TehMeh:
EBSUSS = Business
GMAUCHEN = Machine gun
(Make love; not war!)
Listen up Techie, you are far too brainy; spend more time on the beach or skate park! :wink:
Stormy wrote, "
now they want to know who the blue guy is that's giving me bum info
"
Tell them it's the same guy who gives everyone bum info!
4-DIGIT NUMBER
On the face of it, an almost impossible task! However, let's take a look in more detail:
Since the sum of the digits is 6, none of the digits can be 6, 7, 8, or 9.
So the digits we can use are 0, 1, 2, 3, 4, 5
Since the number is odd, the last digit must be odd.
Since there is at least one odd digit and the sum of the digits is 6, there must be at least one more odd digit (at least 2 odd digits total) because odd + odd = even and odd + even = odd.
So there has to be a 1 and a 3, a 1 and a 5, or a 3 and 5.
There can't be a 3 and a 5 because these two digits add to 8 which is greater than 6.
If there are a 1 and a 5, this adds to 6. We can use these if the other two digits are 0 but each digit is different. So we can't use 1 and 5.
So we know that there are a 1 and a 3.
There are two digits left to fill and we have a choice now of 0, 2, 4.
Since the digits add to 6 and we already have 1 and 3, the only two digits we can choose are 0 and 2.
So our four digits are 0, 1, 2, 3.
To arrange them to give the largest number possible that is still odd: 3201. Did anyone get this?
Mark:
4-DIGIT NUMBER
3201
There you have it!
FOUCONTASIN
DFOERUMX
oh joy. How have you been keeping all these days?
:wink:
