=7, b=17

udder way
x^5*y^17=r => x^10*y^(2*17)=r^2
x^2*y^7=s => x^10*y^(5*7)=s^5

x^10/x^10*y^(5*7)/y^(2*17)=y=s^5/r^2
c=5, d=2

so a+b+c+d=7+17+5+2=7+7+7+10=21+10=31[/size]

Rap

Start every day off with a smile and get it over with… Reminds me of my camping trip. Somebody forgot the corkscrew and for several days I had to live on nothing but food and water.



Rap:

a + b + c + d


x^5*y^17=r => x^35*y^(7*17)=r^7
x^2*y^7=s => x^34*y^(7*17)=s^17

x^34/x^34*y^(7*17)/y^(7*17)=x=r^7/s^17
a=7, b=17

udder way
x^5*y^17=r => x^10*y^(2*17)=r^2
x^2*y^7=s => x^10*y^(5*7)=s^5

x^10/x^10*y^(5*7)/y^(2*17)=y=s^5/r^2
c=5, d=2

so a+b+c+d=7+17+5+2=7+7+7+10=21+10= 31


Man that is just so beautiful; like you were writing poetry!



habandoopnge


laobivdge

Recommendation---When camping next time bring a fine wine product with a screw off lid.

Rap

abandoning hope
abiding love

btw that was good raprap

TTH:

habandoopnge = abandoning hope

laobivdge = abiding love


Rap wrote, "When camping next time bring a fine wine product with a screw off lid."

Wise words indeed!


You and your 5 friends decide to order a large pizza, but when you call in your order, the pizza man asks you how many cuts across the pizza you want him to make.

Although stunned at this question you tell him 6 because there are 6 of you.

Then the pizza man responds back ...
"I'll tell you what -- when your pizza arrives, if you can tell the driver the maximum number of pizza pieces you would have with 6 cuts, he will take $1 off the bill, and, if you can tell him the maximum number of pieces you would have in general with "n" cuts, he will give you the pizza for free."

What would your answer have to be to get the free pizza




Suppose that a, b, and c are positive integers such that a/3 = b/4 = c/5 and abc = 1620.

Find b

[size=7]If you can fold or stack the pizza, you can double the pieces with every cut,,so with 6 cuts yout should get 2^6 (64) pieces. In general you can use this technique for 2^n pieces for n cuts.

b=9[/size]

Rap

Extending camping blamed for B vitamin deficiency.

Not the 9 o'clock news.