The worlds first riddle!

145 + 216 = 361

This one again? Someone else can have at it.

because if he ran any further, he'd be running OUT of the woods

36 is the number i have the most writing for actually....

66 + 1 = 67

Then you're sure to win. :wink:

67 + 16 = 83

ok i think i found my mistake....i thought 92 was a never-win situation but now i see that both ppl can win ...well this was very confusing lol

83 + 9 = 92

92 is a never-win situation.

The end game is as follows:
92, 93, 94, 98, 99, 100
or
92, 93, 97, 98, 99, 100

To figure games like this out, start at the end.

100 is a winning position - mark it with a W.
Subtract all possible moves (in this case squares) from 100. They are losing positions - mark them with an L.

Go to the next unmarked position. It must be a winning position - mark it with a W.
Subtract all possible moves from this number. They are losing positions - mark them with an L.
Repeat these last two steps until done.

Once a player has achieved a winning position, he is guaranteed to be able to maintain a winning position throughout the game.

The winning positions for this game are:
100, 98, 95, 93, 90, 88, 85, 83, 80, 78, 66, 61, 56, 48, 43, 38, 35, 33, 28, 15, and 5.

So, the answer to the first question I posed is that the first player will lose if constrained to picking a square on the first move.

Everyone is entitled to be stupid, but some abuse the privilege; I'm not saying there should be a capital punishment for stupidity, but why don't we just take the safety labels off of everything and let the problem solve itself?





Thoh:

Bill and Caroline


B = 8 + C
B-5 = 3(C-5)
B = 17, C = 9


A master class in clear thinking.



TTH wrote, "This one again? (referring to dog in wood) Someone else can have at it."


Hey! At least it was a different dog.


Thoh: Because if he ran any further, he'd be running OUT of the woods





Mark, I think you should give a name to both games; something new deserves recognition.




145 + 216 = 361


Cubes:

361 + 64 = 425




S H E E T





…..D
…..I
DIGIT
..…I
..…T

S H E E T= spread sheet

I doubt they're original.

425 + 8 = 433

Stormy:

S H E E T= spread sheet






Cubes:



425 + 8 = 433


433 + ? Will this nightmare never end! Not only can't I work backwards; I cannot figure out why I loose on 441 and 442…you are messing with my mind.




A FBI wanted poster of Try has on it a rectangular printed area of 100cm by 140cm, with a blank strip of uniform width around the four edges. The perimeter of the poster is 1 ½ times the perimeter of the printed area.

What is the width of blank strip, and what are the dimensions of the poster






CRIMSON




MISDODLWE

441 is a loss. 442 is a win, but you can't get there from 433.

441 .. 449 .. 450 .. 451
442 .. 443 .. 451
or
442 .. 450 .. 451

POSTER
[size=7]width = 30 cm
dimensions = 160 x 200[/size]

When everything is coming your way……you're in the wrong lane and going the wrong way!
Which proves; if at first you don't succeed, destroy all evidence that you tried.



Mark:


POSTER


width = 30 cm
dimensions = 160 x 200


w: width of the blank strip
Perimeter of the strip = 2[(100 + 2w)+(140+2w)]= 1.5[2(100+140)]




441 is a loss. 442 is a win, but you can't get there from 433.


Yeah, I know. A bit late, but I still think it is a great idea.



CIRCUI

CIRCUI
[size=7]short circuit[/size]

^^^^ this post right here, mark I can read the white.

Dump the Mac and get a PC.

Why, so I can't see it.
I like my Mac.

I have a PC and I can't read it either

Please allow me to rectify your vision impairment:


Mark:

CIRCUI = short circuit


(On a PC if you highlight the answer; you reverse the colors. If you cut and paste; ?'Keep text only' restores the text size.)






Adapted from Enigma No. 1452, by Susan Denham, New Scientist 21 July 2007.



TTH with a little help from Ksanfo made a 4x4 grid of squares, being a 5x5 grid of horizontal and vertical lines. If you figure it out, you can see there are 100 rectangles that can be made out from portions of those vertical and horizontal lines.

She then made a much larger such square grid. The number of little squares in it was a 3-digit number. She calculated how many rectangles of all sizes and shapes were thus formed on that new grid.

She then cut along one of the straight lines of the grid to make two rectangular grids. Then she calculated the total number of rectangles in each of the two new pieces.

It turned out that the total of these two numbers was exactly two thirds of the number visible on the original large square grid from which the two were cut.

What was the size of the original large grid before she cut it, and how far away from an edge did she cut it



Mail male Pat



FREE EE E

ENIGMA 1452
[size=7]Original: 27x27
Pieces: 27x6, 27x21[/size]