@armandok,
A is 1 hour, B is 2 hour, C is 3 hour
With probability function of six permutations of patient ABC, BAC,CAB,CBA, BCA,ACB (this is where it is discreet)
Prob function 1/6,1/3,1/2 (1,2,3) out of any 6 patients
ABC=1*1+2*2+3*3=14
BAC=1*2+2*1+3*3=13
CAB=1*3+2*1+3*2=11
CBA=1*3+2*2+3*1=10
BCA=1*2+2*3+3*1=11
ACB=1*1+2*3+3*2=13
Add em all up=14+13+11+10+11+13=14+2*13+2*11+10=24+26+22=72 hours total for all permutations.
As there are 6 permutations 72/6=12 hours spent on any 6 patients.
and 12/6=2 hr
Rap