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Standard deviation

 
 
Reply Wed 10 Mar, 2010 11:45 am
For a home emergency insurer the time taken from initial call for help to arrival of a tradesman is normally distributed with the parameters:

Mean no. of mins - 60
standard deviation - 10

Calculate the value of the probability that the time taken will be between 45 and 75??


I've got a figure of 82.2% but not sure its right!! My coursebook is a bit rubbish and implies the value of z can only be calculated at full z intervals, not half intervals, which is exactly what 45 and 75 is?

Thanks
 
JPB
 
  2  
Reply Wed 10 Mar, 2010 11:53 am
@PHIL5955,
I get 86.64%

Here's a better z table.
http://www.statsoft.com/textbook/distribution-tables/#z

You have 1.5 std deviations on either side of your mean. 1.5 std deviations = 43.32% of the area under the curve. Multiply by 2.
PHIL5955
 
  1  
Reply Wed 10 Mar, 2010 11:59 am
@JPB,
Thank you
JPB
 
  3  
Reply Wed 10 Mar, 2010 12:09 pm
@PHIL5955,
If the exercise is one of interpolation, however, and you were supposed to interpolate between Z=1 and Z=2 to get your result, then your answer is pretty close to the 81.85% that that method yields.
PHIL5955
 
  1  
Reply Wed 10 Mar, 2010 12:22 pm
@JPB,
Thanks for the comment, great help
JPB
 
  1  
Reply Wed 10 Mar, 2010 12:24 pm
@PHIL5955,
You're welcome.
0 Replies
 
oolongteasup
 
  1  
Reply Thu 11 Mar, 2010 02:03 am
@JPB,
http://www.fourmilab.ch/rpkp/experiments/analysis/zCalc.html

this z score calculator shows plus and minus z 1.5 is 86.64% amazing coincidence?
0 Replies
 
 

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