The worlds first riddle!

VALLEY
137

You can always move down or to the right. Replace the letters with numbers that represent the number of paths down and to the right from that letter. Start by assigning 1 to the bottom and rightmost letters. Each of the others is the sum of the numbers immediately to the right and below. The final answer is the sum of the numbers on the left edge where the Vs were. It looks like this:

CHICKEN & EGG
Good joke!!!

CHANGE FOR A $50
I get 450

Francis, be assured you are on my good to know list.



Mark:
VALLEY
137

You can always move down or to the right. Replace the letters with numbers that represent the number of paths down and to the right from that letter. Start by assigning 1 to the bottom and rightmost letters. Each of the others is the sum of the numbers immediately to the right and below. The final answer is the sum of the numbers on the left edge where the Vs were.

What can I say; this was one of my best riddles. You are a one-guy answer factory.


Good joke!!!

Nice to see someone understood the punch line.


CHANGE FOR A $50
I get 450

That's strange, so do I. (ps7pm) :wink:




Determine the missing numbers in the following sequence of ordered pairs:


(1,3), (2,3), (3,5), (4,4), (5,4),
(6,3), (7,5), (8,_), (9,_), (10, _)



Find four distinct integers a,b,c,d such that
100 <= a,b,c,d <= 12000 and the sum of "all" the four of them
and the sum of "every" two of them are perfect squares.

(That is, a+b, a+c, a+d, b+c, b+d, c+d, and a+b+c+d are all
squares of integers.)


In this puzzle, you must turn MOOD into BARN by changing only one letter from the previous word.

M O O D
_ _ _ _
_ _ _ _
_ _ _ _

B A R N


Can you find the three missing words

ORDERED PAIRS
5, 4, 3 (an old one in disguise)

MOOD to BARN
moon - boon - born (these are fairly easy when the number of steps equals the number of letters that have to change)

Here's one to play with while waiting for the Super Bowl to start.

Determine the unique 9-digit integer M that has the following properties:
(1) its digits are all distinct and nonzero
(2) for every positive integer m = 2, 3, 4, ..., 9, the integer formed by the leftmost m digits of M is divisible by m.

For example if you had to do this with a 3-digit number, 123 would work because 12 is divisible by 2 and 123 is divisible by 3.

FOUR DISTINCT INTEGERS
386, 2114, 3970, 10430

That was a good one. It showed the worth of a spreadsheet!

Try: "Therefore, M = 381654729"
Right on!

CHAD & AMANDA
Chad: $0.50
Amanda: $3.50

1888
2888

LOTTERY
18 white balls and 35 powerballs gets you as close as possible to 300,000.

The number N consists of 1999 digits such that if each pair of consecutive digits in N
were viewed as a two-digit number, then that number would either be a multiple of 17 or a
multiple of 23. The sum of the digits of N is 9599. Determine the rightmost ten digits of N.

DrewDad: (Good to see you around)

1888
2888


In 1888, there were 13 characters:
MDCCCLXXXVIII

In 2888, there will be 14 characters:
MMDCCCLXXXVIII


Mark:
LOTTERY
18 white balls and 35 powerballs gets you as close as possible to 300,000.


The odds are calculated by computing the combination of the white balls taken 5 at a time, and then multiplying by the number of balls from which the Powerball is chosen.

For example, the odds for the original Powerball is figured in the following manner:
45 C 5 * 45 = 54,979,155
Likewise, the current Powerball odds:
49 C 5 * 42 = 80,089,128

After examining all combinations of balls up to 50, only one solution gives us odds of one in 300,000:
Use white balls numbered from 1 to 18, and choose the Powerball from balls numbered 1 to 35.
18 C 5 * 35 = 299,880

The next closest values are:
19 White balls, 26 for powerball: 19 C 5 * 26 = 302,328
24 White balls, 7 for powerball: 24 C 5 * 7 = 297,528
23 White balls, 9 for powerball: 23 C 5 * 9 = 302,841




Seven guests at a restaurant came,

The first every day,
The second every other day,
The third every third day,
and so on to the seventh who came once a week.


When will they all come to dine at the restaurant on the same day
(I.e. what is the smallest number of days?)


What is the lowest integral values for A, B, C, and D where:

A + B = C
A + D = B
2C = 3D
B > 0



Mark, your question, "…The sum of the digits of N is 9599. Determine the rightmost ten digits of N."

Will take some MIT processing power, I will call back later.

RESTAURANT:
7 * 4 * 3 * 1= 84 days till the next they're all there

INTEGRALS:
A=1
B=5
C=6
D=4

I wrote it down on a piece of paper to calculate, but can't really read it anymore.. lol

RESTAURANT
420 days (Liessa forgot 5)

INTEGRALS
same as Liessa

My 14 year old daughter can beat me, so I don't feel bad about Liessa beating me.

Liessa will finish the race 0.25 meters ahead of Mark.

Try: "Providentially, everybody knows that the answer is; 3469234685."


Let N = 111...1222...2, where there are 1999 digits of 1 followed by 1999 digits of 2.
Express N as the product of four integers, each of them greater than 1.

lol! I'm no runner, but thanks.

Darn, I read the Restaurant thing wrong... I hadn't seen "and so on"