Tryagain wrote:Yes, we have no oranges:
A fruit grower wants to transport his 3000 juicy CA oranges 1000 miles across the desert to the market. (Yep, it is a big state) All Mark can use is his one camel which can carry 1000 oranges at once but it needs to eat one orange to walk one mile (that is the camel not Mark, regardless of how many oranges it is carrying).
The way I see it;
1000 miles
3000 oranges
1000 oranges max per trip
One orange eaten per mile
= zero oranges at the end.
What do ya'll think
How many oranges can Mark get to market
Tryagain, I think I prefer being a trivia nerd. I know the answer is not zero. I also know this is not the answer, but I liked it and it was easy: Just make the damn camel run and then you do not have to feed it and then mark can take all 3000 oranges to the market. Technically, it could be an answer because you said the camel walked.

Okay, I know that is also not the answer.

I did come up with an answer, but the truth is I do not have a formula on exactly how I did it. I started out with taking guesses on how far this camel should walk and how many he should carry and stop to drop some off to go back and get more. That made sense to me. I actually have 2 pages of writing. I figured the whole idea is to get as far as possible with as many as possible in as few trips as possible.
I came up with taking 1000 oranges 200 miles, drop off 600, then go back (eating the other 200 of course) x 2 = 1200 then going back a last time and picking up the remaining 1000 and stopping at that 200 miles which gives a total of 1200 + 800 = 2000 oranges. There is still 800 miles to go. This is where I had a problem. I took 800/3=267 rounded. So, take 1000/3=333. So, go 333 miles out, drop off 333 oranges and eat 333 oranges back. Pick up the remaining 1000 oranges and go 333 miles. So now you have traveled 200 + 333 = 533 miles and have 333 + 1000 - 333 = 1000 oranges left. You still have 1000 - 533 = 467 miles left to travel so you can take 533 oranges to the market. Somewhere mark ate one because I cannot account for the extra one missing. Now there has to be a formula and a much simpler way to figure this out I just do not know it.

That is assuming I am even close to the right answer.