I'm not sure what you mean with "assume a Standard Deviation of 0.497".
If the election was a toss up (50% chance for each vote), the expected standard deviation around that is sqrt(100x.50x.50) = 5, so 50 is well within one standard deviation of 52. If you want to compute it by hand, look up a z score of 2/5. If you want to use the Internet, use a favorite binomial calculator
and put in a probability of 0.5, 100 trials and 52 hits. The chance of getting 52 or more votes by chance is 39%. The chance of getting 520 votes out of 1000 by chance drops to 10.9%.