The worlds first riddle!

Mark:

CLOCK HANDS
11/12 times per hour /


Sorry Ralph:

The answer is every 60/55 hours, or every 1 hour, 5 minutes, and 27+3/11 seconds.

a) Let both hands be at 12. It will take the hour hand 1 hour to return to where the minute hand started. However at that time the minute hand will have advanced 1/12 of an hour. When the hour hand gets there the minute hand will have advanced (1/12)^2 or an hour. When the hour hand gets there the minute hand will have advanced (1/12)^3 or an hour.

So the total distance the hour hand will cover until it reaches the minute hand is the sum for i= 0 to infinite of (1/12)^i. Everyone should know that the infinite series for x^i, where x<1 and i from 0 to infinity is 1/(1-x). In this case the answer is 1/(1-1/12) = 1/(11/12) = 12/11 = 65.45 minutes.

b) Let both hands be at 12. Over the next 12 hours they will cross 11 times. Thus they cross every 12/11 hours.



PCRAYIINGN
crying in pain


the RCAANDILEN
candle in the rain


IRWAARQ
war in Iraq

DCOOUNWTN
counting down

SIEGNHDT
end in sight




The world's hardest riddle:


I can tune a piano, but I can't tuna fish!

Who am I




What is the most pieces you can form with n cuts of a pizza

Here's a twist I came up with:

I can't tune a piano, but I can tuna fish.

Who am I?

You must know your scales then!

REO Speedwagon [/color]




sidesidestory

storysideside

side
story
side

Ralph cryptogram.


[size=7]Two sides to every story[/size]

Nice one, lets have more.




DWSAELTY


JGUAILITYL




Answer to World hardest riddle: (Hex) ~


%6e%6f%74%68%69%6e%67

[size=8]PIZZA CUTS
(n^2 + n) / 2 + 1

guilty in jail[/size]


I can't tune a piano, but I can tuna fish.
Starkist - they can (put into a can) tuna fish.

hohouussee

This is driving me krazey, the medical bills are coming your way!

It didn't turn out the way I wanted but you can call it a house inside a house or a house behind a house.

I have to work on some of these sorry guys

m......e


l........a




l.......m


a.......e





a.......l



e.......m

"…you can call it a house inside a house…"

Ralph, you gotta stay outta the sun.

m......e


l........a




l.......m


a.......e





a.......l



e.......m



[size=7]Three square meals [/size]



AJBOOKUET

[size=8]joking about[/size]

3 square meals.....

a) "I can tune a piano, but I can't tuna fish!
Who am I"

b) "I can't tune a piano, but I can tuna fish.

Who am I?"

Ralph: REO Speedwagon
(Do enlighten us partner)

Mark: I can't tune a piano, but I can tuna fish.
Starkist - they can (put into a can) tuna fish.

(That has got to be a winner!)

Mark:
PIZZA CUTS
(n^2 + n) / 2 + 1

With every cut, you should cut through every previous cut. As long as you keep doing this, you will always be able to do so again your next cut. The number of additional pieces formed on cut x will always be x. We all know that sum of all integers from 1 to n is n*(n+1)/2. So the sum of additional pieces cut will be n*(n+1)/2. Finally add 1 because we start with 1 piece: n*(n+1)/2 + 1.

JGUAILITYL
guilty in jail

AJBOOKUET
joking about




After updating my advising records this week, I have found that 54 of my advisees each have accumulated from 54 credit-hours to 100 credit-hours.

Can you explain why at least two of these 54 advisees must have the same number of accumulated credit-hours

(Assume that credit-hours accumulate in whole number increments.)




I am a type of pipe. My last five letters, when made plural, have been used to punish.


I am a mythical character. Remove my first three letters, then read me backward, & you have something that was discussed by a man whose name denotes a type of leader for singers.


I am the immature form of certain creatures. Remove my middle letter & you have something very hot.

REO speedwagon's album "you can tuna a piano but you cant tuna fish"

You win

[size=8]CREDIT HOURS
There are 54 people and only 47 pigeonholes to place them in (you were more generous than you needed to be with the number of people). Therefore, there must be at least one pigeonhole with more than one person.[/size]

Mark:

CREDIT HOURS
There are 54 people and only 47 pigeonholes to place them in. Therefore, there must be at least one pigeonhole with more than one person.



The range of values, from 54 to 100 credit-hours, spans 47 integer values: 54, 55, 56, ..., 98, 99, 100. The first 47 advisees may all have different numbers of accumulated credit-hours, but the 48th advisee is assured to match at least one of the first 47. This is justified by the pigeonhole principle.


"(you were more generous than you needed to be with the number of people)"

It is one of the burdens I am cursed with.



Replace a, b, and c in C(a,5) = C(5,b) + C(5,c) to illustrate Pascal's Formula


A relationship s(n) is described recursively as s(n) = 3*s(n-1) - 2n, with s(1) = 4.

What are the numerical values for s(2), s(3), and s(4)




LALAAMDP


HCEALTL

bridge
water