The worlds first riddle!

I think she must be talking about a free throw shooting contest. She is in Hoosier country, after all.

At least he's stopped picking up little girls.

We don't know that, he could be back at the Russian mart making his move right now. They have both suspiciously gone absent from the thread...

Let's have some more riddles! Hopefully no more that are identical to examples from my high school math book -- those aren't riddles.

i don't spell well win i'm mad so **** off.

i guess for you stupidity knows no bounds.

you tell 'em, yugi!!!!

Mark:


POPULATION
45125 (rounded to nearest integer)

P = 10000 * 2^((Y-1930)/23)





Since the population doubles every 23 years, the population at any one time can be expressed as:
POPULATION = 10,000 * 2^ (#Years/23)
So, for 1980, the # of Years is 50 and the formula becomes:
POPULATION = 10,000 * 2^ (50/23)
POPULATION = 10,000 * 2^ (2.173913043)
1980 POPULATION = 45,125.



Mark:

HALF-LIFE

78.9 days
H = 12 / (-log2(0.9))


Yup, thought so.



….Which can be changed to:
2n=1.1111111111111...
Notice that the unknown is an exponent. When that is the case, we must solve by taking the logarithm of both sides of the equation which then becomes:
n * log(2)=log(1.1111111111)
n= log(1.11111111)/log(2)
n= .152003093
Since n represents the number of half-lives it has undergone in 12 days, this means that the half-life of the substance is 12 divided by .152003093 or 78.945days.




(Due to circumstances beyond my control my online time is somewhat limited. Normal service will return shortly.)



"At least he's stopped picking up little girls."

Don't pick on me just because I have a bad back from trying to bench press 300 pounds.
Thank you Stormy for your timely intervention on behalf of mirth.

"Wait till she finds out about your career as a porn film special effects engineer..."

Now you have done it, I told Stormy I was a plastic surgeon and could give her a complete makeover!

In an effort to dispel any rumours of A Moscow connection I will hopefully be able to have the Godfather say a few words on my behalf. In the meantime…




What is the probability that 7 people chosen at random would have been born on a different day of the week

(That is to say, 1 born on Sunday, 1 on Monday, etc.)






There is a Bridge in New York City that spans 4,260 feet between 2 towers which are each 690 feet tall.

To allow for the curvature of the Earth, how much further apart must the tops of the towers be from the distance at the bottom of the towers


Note: An EXTREMELY precise (and involved) answer can be obtained by using trigonometry, double angle formulas, etc. However a VERY good approximation can be obtained if you remember that; The radius of the Earth is 4,000 miles.

DAYS OF THE WEEK:

[size=7]

1*6/7*5/7*4/7*3/7*2/7*1/7 = 0.00612

[/size]

BRIDGE:

[size=7]

s = r*theta

on the surface:
s1 = r1*theta
4260 ft = 4000*5280*theta
theta = 4260/(4000*5280) = 2.017E-4

at the bridge level:
s2 = r2*theta
s2 = (4000*5280+690)*4260/(4000*5280) = 4260.139

Difference = s2-s1 = 4260.139 - 4260 = 0.1392 ft[/size]

WEEK
1 / C(13,6) = 1/1716 = 0.00058275

BRIDGE
r = 4000 * 5280
delta = 690 * 4260 / r = .139 ft.

She knows how to spell ****.

I retract this answer. C(13,6) is the number of ways to distribute the seven people among the seven days, but they are not equiprobable. I agree with stuh505's answer.

you know what? i really don't care any more. bye-bye.

Who will solve our riddles now?

Here's a more challenging 'riddle' -- how many solutions are there to the digit riddle? (I don't know the answer, at least not yet)

hmm... I think I know.

I have a jar that contains quarters, dimes and nickels totalling $12.90.
These are tips from my evening job as a bus-boy.

The total number of coins in the jar is 127 and there are 3 times as many dimes as there are nickels.

How many quarters, dimes and nickels are there

I'll get back to you on that. Right now, I got to go. but i got to ask. Who give change out as a tip? Either give me dollars or leave. (HINT HINT)

Well being the mathematical moron that I am, I'm not much good on the riddles thread. I'll have stick to word games.

Try hope your online time is sorted soon....this doesn't mean my plastic surgery makeover is off now does it

[quote="stuh505how many solutions are there to the digit riddle?[/quote]

If it's the ## * # = ## + ## = ## problem I posted several pages back, I already answered Try's question about uniqueness.