Why that Ship would be the USS Constitution--
Old Ironsides to those familiar with her. She's not a ship of the line like the Victory--just a frigate, but a big frigate that saw action against the Barbary pirates and engaged and whalloped the HMS Guerriere and Java during the unpleasantness of 1812-1815.
Cow eating constest.
[size=7]Let x be the amount of grass in an acre & y be the amount of grass an acre can grow in 10 days. so 5 cows eating 2 acres of grass in 10 days becomes
1*5=2x+1*2y
& 7 cows eating 3 acres of grass in 3 10 day periods is
3*7=3x+3*3y
solving for x and y becomes
x=1/4 & y=9/4
Let z be the number of 10 day periods
then 16 cows eating 7 acres of grass becomes
16z=7x+7zy
or
16z=7(1/4)+7(9/4)z
64z=7+63z
and z=7
so 16 cows can eat 7 acres of grass in 7- 10 day periods & 7-10 day periods is 70 days.[/size]
Rap
Rap, thank you for the name, I took the tour and they have done a fantastic job with the refit. Amazing history, enough to keep me occupied for days.
Shari, veterinarians the word over will look in wonder at your succinct answer.
1,000,000 air
123456789
US
<STRAWBERRY>
>cake<
Numerous
strawberry shortcake
millionaire
So my answer was that bad huh?
Look on the bright side, until Rap came along, yours was the closest answer.
However, you sure are hot with the other questions.
<T
I
M
E>
ab defg
Quack quack quack
Cluck cluck cluck
Book going
Gees I need to be tutored. I had my boss help me w/ that one and he was a math major back in college. The thing that threw him off was that you said everything was constant so if that was the case then why did you have to give 2 examples each with different rates of consumption?
<T
I
M
E>
ab defg
Long ttime no see
Quack quack quack
Cluck cluck cluck----Foul Play
Book going---Tickets please (alt No Tickee, No Laundree)
Rap
shari6905 wrote:Gees I need to be tutored. I had my boss help me w/ that one and he was a math major back in college. The thing that threw him off was that you said everything was constant so if that was the case then why did you have to give 2 examples each with different rates of consumption?
The areas (numbers of acres) were different--the grass regrowth rate per acre was the same. The constants were the grass consumption per cow and the grass growth rate per acre.
Rap
[size=8]going by the book
foul language[/size]
You put your pants on one leg at a time
Win or lose-but Ulose+ could be close but no cigar
Grabs (Feels) up
Wagon
[size=7]D=n0*π*d0 D=n1*π*d1
n0*π*d0==n1*π*d1
n0/n1=d1/d0=4.25/3.5=17/14
since 17 and 14 are relatively prime
17 revolutions of the smaller wheel is the same as 14 revolutions of the larger wheel
and
D=n0*π*d0=17*π*3.5=186.324 ft[/size]
Rap
[size=8]pair of pants
up for grabs
you win some, you lose some
WAGON
The number of revolutions will be 17 and 14 respectively; so the wagon travels 59.5*pi feet.[/size]
Four mathematicians have the following conversation:
Dadpad: I am insane.
Mark: I am pure.
Rap: I am applied.
Shari: I am sane.
Dadpad: Rap is pure.
Mark: Shari is insane.
Rap: Mark is applied.
Shari: Rap is sane.
You are also given that:
Pure mathematicians tell the truth about their beliefs.
Applied mathematicians lie about their beliefs.
Sane mathematicians beliefs are correct.
Insane mathematicians beliefs are incorrect.
Describe the four mathematicians
i i i i
o o o o
COORDERURT
IT
E
C
A
F
[size=8]order in the court
face up to it[/size]
Mathematicians
[size=7]Dadpad is applied and sane
Mark is pure and sane
Rap is pure and insane
Sari is applied and insane[/size]
[size=7]oivi pronounced oui vey
Order in the court
Face up to it[/size]
Rap
[size=7]Wheels
front wheels d*3.142=10.997
back wheels d*3.142=13.3535[/size]
A 10 ha forest is planted in rows. the rows are 4 m apart, the trees are planted 2.5 m apart along the row.
1. How many trees are planted?
[size=8]MATHEMATICIANS
Only an applied person would say, "I'm insane." Therefore, Dadpad is applied
Only a sane person would say, "I'm pure." Therefore, Mark is sane.
Only an insane person would say, "I'm applied." Therefore, Rap is insane.
Only a pure person would say, "I'm sane." Therefore, Shari is pure.
Since Rap is insane, and Shari is pure and said Rap is sane, Shari is insane.
Since Shari is insane, and Mark is sane and said Shari is insane, Mark is pure.
Since Mark is pure, and Rap is insane and said Mark is applied, Rap is pure.
Since Rap is pure, and Dadpad is applied and said Rap is pure, Dadpad is insane.
Dadpad: Applied/Insane
Mark: Pure/Sane
Rap: Pure/Insane
Shari: Pure/Insane
I seem to have fared quite well. Thank you. However, perhaps I'm insane and just think I fared well.[/size]
10 ha! What the hell is a ha--I'm a 'Merican' dunt no nutting bout the metric system--cept it was invented by Ben Franklin. Now a good patriotic 'Merican' acre is 43560ft^2!
The exact number is contingent upon the shape--because if I remember it right ha (like the patriotic 'Merican' acre) is an area tern--doesn't say anything about the shape, although I could take an educated guess---the footprint of each tree is 4m by 2.5m or 10m^2. 10ha (if I rememember that communist metric system right is 100 ha to a square kilometer) is 100,000 m^2--so you oughta be able to plant 10,000 trees--ignoring the edge effects.
If it were perfectly square, though--you should be able to cram another 160 trees onto the plot.
Rap
[size=8]TREES
Depends on the dimensions:
4m x 2500m = 2002 trees
8m x 1250m = 1503 trees
.
.
.
100m x 100m = 1066 trees[/size]
sorry i forgot about the metric stuff.
A hectare (ha) is 100 meters by 100 meters so 10 ha is 100 m by 1000 m
if my 100 m side is the base of my rectangle the sum is 100/4 (4meter row spacing. 100/4=25 rows
the row lengths are 1000m long (2.5m between trees) 1000/2.5=400
25*400=10,000 trees
I am interested in getting more trees if possible by changing the shape. Is this possible?
as an example if rap is correct 160 more trees would gross my client $3200 more.
If mark is correct 100mx100m= 1 ha=1066 trees per ha (not 1000 per ha as i have calculated) then I can make my client $13,200 more than I have told him. (1066x10ha=10660 trees)
If the lot shape is 100 by 1000 meters then start on the edge (no setback) of the property and plant to the edge of the property and you'll get another row of trees. The same can be done on the ends and you'll get another tree per row.
So number or rows (100/4)+1=26. Number of trees per row is (1000/2.5)+1=401, so theoretically you can get 10,426 trees. However, you would be seriously encroaching on your client's neighbors as (depending on the decision of the courts) the neighbors could own 3/4 of the four trees on the corners and 1/2 of the trees on the edges.
So for legal reasons you might short the spacing on the edges and ends slightly to keep from potentially encroaching on neighbors (minimal setback) and still get an extra 426 trees.
Rap
