The worlds first riddle!

Why that Ship would be the USS Constitution--Old Ironsides to those familiar with her. She's not a ship of the line like the Victory--just a frigate, but a big frigate that saw action against the Barbary pirates and engaged and whalloped the HMS Guerriere and Java during the unpleasantness of 1812-1815.

Cow eating constest.

[size=7]Let x be the amount of grass in an acre & y be the amount of grass an acre can grow in 10 days. so 5 cows eating 2 acres of grass in 10 days becomes
1*5=2x+1*2y
& 7 cows eating 3 acres of grass in 3 10 day periods is
3*7=3x+3*3y
solving for x and y becomes
x=1/4 & y=9/4
Let z be the number of 10 day periods
then 16 cows eating 7 acres of grass becomes
16z=7x+7zy
or
16z=7(1/4)+7(9/4)z
64z=7+63z
and z=7
so 16 cows can eat 7 acres of grass in 7- 10 day periods & 7-10 day periods is 70 days.[/size]

Rap

Rap, thank you for the name, I took the tour and they have done a fantastic job with the refit. Amazing history, enough to keep me occupied for days.

Shari, veterinarians the word over will look in wonder at your succinct answer.


1,000,000 air



123456789
US



<STRAWBERRY>
>cake<

Numerous
strawberry shortcake
millionaire

So my answer was that bad huh?

Look on the bright side, until Rap came along, yours was the closest answer.
However, you sure are hot with the other questions.

<T…I…M…E>
ab defg…


Quack quack quack
Cluck cluck cluck


Book going

Gees I need to be tutored. I had my boss help me w/ that one and he was a math major back in college. The thing that threw him off was that you said everything was constant so if that was the case then why did you have to give 2 examples each with different rates of consumption?

<T…I…M…E>
ab defg… Long ttime no see


Quack quack quack
Cluck cluck cluck----Foul Play


Book going---Tickets please (alt No Tickee, No Laundree)

Rap

The areas (numbers of acres) were different--the grass regrowth rate per acre was the same. The constants were the grass consumption per cow and the grass growth rate per acre.

Rap

[size=8]going by the book
foul language[/size]

Shari:

NV GREEN
green with envy


2222222
day
tuesday


+ EEEEE
mountains
Andies Mountains

1,000,000 air
millionaire

123456789
US
Numerous


<STRAWBERRY>
>cake<
strawberry shortcake

Totally awesome (that is a statement not a puzzle).

Shari honey cheer up. This is the riddles section and you need to think ?'out the box', the key is usually in the wording of the question, it takes time to tune in and avoid the curve ball. However, with Mark and Rap you have the very best in the business.



Rap:

Cow eating constest.

Let x be the amount of grass in an acre & y be the amount of grass an acre can grow in 10 days. so 5 cows eating 2 acres of grass in 10 days becomes
1*5=2x+1*2y
& 7 cows eating 3 acres of grass in 3 10 day periods is
3*7=3x+3*3y
solving for x and y becomes
x=1/4 & y=9/4
Let z be the number of 10 day periods
then 16 cows eating 7 acres of grass becomes
16z=7x+7zy
or
16z=7(1/4)+7(9/4)z
64z=7+63z
and z=7
so 16 cows can eat 7 acres of grass in 7- 10 day periods & 7-10 day periods is 70 days.



This just goes to show, you don't have to buy the whole cow if all you want is a glass of milk. :wink:

By the time the cows have eaten all the grass total grass consumed will equal total initial grass plus total grass re-growth. Next lets define some terms.
x=initial amount of grass in an acre.
y=amount of grass grown in one acre in one day.
Putting the given information in the form of equations we get:
50=2x+20y
210=3x+90y
To put the first equation in more simple English, 5 cows eating for 10 days results in a consumption of 50 units of grass. This is equal to the sum of 2x initial units of grass and 20y units of grass growth (10 days times 2 acres).
Next we must solve for x and y. Rewriting the above equations we get:
150=6x+60y (multiplying by 3)
420=6x+180y (multiplying by 2)
Subtracting the first equation from the second we get 270=120y, so y=9/4. Plugging this into either equation we get x=5/2.
The question to be answered is "How many days will it take 16 cows to eat 7 acres of grass?" Let's let d be the number of days. So setting this up as an equation we get.
16d=7x + 7dy
16d=35/2 + 63d/4
d/4=35/2
d=70.

Therefore, it will take 70 days for 16 cows to eat 7 acres of grass.

<T…I…M…E>
ab defg… Long time no see


Quack quack quack
Cluck cluck cluck----Foul Play


Mark:

Book going
going by the book

Quack quack quack
Cluck cluck cluck
foul language



PANTS
PANTS


UWIN+
ULOSE+


SSSS
BBBB
AAAA
RRRR
GGGG



Due to all this snow I thought that I had better git the old wagon outta the barn.

The front wheels measure 3.5 feet in diameter. The rear wheels measure 4.25 feet in diameter. While the wagon is stopped, a veterinarian worried about the abnormal load makes a chalk mark on both front and rear wheels.

How far must the wagon travel before both chalks marks return to their initial position at the same time

You put your pants on one leg at a time
Win or lose-but Ulose+ could be close but no cigar
Grabs (Feels) up

Wagon
[size=7]D=n0*π*d0 D=n1*π*d1
n0*π*d0==n1*π*d1
n0/n1=d1/d0=4.25/3.5=17/14
since 17 and 14 are relatively prime
17 revolutions of the smaller wheel is the same as 14 revolutions of the larger wheel
and
D=n0*π*d0=17*π*3.5=186.324 ft[/size]

Rap

[size=8]pair of pants
up for grabs
you win some, you lose some

WAGON
The number of revolutions will be 17 and 14 respectively; so the wagon travels 59.5*pi feet.[/size]

Four mathematicians have the following conversation:

Dadpad: I am insane.
Mark: I am pure.
Rap: I am applied.
Shari: I am sane.

Dadpad: Rap is pure.
Mark: Shari is insane.
Rap: Mark is applied.
Shari: Rap is sane.

You are also given that:


Pure mathematicians tell the truth about their beliefs.
Applied mathematicians lie about their beliefs.
Sane mathematicians beliefs are correct.
Insane mathematicians beliefs are incorrect.

Describe the four mathematicians



i i i i
o o o o



COORDERURT



IT

E
C
A
F

[size=8]order in the court
face up to it[/size]

Mathematicians
[size=7]Dadpad is applied and sane
Mark is pure and sane
Rap is pure and insane
Sari is applied and insane[/size]

[size=7]oivi pronounced oui vey

Order in the court

Face up to it[/size]

Rap

[size=7]Wheels
front wheels d*3.142=10.997
back wheels d*3.142=13.3535[/size]

A 10 ha forest is planted in rows. the rows are 4 m apart, the trees are planted 2.5 m apart along the row.

1. How many trees are planted?

[size=8]MATHEMATICIANS
Only an applied person would say, "I'm insane." Therefore, Dadpad is applied
Only a sane person would say, "I'm pure." Therefore, Mark is sane.
Only an insane person would say, "I'm applied." Therefore, Rap is insane.
Only a pure person would say, "I'm sane." Therefore, Shari is pure.

Since Rap is insane, and Shari is pure and said Rap is sane, Shari is insane.
Since Shari is insane, and Mark is sane and said Shari is insane, Mark is pure.
Since Mark is pure, and Rap is insane and said Mark is applied, Rap is pure.
Since Rap is pure, and Dadpad is applied and said Rap is pure, Dadpad is insane.

Dadpad: Applied/Insane
Mark: Pure/Sane
Rap: Pure/Insane
Shari: Pure/Insane

I seem to have fared quite well. Thank you. However, perhaps I'm insane and just think I fared well.[/size]

10 ha! What the hell is a ha--I'm a 'Merican' dunt no nutting bout the metric system--cept it was invented by Ben Franklin. Now a good patriotic 'Merican' acre is 43560ft^2!

The exact number is contingent upon the shape--because if I remember it right ha (like the patriotic 'Merican' acre) is an area tern--doesn't say anything about the shape, although I could take an educated guess---the footprint of each tree is 4m by 2.5m or 10m^2. 10ha (if I rememember that communist metric system right is 100 ha to a square kilometer) is 100,000 m^2--so you oughta be able to plant 10,000 trees--ignoring the edge effects.

If it were perfectly square, though--you should be able to cram another 160 trees onto the plot.

Rap

[size=8]TREES
Depends on the dimensions:
4m x 2500m = 2002 trees
8m x 1250m = 1503 trees
.
.
.
100m x 100m = 1066 trees[/size]

sorry i forgot about the metric stuff.

A hectare (ha) is 100 meters by 100 meters so 10 ha is 100 m by 1000 m

if my 100 m side is the base of my rectangle the sum is 100/4 (4meter row spacing. 100/4=25 rows

the row lengths are 1000m long (2.5m between trees) 1000/2.5=400

25*400=10,000 trees

I am interested in getting more trees if possible by changing the shape. Is this possible?

as an example if rap is correct 160 more trees would gross my client $3200 more.

If mark is correct 100mx100m= 1 ha=1066 trees per ha (not 1000 per ha as i have calculated) then I can make my client $13,200 more than I have told him. (1066x10ha=10660 trees)

If the lot shape is 100 by 1000 meters then start on the edge (no setback) of the property and plant to the edge of the property and you'll get another row of trees. The same can be done on the ends and you'll get another tree per row.

So number or rows (100/4)+1=26. Number of trees per row is (1000/2.5)+1=401, so theoretically you can get 10,426 trees. However, you would be seriously encroaching on your client's neighbors as (depending on the decision of the courts) the neighbors could own 3/4 of the four trees on the corners and 1/2 of the trees on the edges.

So for legal reasons you might short the spacing on the edges and ends slightly to keep from potentially encroaching on neighbors (minimal setback) and still get an extra 426 trees.

Rap