The worlds first riddle!

I've suddenly got a hankerin' for fruit salad.

Almost forgot...
Hi Patti. How long have you been with Try?

Mark:

30L = 30000cc
r = h = 10*(30/pi)^(1/3)
Since r=h, A = 3*pi*r^2 = 4242.14376 square centimetres

(That is so neat)



"How do Patti's pear of melons stack up against Shari's?"
Not in the same league.

"Almost forgot..."
Since when?


"I've suddenly got a hankerin' for fruit salad."

?'Fruit Salad' you say. Please be very careful:

"Three guys who were lost at sea ended up landing on an unfamiliar island. After wandering around for a while, a group of natives picked them up and took them to their hut. The chief came up to them and said, "We will let you live, if you can go out into the jungle and bring me 10 pieces of fruit." So the men agree and take off. The first guy brings back 10 apples and places them before the chief. "Now, you must stick the apples up your butt and not show a bit of emotion, or else we will kill you." The guy got one, and on the second, he flinched and was killed.

The second guy walks up and shows the chief 10 berries. He is given the same task and makes it up to 8 and then begins to laugh hysterically. He is also killed. When the second guy gets to heaven and meets up with the first, the first asks him "You almost had it! Why did you laugh??" The second replies, "I couldn't help it. I got the 8th up there and saw Mark walking up with pineapples!!!"


With reference to: ?'smeteltoumies' I could admit defeat, or you could extend the deadline 24 hours - Your call.



It may seem unbelievable, but government employees in China during the T'ang Dynasty (618-906 A.D.) had to take tests roughly equivalent to our present-day civil service examinations. The standard test for the arithmetic portion of the examination was prepared by the great Chinese Mathematician Hsia-Hou Yang. Here is one of the questions. Could you have passed this part of the government examination?


A farmer owned 18 k'o, 7 t'ow, 5 ho of rough and unprocessed rice.

[Note: A k'o, approximately equal to one bushel, was the equivalent of 10 t'ow or 100 ho.]

The farmer took his rice to the miller to be exchanged for processed and milled rice at the rate of 1 k'o, 6 t'ow of processed rice for each 3 k'o of rough rice.

How much processed rice did the farmer receive

[size=8]RICE
1875 * 160/300 = 1000[/size]

"With reference to: ?'smeteltoumies' I could admit defeat, or you could extend the deadline 24 hours - Your call."

Deadline extended indefinitely.
Big hint: The proper noun is the name of a city.

[size=8]ESCALATOR
100 steps[/size]

7 t'ow and 5 ho is .75 k'o which gives the farmer 18.75 k'o
18.75/3 = 6.25
6.25*1.6 = 10 (k'o)

The whole decimal thing is niggling at me because it seems such an obvious answer...

Mark:


ESCALATOR
100 steps


Let v be the speed of the escalator, in steps per second. Let L be the number of steps that you need to take when the escalator stands still. Upwards (along with the escalator), you walk 1 step per second. You need 50 steps, so that takes 50 seconds. This gives: L - 50 × v = 50. Downwards (against the direction of the escalator), you walk 5 steps per second. You need 125 steps, so that takes 25 seconds. This gives: L + 25 × v = 125. From the two equations follows: L = 100, v = 1. When the escalator stands still, you need 100 steps.

(Thanks to Mark my big book of unanswered questions remains empty)


RICE
1875 * 160/300 = 1000

(Mark, you can always join us at the Imperial Court)



The farmer received 1,000 ho or 10 k'o of processed rice.
To simplify the computation, convert all units to ho.
The desired amount of rice = 1,875 / 300 x 160 = 1,000 ho, which is equivalent to 10 k'o.

You can set up a proportion:
1875 / x = 300 / 160
Solving for x, you get x = 1,000 ho.



How! YoungBull. Welcome to A2K and the Riddles Forum. You have succeeded where many have failed, I hope you stick around and enjoy yourself.

7 t'ow and 5 ho is .75 k'o which gives the farmer 18.75 k'o
18.75/3 = 6.25
6.25*1.6 = 10 (k'o)

Proving, there are many ways to skin a buffalo.



According to the Barbie web site, "This one doll is a $1.9 billion a year industry, with two Barbie's being bought every second."

What is the average cost of one Barbie, given the information above

[size=8]BARBIE
$30.10

That seems high. The $1.9B surely includes accessories.[/size]

Mark:

A.K.A. BARBIE
$30.10

There are 3,600 seconds x 24 hours x 365.25 days per year = 31,557,600 seconds in an average year. If two Barbies are sold every second, then 63,115,200 Barbie dolls are sold annually. This works out to an average cost of 1,900,000,000 / 63,115,200 = $30.10 each.

"That seems high. The $1.9B surely includes accessories."

(We do not wish to know how much you spend on accessories, thank you)



Several schools competed in a cross country meet. Each team sent three participants.

Shari, Katelyn, and Jessica were the three representatives for Harvard. Shari finished the race in the middle position, Katelyn finished after Shari in 19th position, and Jessica finished 28th.

How many schools took part in the race

[size=8]CROSS COUNTRY
The total number of entrants must be an odd multiple of 3, greater than 28, and less than 37.
Eleven schools participated. Shari finished 17th.[/size]

What's the smallest palindromic prime number with an even number of digits greater than 11?

Mark:


CROSS COUNTRY
The total number of entrants must be an odd multiple of 3, greater than 28, and less than 37.
Eleven schools participated. Shari finished 17th.


As Shari finished in middle position we know that there must be an odd number of runners in the race, but because there are three girls representing each school, the number of runners must be an odd multiple of three.
In addition, we know that Jessica, who finished 28th, was not last, as there is an odd number of runners. Therefore, there must be at least 29 runners.

If there were 33 runners, the middle position would be 17th.
If there were 39 runners, the middle position would be 20th.
However, we are told that Katelyn, who finished 19th, finished after Shari.
Hence there must have been 33 runners in the race and we deduce that eleven schools must have taken part.




Take a long rope; tie it to the bottom of the goal post at one end of a football field. Then run it across the length of the field (120 yards) to a goal post at the other end.
Stretch it tightly, and then tie it to the bottom of that goal post, so that it lies flat against the ground.
Now suppose that I add just 1 foot of slack to the rope, so that now I can lift it off the ground at the 50-yard line. How high can I lift it up

I think you were trying to catch me out, to see if I answered 1111. Well!


The first four digit palindrome is 1001 which is divisible by 11.
The next four digit palindrome is 1111, which is also divisible by 11 and is 110 bigger than 1001. 110 is important, because not only is it divisible by 11, but every four digit palindrome is x(1001) + y(110), where x is any integer from 1 to 9, and y is any integer from 0 to 9.



Now I am sure you know how it is, we were enjoying a discussion about how we were robbed at the Super Bowl, when all of a sudden Shari asks:

What is the smallest number with multiplicative persistence of 11?

Luckily, I knew the answer and was rewarded with a fine pear .

How about y'all

[size=8]LONG ROPE
You could probably lift it about 8 feet (depends on how tall you are). It can be lifted 13.4257 feet.[/size]

PALINDROMIC PRIME
Are you saying it contains at least six digits?

[size=8]SUPER BOWL
277777788888899[/size]

PALINDROMIC PRIME
"Are you saying it contains at least six digits?"


No, the first four-digit palindrome is 1001




What may I ask is the smallest number (besides 1) which is one less than twice it's reverse

But 1001 is not prime.

[size=8]REVERSE * 2 - 1
73[/size]

"What's the smallest palindromic prime number with an even number of digits greater than 11?"

1001


"But 1001 is not prime."


Ok! Lets review the rules:

a) Smallest
b) Palindromic
c) Even number of digits
d) Greater than 11


I replied : 1001

This only violated rules a > c.



You, kindly pointed out, "But 1001 is not prime." Which should have been obvious to all but the terminally stupid.

I have therefore reviewed my answer in consultation with my shrink, and it would appear a ?'typo' is to blame.
The answer should have read:


Palindromic prime in base 2

111011010111


In conclusion, may I say what I thought was a five second answer took far longer due to your restrictions. You Sir, are trickier than a sack full of Pole Cats.




Perhaps, you could assist me in:

What is the largest ?'proven' palindromic prime


(The number of decimal digits would be sufficient)

Bookmark.

Welcome Butterfly , are you related to Mark?

Let me restate the question:

What's the smallest palindromic prime number (base 10) greater than 11 with an even number of digits?