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Wed 10 Mar, 2010 11:45 am
For a home emergency insurer the time taken from initial call for help to arrival of a tradesman is normally distributed with the parameters:
Mean no. of mins - 60
standard deviation - 10
Calculate the value of the probability that the time taken will be between 45 and 75??
I've got a figure of 82.2% but not sure its right!! My coursebook is a bit rubbish and implies the value of z can only be calculated at full z intervals, not half intervals, which is exactly what 45 and 75 is?
Thanks
@PHIL5955,
I get 86.64%
Here's a better z table.
http://www.statsoft.com/textbook/distribution-tables/#z
You have 1.5 std deviations on either side of your mean. 1.5 std deviations = 43.32% of the area under the curve. Multiply by 2.
@PHIL5955,
If the exercise is one of interpolation, however, and you were supposed to interpolate between Z=1 and Z=2 to get your result, then your answer is pretty close to the 81.85% that that method yields.
@JPB,
Thanks for the comment, great help
@JPB,
http://www.fourmilab.ch/rpkp/experiments/analysis/zCalc.html
this z score calculator shows plus and minus z 1.5 is 86.64% amazing coincidence?