The worlds first riddle!

heartache, headache

tennis: it's got love (zero) in it

Could it possibly be: ACRES, CARES, RACES, SCARE ?

[size=8]GUM BALLS
There are zero gun balls.
The number of gum balls could be:
1 red, 1 blue, 3 yellow
2 red, 2 blue, 2 yellow
3 red, 3 blue, 1 yellow

BEAR
Are you sure it wasn't a penguin?[/size]

Mark:

Could it possibly be: ACRES, CARES, RACES, SCARE

Quiet possibly :wink:


GUM BALLS
There are zero gun balls. (Cute)

The number of gum balls could be:
1 red, 1 blue, 3 yellow
2 red, 2 blue, 2 yellow
3 red, 3 blue, 1 yellow


(Even cuter)
I had it as; 2 red, 2 blue, 2 yellow. However, I take your point.

BEAR
Are you sure it wasn't a penguin?

The directions are true, only if it happened in the North Pole. Therefore, the color of the bear is - white.

I hope you and Shari had a good time in Chicago, perhaps now you will believe me that the A2K meeting was last month.


"What" said Shari is the least value of 3x + 4y if x2y3 = 6



What day of the week was January 12, 1979



A garrison of 3300 men has provisions for 32 days, when given at a rate of 850 grams per head. At the end of 7 days a reinforcement arrives and it was found that now the provisions will last 8 days less, when given at the rate of 825 grams per head.

How, many more men can it feed

Try: Congratulations on hitting 5000. You've been a busy boy lately. The missus must be having to go elsewhere for satisfaction. :wink:

"The directions are true, only if it happened in the North Pole." Hmmm.
Different question: Given those directions, what is the probability that their starting point was within 2000 miles of a bear?

[size=8]CALENDAR
Friday

PROVISIONS
The reinforcement consisted of 1700 men.

LEAST VALUE
If the problem is to find the least value of 3*x + 4*y such that (x^2)*(y^3)=6, then there is no minimum.

As y approaches zero from above, x=-sqrt(6/(y^3)) approaches negative infinity.[/size]

Tie me to a hog and call her Daisy May, I credited Mark with:

"Could it possibly be: ACRES, CARES, RACES, SCARE?"

When in fact all the kudos belongs to our very own centrefold babe; Butterfly.

Please accept my apologies for this gross oversight, you are absolutely correct.
A mark will be deducted from Marks mark. I thank the management for bringing this miscarriage of justice to my attention.


Butterfly walks 5/6 of her usual rate, and is 40 minutes late. What is the usual time for her trip

You didn't answer my bear question.

LEAST VALUE
if 3x=10, then as y approaches negative infinity, 3x+4y approaches negative infinity. I think we should bury this one.

BALLS
Set aside one green and one blue. There are now 5 choices for green (0-4), 4 choices for blue (0-3), and 4 choices for red (0-3). Therefore, the total is 5*4*4 = 80.

PIPES
167 minutes (reminds me of snails and wells)

LATE BUTTERFLY
240 minutes

Mark:

You didn't answer my bear question.

"Given those directions, (They walk 10 km south, then 10 km east. Then they walk 10 km north and get back at their camp, exactly where they left.) What is the probability that their starting point was within 2000 miles of a bear?"


Actually, the bear could go west two or five kilometers and it would not make any difference -- the bear would be making a circle around the North Pole. East and West you travel along parallels which are circles equidistant from the poles. North and South you travel along meridians which are circles that cross both the north and the south poles.

There is another way to go south, west and north one kilometer and end up at the original point without starting at the North Pole*. Start 1 + 1/(2π) kilometers (approx. 1.16Km) from the South Pole. Walk one kilometer south, then one kilometer west (which is a 1 Km circle around the South Pole), and finally, one kilometer north to the starting point. However, there are no bears in Antarctica; there are only penguins.

I seem to remember you gave the definitive answer to a similar question some time back. I was so impressed that I made a copy, unfortunately that is at another office. However, I am sure you would not mind enlightening us.




LEAST VALUE
if 3x=10, then as y approaches negative infinity, 3x+4y approaches negative infinity. I think we should bury this one.
(good idea, along with a few others)

BALLS
Set aside one green and one blue. There are now 5 choices for green (0-4), 4 choices for blue (0-3), and 4 choices for red (0-3). Therefore, the total is 5*4*4 = 80.

I have, wait for it…3720. This made perfect sense at the time, but then, so does your answer.

PIPES
167 minutes (reminds me of snails and wells)

Exactly.

LATE BUTTERFLY
240 minutes



Of the words listed below, one is "odd man out." This has
nothing to do with the number of vowels, consonants or
syllables.

Can you find the misfit

LUMP REAM SAGA PALM




I am just a small letter, you see,
As irrational as I can be,
Though it sounds quite insane,
When I'm squared, you'll obtain,
The negative of little me.

What am I



What has six faces
But does not wear makeup.
It also has twenty-one eyes,
But cannot see

DIRECTIONS
Assuming each possible starting position is equally likely to be chosen, the probablility of being within 2000 miles of a bear is zero. There are an infinite number of starting locations near the south pole - only one at the north pole.

[size=8]ODD MAN OUT
How about ream? It's the only one that doesn't form a word when the last letter is removed.

6 FACES, 21 EYES
a die

SMALL LETTER
Hmmm. 0 and -1 satisfy the last two lines, but not the first two.[/size]

Hi Try,

Lump / Plum
Ream / Mare
Palm / Lamp

'Saga' is the only one of the four words that I couldn't make into an anagram.
Regards, Butterfly

Goliath's challenger...

yoyo

Francis:

Goliath's challenger...

(His cryptic answer is better than the riddle)

DAVID (Roman numerals)

... David offers to go and fight the Philistine challenger Goliath. ... After knocking Goliath down, David uses Goliath's own sword to kill and behead him. ...

Francis mon ami, you are so quick, the ink was hardly dry.




Mark:

"That was the first thing I considered, but i^2 does not equal -i."

(That is a riddle! You do the math, I will do the jokes)




"I have joy in bringing two together, But darn my existence!
My life hangs by a thread, and is filled with ups and downs."


(Join + darn + thread = Sewing Machine)



As a whole, I am both safe and secure.
Behead me, and I become a place of work.
Behead me again, and I am the partner of ready.
Restore me, and I become the domain of beasts.

What am I



What two words, formed from different arrangements of the
same six letters, can be used to complete the sentence below?

"Judging from its climate records, Murmansk may be one of the ------ ------ in the world."




In June, a baseball team that played 60 games had won 30% of its games. After a phenomenal winning streak, this team raised its average to 50%.

How many games must the team have won in a row to attain this average

[size=8]WHAT AM I
stable

ANAGRAM
iciest cities

WINNING STREAK
24[/size]

With Mark's quick reply, it looks like the joke is on me.

Therefore, I am forced to release the hounds of hell on this the 060606


1. All G's are H's
2. All G's are J's or K's
3. All J's and K's are G's
4. All L's are K's
5. All N's are M's
6. No M's are G's


i) If no P's are K's, which of the following must be true

(a) All P's are J's (b) No P is a G (c) No P is an H
(d) If any P is an H it is a G (e) If any P is a G it is a J

ii) Which of the following can be logically deduced from the conditions stated

(a) No M's are H's (b) No M's that are not N's are H's
c) No H's are M's (d) Some M's are H's (e) All M's are H's


iii) Which of the following is inconsistent with one or more of the conditions

(a) All H's are G's (b) All H's that are not G's are M's
(c) Some H's are both M's and G's (d) No M's are H's (e) All M's are H's


iv) The statement "No L's are J's" is


I. Logically deducible from the conditions stated
II. Consistent with but not deducible from the conditions stated
III. Deducible from the stated conditions together with the additional statement "No J's are K's"

(a) I only (b) II only (c) III only (d) II and III only (e) Neither I, II nor III