The worlds first riddle!

[size=7]TARAH
32

888333331111111[/size]

You find a note under your co-workers desk on which a message seems to be written in code. It reads: Abc'd ebbf ghi ibajckgldmkf qhdc nbcobbl hd. Bakpjnbcm.

You take it to your teenage son. He deciphers the secret alphabet except for one word that he keeps in code.

It reads: Let's keep our relationship just between us. Bakpjnbcm.

The curiosity is getting to you. Can you figure out the missing word

[size=7]NOTE
Hmmm.
Eli?abeth
I wonder what it could be...
That's a tough one. I give up.[/size]

Ok, ok:
You own a magazine stand. Last month, you sold 1134 magazines at an average price of $4.25 per magazine. You pay out a total of $1,530.00 in salaries to your two full-time employees, Mutt and Jeff, which constitutes 80% of your business expenses.

How much profit did you realize last month

[size=7]MAGAZINE STAND
$2907[/size]

Mark's right, 2907 bucks

4.25x1134=4819.5

1530x2=.8X when X=expenses
multiply by 2, divide by .8
=
1912.5

4819.5-1912.2=2907

Black stump thanks TA and my inlaws live in wagga.



I would be somewhat reluctant to answer

[size=7]NICK
$7

DP
12[/size]

ok, first of all, thats not so unbelieveable, considerring i can run one mile in 7:18, and long distance pace would probably be about a 10 min mile pace. but thats beside the point mark's right with both of them, with getting 7 bucks for the first one and 12 miles total for the second

give us somethin to think about, these are elementary..im not tryin to be a smart ass, or cocky, but i think mark would agree, GIVE US A CHALLENGE (that doesnt have to do with a dude walkin by 2 guys talking outside a cave that only a nobel prize winner that hasnt been found yet can solve)

[size=7]ECLIPSES
144/11 (or 13 1/11) months[/size]

Mark:

NICK
$7

(Divide your cost by the number of albums, 26.00 / 104 = $0.25 per album. Multiplying the 28 albums you want by the unit cost, 28 x $0.25 = $7.00).


DP
12

(Divide 9 miles by 1.5 hours for your average speed = 6mph. Divide your average speed by 2 for miles per ½ hour, 6mph / 2 = 3 miles per 30 minutes. Add the 3 miles to the 9 miles you ran, 9+3 =12 miles).


Nick confirms the numbers.


Mark:

ECLIPSES
144/11 (or 13 1/11) months /

(Congrats Mark)


The amount of time the red moon must travel for can be broken down into two parts:

1. the amount of time needed to complete one orbit
2. the additional amount of time needed to cover the distance achieved by the white moon.

The amount of time it would take the red moon to orbit the planet once would be twelve months. The amount of time it would take the red moon to cover the distance achieved by the white moon would be one twelfth of the time it took the white moon to do this, thus t/12.

As the white moon and the red moon will in fact have travelled for the same amount of time (just at different speeds), the time the red moon travels for (12 mos. + t/12) will be equal to the amount of time (t) for which the white moon has traveled. Thus we get the equation:

12 mos. + t/12 = t
Solving for t, we get: 144/11 (or 13.090909...) months.

The space below is reserved for Nick's answer.

"




"


What would be the first number in this series




You drop 4 coins in a well. One nickel, one quarter, and the other two are dimes. Using a special device, your friend is able to retrieve two coins from the well and tells you that one of the coins is a dime.

What are the chances that the other coin she took out is also a dime



What is the next number set in this idiosyncratic series:

Wsx edc rfv

[size=7]COINS IN A WELL
1/5[/size]

What's up with these sequences?

55 does that too....

COINS IN A WELL
There are C(4,2)=6 ways to select two of the coins:
D1D2
D1N
D1Q
D2N
D2Q
NQ
Five include at least one dime. Only one of those includes both dimes.

So does 99