34
   

The worlds first riddle!

 
 
markr
 
  1  
Reply Mon 11 Apr, 2005 01:43 pm
11) B
12) none of the above (x=-3/2)
15) A
16) B
0 Replies
 
markr
 
  1  
Reply Mon 11 Apr, 2005 01:58 pm
whimsical wrote:
I have taken Tryagain's riddle and wondered what would happen if you have four balls.


It can't be more than nine. The first two balls can each be dropped once to perform a binary search to narrow it down to 25 floors (assume they both break). That leaves the original problem with only 25 floors.

Since [7 * (7+1)] / 2 = 28 >= 25, it will take at most seven more drops.

So, nine is an upper bound.

Seven is the lower bound, since a binary search with as many balls as you need can be done in seven drops.
0 Replies
 
Tryagain
 
  1  
Reply Tue 12 Apr, 2005 10:37 am
0 Replies
 
turtlette
 
  1  
Reply Tue 12 Apr, 2005 12:10 pm
Void where prohibited and only while supplies last.
0 Replies
 
whimsical
 
  1  
Reply Tue 12 Apr, 2005 02:05 pm
Mark, what do you mean with a binary search?

Whim
0 Replies
 
markr
 
  1  
Reply Tue 12 Apr, 2005 03:15 pm
17) B
18) D
21) B
23) D
0 Replies
 
markr
 
  1  
Reply Tue 12 Apr, 2005 03:53 pm
whimsical wrote:
Mark, what do you mean with a binary search?

Whim


The technique for searching for an item in a sorted list:
1) Look at the middle element of the range
2a) If that element is what you're looking for, you're done.
2b) If that element is smaller than what you're looking for, the new range is from the next element to the end of the previous range. Go to step 1.
2c) If that element is larger than what you're looking for, the new range is from the first element of the previous range to previous element. Go to step 1.

The size of the search region is halved with each comparison.

For this problem, it will take at most ceiling(log2(N+1)) drops, where log2 is log base 2.
0 Replies
 
markr
 
  1  
Reply Wed 13 Apr, 2005 12:56 am
markr wrote:
whimsical wrote:
I have taken Tryagain's riddle and wondered what would happen if you have four balls.


It can't be more than nine. The first two balls can each be dropped once to perform a binary search to narrow it down to 25 floors (assume they both break). That leaves the original problem with only 25 floors.

Since [7 * (7+1)] / 2 = 28 >= 25, it will take at most seven more drops.

So, nine is an upper bound.

Seven is the lower bound, since a binary search with as many balls as you need can be done in seven drops.

Whim,
I sent you a spreadsheet that shows a solution in 8 drops. I think it also makes it obvious that 8 is as low as you can go with 4 balls.
0 Replies
 
whimsical
 
  1  
Reply Wed 13 Apr, 2005 06:24 am
Thanks Mark.

Whim
0 Replies
 
Tryagain
 
  1  
Reply Wed 13 Apr, 2005 09:53 am
Li'l Turtle wrote, "I heard she was having a crazy sale!"

I just love yard sales. I am on my way. Laughing

For those who've never been there, no explanation is possible....... For those who have, no explanation is needed..........

"Void where prohibited and only while supplies last." Shocked

Bring it on! Laughing


Mark, you are my hero. Laughing

17) B Cool
18) D Cool
21) B Cool
23) D Cool


17. (B) Team A can win in the following circumstances representing the order of wins after the first game: AA, ABA, ABBA, BAA, BBAA, BABA. These sequences of wins for A have probabilities [1/4], [1/8], [1/16], [1/8], [1/16], [1/16], respectively. Adding them provides the answer.

18. (D) Let the first number of the consecutive sequence be F, and let the last number be L. Then, if there are n numbers in the sequence, 75 = n[(F+L)/2] > 150 = n(F+L). Now n, F and L are positive integers and thus n divides 150 = 2×3×5×5. Thus possible values of n are 2,3,5,6,10,15,... The following table sets out the possibilities
n F+L SUM
2 75 37+38
2 50 24+25+26
5 30 13+14+15+16+17
6 25 10+11+12+13+14+15
10 15 3+4+5+....+10+11+12
For n = 15 or more F would be negative. Thus there are 5 possible values of n.

21. (B) Simplifying the expression we have 12a+12b = ab- ab-12a-12b+144 = 144- a(b-12)-12(b-12) = 144 - (a-12)(b-12) = 144. (The table will not reproduce)



The last in this file, thank goodness.


You are at a computer store which sells 3 computers: the Japanese one, which always answers any Yes-or-No question correctly, the Chinese one, which always answers any Yes-or-No question IN-correctly, and a Russian one, which sometimes tells the truth and sometimes lies - you never know.

You can ask one Yes-or-No question to any one of the three computers, after which you must buy any one of the three. You don't want the Russian computer, but each of the other two is okay. What can you do Question




N cars, each having a different speed, are going along a 1-lane road, so no passing is possible. Eventually, the cars will accumulate in packets, with the "fast" cars tailgating the "slow" ones. E.g., if the initial order was 1,5,2,4,3 (1 being the slowest, 5 being the fastest), we will end up with 3 packets: {1}, {5,2} and {4,3}. can you find the average number of packets as a function of N. Question




A family of 4 is trying to cross a bridge at night. One needs a flashlight to cross the bridge, and only two persons can cross the bridge at the same time, moving at the speed of the slower of the two. Father crosses the bridge in 1 minute, Mother in 2 minutes, Child in 5 minutes and Granny in 10. What is the fastest way for them to cross the bridge Question

The obvious solution is for F to always carry the flashlight back, i.e., FM+F+FC+F+FG which means 19 minutes (the notation means: first, F and M cross, then F carries the flashlight back, third, F and C cross together, fourth, F carries the flashlight back again, finally, F and G cross). Can you do faster Question

It is alleged that this is the standard problem given at an interview at M*soft.




Starting tomorrow HARDCORE RIDDLES.

Not for the faint hearted, or those on medication.

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If you read this far you must be a lawyer trying to find a loophole in this disclaimer, or you just cheated and checked the end to see what I added here. I should have put this in the middle somewhere. Be happy. Rock on.
0 Replies
 
markr
 
  1  
Reply Wed 13 Apr, 2005 01:26 pm
CARS
(N+1)/2

FLASHLIGHT
FM+F+CG+M+FM = 17
0 Replies
 
markr
 
  1  
Reply Wed 13 Apr, 2005 01:49 pm
COMPUTERS
Ask computer 1 if computer 2 is correct more often than computer 3. If the answer is no, pick computer 2. If the answer is yes, pick computer 3. Here are the possibilities:
Code:
1 2 3 response choice
---------------------
J C R N 2
J R C Y 3
C J R N 2
C R J Y 3
R J C Y/N 3/2
R C J Y/N 3/2
0 Replies
 
markr
 
  1  
Reply Wed 13 Apr, 2005 09:42 pm
Tryagain wrote:


Does that mean you're up there? North of Boston? How convenient!
0 Replies
 
markr
 
  1  
Reply Wed 13 Apr, 2005 09:45 pm
Tryagain wrote:
Starting tomorrow HARDCORE RIDDLES.

Not for the faint hearted, or those on medication.

MOTHER OF ALL DISCLAIMERS:
<snip>


"Not for the faint hearted." The riddles or the disclaimers? Shocked
0 Replies
 
Tryagain
 
  1  
Reply Thu 14 Apr, 2005 05:44 am
0 Replies
 
markr
 
  1  
Reply Thu 14 Apr, 2005 08:59 am
census: false
yes/no: false
standard deviation: true
impossible: true
median: false
0 Replies
 
Tryagain
 
  1  
Reply Fri 15 Apr, 2005 11:36 am
0 Replies
 
markr
 
  1  
Reply Fri 15 Apr, 2005 01:26 pm
1) 10
2) 32
3) 715 * 46 = 32890
4) 7 stickels

GOLD
46 bags
0 Replies
 
Tryagain
 
  1  
Reply Sat 16 Apr, 2005 07:08 am
0 Replies
 
markr
 
  1  
Reply Sat 16 Apr, 2005 11:06 am
RABBITS
5 jumps (5 5 5 5 -7)

DIVISORTON
389

SMALLEST NUMBER
59
0 Replies
 
 

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