Mark:
BUCKINGHAM FOUNTAIN
5/9
The diagonals intersect the axes 1/3 of the way between 12:00 and 1:00. Inside the diagonal bar represents them meeting. The sum of the areas of the triangles is 4/9; so the diagonal is 5/9.
What the!!!.....
graph explanation:
Both axes represent time. The x-axis is time for the person x; the y-axis is time for person y.
Pick a point in the square. The x-coordinate is when person x arrives; the y-coordinate is when person y arrives. Using that point as the bottom left corner, create a smaller square that is 20 minutes by 20 minutes. If that smaller square intersects the line x=y (main diagonal of larger square), the people will meet.
It would appear Mark's answer does not take into account the direction of the wind, or Thoh's pronounced limp!
Let's check it out:-
There are four events that can happen.
1. Thoh arrives first and TTH meets him while he is waiting.
2. Thoh arrives first, leaves and then TTH shows up.
3. TTH arrives first and Thoh meets her while she is waiting.
4. TTH arrives first, leaves and then Thoh shows up.
Also there are 3 main time segments that different things can happen during. from 12:00 12:00-12:20, 12:20-12:40, 12:40-1:00.
There is a 1/3 chance of TTH showing up in any of these times.
If TTH shows up from 12:20-12:40
Then there are 20 minutes before and after TTH's arrival that Thoh could arrive and they would meet. So 40 minutes out of the hour that Thoh could arrive and they will meet. (40/60)
If TTH shows up between 12:00 and 12:20 there are 20 minutes after her arrival, and all the time between 12:00 and when she arrived. This time averages out to be 10 minutes (remember we are assuming she showed up between 12:00 and 12:20) So that's 30 minutes out of the hour that Thoh could show up and they would meet. (30/60)
From 12:40-1:00 you have a similar situation. There's twenty minutes before TTH's arrival that Thoh could have shown up. And all the time till 1:00, which again averages out to 10 minutes. So again 30 minutes out of the hour.
(30/60)
Each of those three are equally likely with 1/3 probability so
1/3(30/60 + 40/60 + 30/60)
1/3(5/3)
5/9
Their probability of meeting is 5/9. So Mark was right all along

.
I can't wait to see the pictures.
VSHAORLTCIUTD = invalid shortcut
(TTH: ?'VALID SHORT CUT'

)
Well done girly. But to be fair short cut was (in) valid, which makes it; INVALID
DRCRIAVECKWAGY = crack in driveway
Ha ha! That lasted six minutes. (I will have to check the other one).
Fast Mark is trying his hand at blackjack on a
two deck table in Las Vegas.
The dealer rolls through 3 hands in which Mark counts 17 face cards and 29 non face cards.
On the fourth hand he sees 4 face cards and 9 non-face cards, of which he has a SEVEN and a FIVE and the dealer has an ACE showing.
What are the odds that Mark will bust if he takes one card