The worlds first riddle!

[size=7]vi) 89 or rather 68
vii) 16,000 miles (or 9941 km). 24K*4/6=16K
viii) 6 minutes---6 cats,6rats,6min=>1 cat, 1 rat, 6 min=>10 cats, 10 rats, 6 min
ix) 1 & 41, 1 and 41 are both whole #'s and 41=1*41
x) too short---49.5m[/size]

Gus---only 25. Tragic he was so young.

Rap

Rap wrote, "Gus---only 25. Tragic he was so young."


Thank you for those kind words. Although he looked somewhat older - about 80 years. He was young at heart.

[size=7]I contend that 31 days is correct for (i). The 1st is one day frm the 2nd, two days from the 3rd, etc.

vi. ?
vii. Each tire was used for 16,000km, but traveled the full 24,000km.
viii. 6
ix. 1 and 41
x. Apparently the sales clerk knew the rule was short and took that into account since the first sentence says he bought 50m. Perhaps he only thought he bought 50m. In that case, he actually got 49.5m.[/size]

I think it was Mark's attorney who wrote, " I contend that 31 days is correct for (i). The 1st is one day frm the 2nd, two days from the 3rd, etc."

I hear what you are saying. However, as Rap says, "August 1st is a Wednesday, September 1st is a Saturday"

As the question asks, "How many days is it from…to…" 31 + 1 = 32


That said, you answered the question you saw, and that answer was correct. This being the season of goodwill, please accept a further 20 points, and 10c of your next burger.


I can't believe I said that! After all, if I waz to git me a tattoo, it would be a BIG Harley banner with the words, "Born to be bad ~
got sidetracked "


######################################################


VOUCHER

Please allow the bearer of this coupon a 10c reduction on his next burger.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Thanks. I'm afraid I didn't get you anything for xmas.

I'm going to make a ton of copies of the voucher. I'll never pay full price for a burger again.

Christmas Conundrums. Part III (payback)




xi. If there are 5 Mondays, 5 Tuesdays and 5 Wednesdays in January, on what day of the week will February 1st fall


xii. In a small group of people it was found that all of the following relationships could be claimed -

Father, mother, son, daughter, brother, sister, cousin, nephew, niece, uncle and aunt.

What is the smallest group of people that can manage this, and how must they be related


xiii. When cleaning up at the end of a picnic, three children found 21 drink-cans. 7 were full, 7 were half-full and 7 were empty.

The children agreed to share them out so that each of them should have the same number of cans and the same amount of drink.

How did they manage it

[size=7]xi) January has 31 days the fifth Monday, Tuesday, and Wednesday are three days 31-3=28 which is 4 weeks. So February 1st is a Thursday
xii) Four, Brother and Sister with son and Daughter respectively.
Brother, Uncle and Father with Son, Cousin, Nephew
Sister, Aunt, Sister with Daughter, Cousin, Niece
xiii) Kida A & B get 3 full, one half full and 3 empty. Kid C gets one full, 5 half full, and an empty. Each gets 3 1/2 cans of drink and 7 cans each.[/size]

Rap

[size=7]xi. Thursday
xii. no time
xiii. 3, 1, 3; 2, 3, 2; 2, 3, 2 (full, half, empty)[/size]

Happy Holidays! I'll be out until the 28th. We're heading down to Mexico for some warmer weather, and I'm not expecting to have Internet access there. I hope they accept my burger coupons. Maybe they'll work on a beef taco.

Rap:

xi) January has 31 days the fifth Monday, Tuesday, and Wednesday are three days 31-3=28 which is 4 weeks. So February 1st is a Thursday

xii) Four, Brother and Sister with son and Daughter respectively.
Brother, Uncle and Father with Son, Cousin, Nephew
Sister, Aunt, Sister with Daughter, Cousin, Niece Nice.

xiii) Kida A & B get 3 full, one half full and 3 empty. Kid C gets one full, 5 half full, and an empty. Each gets 3 1/2 cans of drink and 7 cans each.

Man, you are on fire.


Mark: (now departed)

xi. Thursday
xii. no time

xiii. 3, 1, 3; 2, 3, 2; 2, 3, 2 (full, half, empty)

I have the same answer as Rap, it looks like Mark has come up with another.



Christmas Conundrums. Part IV.5 (Revenge of the pith)



ivx. Find a number whose double is bigger than its half by 99


xv. A clock takes 5 seconds to strike six times. How long does it take to strike twelve times

xvi. Another clock takes 5 seconds to strike five times. How long does that clock take to strike ten times


xvii. Each letter in the original message has been substituted by some other letter.

LYCW ZQHNX FYZZ XYCN RYOBLW XBYX

What is the message

[size=7]ivx) 2x-x/2=99, x=66
xv) 6 chimes 5 seconds so tb=5/(6-1)sec=1 sec. 12 chimes=(12-1)*1sec=11 sec, 12 chimes-11 sec
xvi) 5 chimes, 5 seconds so tb=5/(5-1)sec=5/4 sec. 10 chimes=(10-1)*5/4sec=45/4 sec. 10 chimes-11 1/4 sec
xvii) LYCW ZQHNX FYZZ XYCN RYOBLW XBYX. I worked on this one for quite a while starting with XBYX---It's a conundrum.[/size]

I think there are several answers to the pop can problem.

Rap

Rap:

ivx) 2x-x/2=99, x=66
xv) 6 chimes 5 seconds so tb=5/(6-1)sec=1 sec. 12 chimes=(12-1)*1sec=11 sec, 12 chimes-11 sec
xvi) 5 chimes, 5 seconds so tb=5/(5-1)sec=5/4 sec. 10 chimes=(10-1)*5/4sec=45/4 sec. 10 chimes-11 1/4 sec
xvii) LYCW ZQHNX FYZZ XYCN RYOBLW XBYX. I worked on this one for quite a while starting with XBYX---It's a conundrum.

My dear Rap, it is not a conundrum, it is a bloody disaster. I have committed a grave sin by mistyping a code! It don't get much worse than that. It should have spelt out:
TINY LEAKS WILL SINK MIGHTY SHIPS

"I think there are several answers to the pop can problem."

I think you are right.


On a happier note, it has been pointed out to me that today, this decaying thread enters its third year.

Posted: Sat Dec 20, 2003 2:21 pm Post: 492467 - The worlds first riddle!

Congratulations to all contributors who have played a part in compiling what is surely the largest depository of riddles, puzzles and problems on the net. A2K rocks.



xviii. There are some sheep and geese in a field, and between them they possess 50 legs. If the sheep had had 2 legs each, and the geese had had 4 legs each there would have been 58 legs present.

How many sheep and geese are there


ixx. A number is halved and the result is squared. This gives an answer that is twice the size of the original number. What was the original number

[size=7]xviii) 11 geese and 7 sheep
ixx) the number is 8. 0 also works, but that may be a trivial case.[/size]

Three years ago I was a happy man.

Rap

…(this decaying thread enters its third year.)


"Three years ago I was a happy man."


Rap that is the funniest line you have ever written.
You have made my day.


xx. What two numbers, which when added together produce the same answer as when they are multiplied together - what


ixx. All except two of my pets are dogs.
All except two of my pets are rabbits.
All except two of my pets are fish.

How many pets must I have



I think the answer may be six squirrels

[size=7]xx) Two numbers
A+B=AB
if A & B are both odd, then A+B is even and AB is even, but if A&B are odd AB is Odd, so A&B cannot both be odd
if A is odd and B is even (or vice versa) the A+B is odd and AB must be odd. But id A is Odd and B is even AB is even, so neither A or B can be odd

This leaves A & B as even, and if they are even they are both divisible by 2. so A+B=2*[A|2]+2*[B|2}=2*{[A|2]+[B|2]} and AB=2*[A|2]*2*[B|2]=4*[A|2][B|2]
and since A+B=AB then 2*{[A|2]+[B|2]}=4*[A|2][B|2] and [A|2]+[B|2]=2*[A|2][B|2]
This can only occur if [A|2]=[B|2]=1 so 1+1=2*1*1
if [A|2]=1 then A=2 and if [B|2]=1 then B=2
so the two numbers are A=B=2

xxi) you got three pets on dog, one fish, one rabbit and if the dog is a beagle you'll soon be down to two pets. So get a cat for the dog, and you'll soon be down to two pets again.[/size]

Rap

Rap:

xviii) 11 geese and 7 sheep

ixx) the number is 8. 0 also works, but that may be a trivial case.

xx) Two numbers
A+B=AB
if A & B are both odd, then A+B is even and AB is even, but if A&B are odd AB is Odd, so A&B cannot both be odd
if A is odd and B is even (or vice versa) the A+B is odd and AB must be odd. But id A is Odd and B is even AB is even, so neither A or B can be odd

This leaves A & B as even, and if they are even they are both divisible by 2. so A+B=2*[A|2]+2*[B|2}=2*{[A|2]+[B|2]} and AB=2*[A|2]*2*[B|2]=4*[A|2][B|2]
and since A+B=AB then 2*{[A|2]+[B|2]}=4*[A|2][B|2] and [A|2]+[B|2]=2*[A|2][B|2]
This can only occur if [A|2]=[B|2]=1 so 1+1=2*1*1
if [A|2]=1 then A=2 and if [B|2]=1 then B=2
so the two numbers are A=B=2

That is the best answer - EVER!


xxi) you got three pets, one dog, one fish, one rabbit and if the dog is a beagle you'll soon be down to two pets. So get a cat for the dog, and you'll soon be down to two pets again.




xxii. A square lawn has a path 1 metre wide which goes around the outside of all the four edges. The area of the path is 40 square metres.

What is the area of the lawn


xxiii. Taking an exact number of strides I can walk 9.49 metres.
What is the length of my stride

[size=7]xxi) lawn. sidewalk side length is L. Lawn length is Lw. Sidewalk Area is given by L^2-Lw^2=(L+Lw)(L-Lw)=40 and since L-Lw=2 then L+Lw=20 so 2L=22 and L=11 & Lw=9.

The area of the lawn is A=Lw^2=9^2=81 m^2

xxii) Stride exact I'll assume means whole so 9.49 or in reality 949 has to be a composite number and it is cause 949=13*73. So I'll assume you aren't a midget and your stride isn't 13 cm and you took 73 of them, so you took 13 strides and it is 73cm. So the length of your stride is 0.73 m.[/size]


Rap

xxiv. Which is bigger - half a square metre or a half metre square


xxv. When my age is divided by 2, 3, 4 or 6 there is always a remainder of 1, but when divided by 7 there is no remainder.

How old am I

[size=7]xxiv) A half a square metre is twice the area of a half metre square.
xxv) 49 [/size]

Rap

hey everybody, sorry, i went on vacation, just a burden of holiday seasons