Mark:
Tripod
That is better than; 3 p's in a pod.
Take pets
Take a step back
TIME
Operator
Big time operator
AGES
I is 40, J is 30
90% of this problem is working through the wording into the form of an equation.
Let i be my age and j be the age of John. The first piece of information tells us...
i = 2*((i+j)/2 + (j-i)) + (j-i)
= 2*(3j-i)/2 + (j-i)
= 4j - 2i
= (4/3)*j
The second piece of information tells us...
j = (j+10)/2 + (i-j)
= i - j/2 + 5 = (2i+10)/3
Combining the two equations we get...
i = (4/3)*(2i+10)/3
= (4/9)*(2i+10)
= (8/9)*i + 40/9
= 40
So I am 40 (and John is 30).
My last half means 'impolite,' & I mean to 'stick out.'
protrude
I am the title of a movie. Remove my first two letters & you have the plural form of a parasitic insect
malice
I am a wanton leader from long ago. Remove my first letter & read me backward & you will find something that is mined
Nero
JCUASSET
I think he means just in case,

but case is in just.
Well spotted Mark, I am an idjot.
Rap:
Spider to the fly
Probability that 5 flies made it past the spider is P(5,0)(1/2)^5=1/32=1/32?-no flies eaten
Probability that 4 flies made is past the spider is P(5,1)(1/2)^5=5(1/32)=5/32?-1 fly eaten
Probability that 3 flies made it past the spider is P(5,2)(1/2)^5=10(1/32)=10/32?-2 flies eaten
Probability that the spider has eaten less than 3 flies (still hungry) is 1/32+5/32+10/32+16/32=1/2
and the probability that the spider is sated is 1-1/2=1/2
So the probability of the 6th fly making it past the spider is
(1/2)*1[spider not hungry]+(1/2)*(1/2)[spider still hungry]=1/2+1/4=3/4

/
It appears we agree.
Using the binomial distribution, the probability that n flies out of 5 have been eaten is combin(5,n)*(1/2)^5, where combin(5,2)=5!/(n!*(5-n)!).
The probability that 0 flies were eaten is combin(5,0)*(1/2)^5=1/32.
The probability that 1 fly was eaten is combin(5,1)*(1/2)^5=5/32.
The probability that 2 flies were eaten is combin(5,2)*(1/2)^5=10/32.
So the probability that the spider is still hungry is 1/32 + 5/32 + 10/32 = 16/32 = 1/2. The probability the spider is full is 1-1/2=1/2.
Thus the probability of a successful attempt to pass is (1/2)*1 + (1/2)*0.5 = 0.75
CALLEDCALLEDCALLED
COSENCHOSEN
CALLEDCALLED
CHOSEN
Many are called, one is chosen
"I've walked the decks of the Oldest Commissioned Warship Afloat."
As the victory is in dry dock, what is the name of said ship?
"Horatio Hornblower"
Fantastic read and fits in well with many of the threads in the History forum.
"what the pigeons do daily to Nelson's column."
Sorry to inform you but, the last time I was there the new mayor for London had got rid of them all. Have you checked it out with G@@gle Earth. It's as clear as being there.
You know who wrote, "I was tired of being you."
How do you think I feel after more than nineteen years!
"Where are you from, anyway?"
My life is an open book, it's just that all the pages are stuck together.
"You are very sneaky when it comes to personal info"
Such is the price of fame.
".......can you keep the peace for a day?"
That is a heck of thing to ask. However, as it's you - deal.
Cute pic, back attcha.
DP your answer, "What am I? ................... wheelbarrow "
Thanks, I did not get it.
NV GREEN
2222222
day
+ EEEEE
mountains
Five cows can eat two acres of grass in 10 days. Seven cows can eat three acres of grass in 30 days. The grass grows at a constant rate and each cow eats at a constant rate. The length of the grass before the cows begin grazing is constant.
How many days will it take 16 cows to eat seven acres of grass