0
   

Is the Sun Round or Thin?

 
 
Reply Mon 30 Dec, 2019 02:46 am
When someone stays sationary relative to the sun, he will see that the sun is a round ball. When he moves to the sun in constant velocity (the sun moves to him relatively), he will see that the sun is an oval ball/thin due to the "length contraction effect" in the direction of movement.
The effect of gravity is even in all directions, so the sun is round; if the sun is thin, that means the effect of gravity is not even in all directions. Physics rule is not equivalent in different inertial frames? But one of the basic principle of SR is "physics rule is equivalent" in different inertial frames...



  • Topic Stats
  • Top Replies
  • Link to this Topic
Type: Discussion • Score: 0 • Views: 704 • Replies: 26
No top replies

 
fresco
 
  1  
Reply Mon 30 Dec, 2019 10:32 am
@htam9876,
You appear to be dabbling with speculative ontology and epistemology by playing with mathematical modelling. I suggest you bear in mind the philosophical quagmire involved with the words 'is' and 'reality', with respect to Nietzsche's point.... that all we ever have are descriptions which can only evaluated by their contextual utility, and not by comparison with a nebulous 'reality' concept.
maxdancona
 
  1  
Reply Mon 30 Dec, 2019 11:28 am
@fresco,
I think his problem is mathematical rather than philosophical. It is standard for physics students to solve problems in different reference frames.

The matgematics work in any reference frame.

0 Replies
 
htam9876
 
  0  
Reply Mon 30 Dec, 2019 05:50 pm
@htam9876,
The OP hints that the traditional Lorenzt transformation is not yet sufficient enough.
Below is the mass - space equation concept in X4 Theory:
The equation for the traditional Lorenzt transformation of length contraction is: L’ = L /γ
The mass – speed equation is M =γM0
Then, ML’ = M0L so, L’ = M0L / M
Because M0 and L are constants, then: L’ ∝ 1 / M. This might be called the “mass – space equation”.
Mass M is a scalar, so the equation reflects the contraction of size in all directions due to the increase of mass.
It seems that the “mass – space equation” is a derived one. But its components “mass” and “space” are most basic physical elements. Actually, it should be a more basic equation than the equation for the traditional Lorenzt transformation of length contraction and the mass – speed equation. It describes more basic natural rule.
During the course of exploration, people perhaps touch the leaves of a tree first, then the sticks, and so on the stock, at last the root. But for a tree, the root is the most basic.
From the angle of the physical substance of the object itself, perhaps the research might be more in depth and sufficient.
McGentrix
 
  0  
Reply Mon 30 Dec, 2019 10:31 pm
@htam9876,
Aren't you the OP?
maxdancona
 
  1  
Reply Mon 30 Dec, 2019 10:33 pm
@McGentrix,
I think this is another person trying to disprove science while being ignorant of science.

The concepts of frames of reference is tackled by advanced high school students. By the third semester, University students become adept at solving these problems in special relativity.

I havent seen any indication that the OP has taken even the first step.
htam9876
 
  0  
Reply Tue 7 Jan, 2020 05:29 pm
@McGentrix,
? Of course, htam9876 is the OP...
0 Replies
 
htam9876
 
  0  
Reply Tue 7 Jan, 2020 05:32 pm
@maxdancona,
Dear, I am used to be a bad student in school long long ago...
Now I even like to dig out the hidden flaws in textbooks...
0 Replies
 
htam9876
 
  0  
Reply Tue 7 Jan, 2020 05:38 pm
@htam9876,
I have configurated another thought experiment to verify the insufficiency of the traditional Lorentz transformation:

Current in Different Inertial Frames

Assume a part of stable DC circuit with the shape of “L” rests in inertial frame S: section 1 horizontal; section 2 vertical; wire cutting face is a square for convenience. (picture failed to upload)
Another inertial frame S’ moves rightward at velocity u.
The purpose of this thought experiment is to verify whether the “length contraction effect” is in all direction as the “mass – space equation” shows or just in the moving direction as traditional Lorentz transformation shows.

First, analysis resorts to traditional Lorentz transformation.
In frame S:
For section 1, I1 = n1qv1; for section 2, I2 = n2qv2
(Here take the moving direction of electron as the direction of current for convenience, n is the density of free electron in the wire, q is the charge carried by electron, v is the moving velocity of free electron.)
I1 = I2, n1 = n2 = n, v1 = v2 = v
In frame S’:
For section 1, △x’ = △x / γ (γ = 1 / √1 - u²/ c² ) , △y’ = △y , △z’ = △z
V’ = △x’△y’△z’ = △x△y△z / γ = V / γ , V’ is volume in frame S’, V is volume in frame S
So, n1’ = γn1 = γn
Lorentz transformation of velocity:
v1’ = (v1 - u) / (1 - u v1/c² )
I1’ = n1’qv1’ = γnq (v1 - u) / (1 - u v1/c²)
For section 2, also V’ = V / γ
So, n2’ = γn2 = γn
Lorentz transformation of velocity:
v2’ = v2 / γ(1 - u v1/c²)
I2’ = n2’qv2’ = γnq v2 / γ(1 - u v1/c²) = nq v2 / (1 - u v1/c²)
I1’ ≠ I2’
Physics rule is not equally applicable in inertial frame S’.
Next, resort to the space contraction in all directions which is disclosed by the “mass – space equation”.
In frame S’:
For section 1, n1’ = γ³n1 = γ³n
v1’ = dx’ / dt’ = (v1 - u) / (1 - u v1/c² )
I1’ = n1’qv1’ = γ³nq (v1 - u) / (1 - u v1/c²)
For section 2, n2’ = γ³n2 = γ³n
v2’ = dz’ / dt’ = dx’ / dt’ = (v1 - u) / (1 - u v1/c² )
I2’ = n2’qv2’ = γ³nq (v1 - u) / (1 - u v1/c²)
I1’ = I2’
Physics rule is equally applicable in inertial frame S’.

Li Qiang Chen
Jan 8, 2020
0 Replies
 
htam9876
 
  0  
Reply Fri 24 Jan, 2020 09:39 am
@htam9876,
他江门地方黑恶势力钟永康集团及新会一中九一四班全世界打靶啦。
0 Replies
 
htam9876
 
  0  
Reply Sun 26 Jan, 2020 04:03 pm
@htam9876,
Below I derive the mass – space equation from the microscopic angle. It concerns modeling, charge, particle physics, QM, etc. The course of derivation is long and complicated, but the result is very very simple. (content abstracted from X4 Theory 2020 Part 1)

X4 Theory of photon (Ⅲ)
X4 Model of Unit Electrical Charge

When we watch a spiral spring, we find that the chirality, left handed or right handed, is natural spacial property and will not change following movement / reference frames (Figure 5).

Figure 5

The concept of dimension should be continues and integral. Why this kind of natural spacial property seems to disappear down to microscopic scale? One solution might be that it reflects in the structure of basic particles.
Another question is that if a unified property existing in nature to judge “anti”, including charges?
A nonstandard model is initiated here in X4 Theory and have a try to solve these problems.
Let’s see the unit step function:
μ(t) = 0 (t<0) μ(t) = 1 (t>0)
It could be interpreted here as below:
Because t<0 meaningless, so the signal or the state of matter does not exist.
When t>0, the signal or the state of matter exist.
Next, play a mathematical game of “anti”…
With Fourier transformation (detailed calculation omitted), we got:

1 = (1/2) + (1/π)∫0→+∞(1/ω)sinωt dω
Then, replace variants, we got:
1 = (1/2) + (1/π)∫0→+∞(1/R)sinR P dR
Namely:
1 = (1/2) + (1/2) = (1/π)∫0→+∞(1/R)sinR P dR + (1/π)∫0→+∞(1/R)sinR P dR ①
And so on, we got:
-1 = -[(1/2) + (1/π)∫0→+∞(1/R)sinR P dR]
= (-1/2) + (-1/2) = (1/π)∫0→+∞(1/-R)sin(-R) P d(-R)+ (1/π)∫0→+∞(1/-R)sin(-R) P d(-R)
If we take R’ = -R, then
-1 = (-1/2) + (-1/2) = [(1/π)∫0→-∞(1/R’)sinR’ P dR’] + [(1/π)∫0→-∞(1/R’)sinR’ P dR’]
= [-(1/π)∫0→+∞(1/R’)sinR’ P dR’] + [-(1/π)∫0→+∞(1/R’)sinR’ P dR’] ②
And so on, we got:
0 = (1/2) + (-1/2) = (1/π)∫0→+∞(1/R)sinR P dR +[- (1/π)∫0→+∞(1/R’)sinR’ P dR’ ] ③
Note: in the final result of equation②, the value of R’ is positive too because it has changed to be in the anti 4D space. The equation of R’ = -R just reflects the contrast relationship of two contrast 4D spaces.

Next, let’s analyze the characteristics of equation①②③
⑴ In macro, it’s a scalar constant.
⑵ In micro, it has something to do with space R.
⑶ The value of the constant inverts following the inversion of the four dimensional space. And there is a case of neutrality.
⑷ According to the replacement of variant, P >0,and could be regarded as the magnitude of three dimension spacial momentum.
According to the integration area, R >0, and could be regarded as the four dimension space for a particle R = X4 r, X4> 0, r > 0, r is the distance (3D space) from the origin of the coordinate system.
And(1/R)sinR P could be regarded as the space part of a position space wave function in triangular form in 4D space. If we apply wave function in momentum space in 4D space, it will beΨ(P ) =(1/r)sinr P , it represents a wave function distribution field adjacent to the origin of coordinate system. The property of this field is not even. It ∝1/r. When the distance trends to infinite, the field trends to zero. While the distance trends to zero, the field trends to infinite.
And (1/π)∫0→+∞(1/r)sinr PdX represents the comprehensive result of the field.
The situation of R’ could be regarded similar but for an anti particle.
We see that equation①②③ are very similar in nature to one physical quantity, it’s point electrical charge.

Next, we just use them as the mathematical model for unit electrical charge (+e or –e) and electrical neutrality and analyze them a further step. We got:
(A) Unit electrical charge has deeper cause in it. The deeper structure of matter could be called layer here. The electrical charge of such layer is + (1/2)e or - (1/2)e, simple equivalent to (1/π)∫0→+∞(1/R)sinR P dR or -(1/π)∫0→+∞(1/R’)sinR’ P dR’. Value inverted following the inversion of the four dimensional space R.
(B) Because the two wave function distribution fields:
(1/R)sinR P and(1/R)sinR P in case of equation①,
(1/R’)sinR’ P and(1/R’)sinR’ P in case of equation②,
(1/R)sinR P and (1/R’)sinR’ P in case of equation③,
Have the same origin of coordinate system in the respective case, and because only one direction is analyzed here, in fact, all direction should be the same situation,
So, the ideal Geometrical shape of layers in any case of equation①②③ should be concentric circle kind in any normal cutting plane of a sphere.
(C) Layers in any case of equation①②③ might be the two aspects of one thing naturally.
(D) We can’t exclude a very special case:there is a kind of layer which has no space inversion effect( namely 0 = 0 + 0). Of course, it will be electrical neutral.

Next, analyze what specific physical structure could realize the conditions mentioned above from (A) to (D).
We think about circle kind of electromagnetic standing wave in any normal cutting plane of a sphere.
It’s two aspects (two travelling waves go in opposite direction) of one thing (the standing wave).
And we got the important character of layer: No alone layer exists in nature. Layers which construct a basic particle could not be separated by means of collision. There seems to be a strong force constraining that two lays but in fact that strong force is just a false impression.

We check out the ordinary standing wave function:
Y =(2Acos2πx/λ)cos2πγt
It’s an even function and has no space inversion effect.

We consider the track of the standing wave:
If the track is a smooth circle, its shape is too simple. Look at a smooth circle in the XY plane. The parametric equation is:
X = r cosθ Y = r sinθ Z = 0
If space inverted θ= -θ’ then:
X = r cosθ’ Y = - r sinθ’ Z = 0
That’s another smooth circle in the XY plane which derived from reflection of the original circle against X axis and in fact is the copy. No space inversion effect too. We put it aside temporarily.

If the track is a helical line, it has chirality, left handed or right handed(called natural identification of space here).

Look at the parametric equation of a helical line:

X = r cosθ Y = r sinθ Z = kθ
If space inverted θ= -θ’ then:
X = r cosθ’ Y = - r sinθ’ Z = - kθ’

The chirality inverted.
Then the specific physical forms of that circle kind standing wave could be:
(Ⅰ) Superposition of two right handed helical circle kind travelling waves go in opposite direction, namely, Superposition of two right handed layers.
(Ⅱ) Superposition of two left handed helical circle kind travelling waves go in opposite direction, namely, Superposition of two left handed layers.
(Ⅲ) Superposition of one right handed helical circle kind travelling wave and one left handed helical circle kind travelling wave go in opposite direction, namely, Superposition of one right handed and one left handed layers.

If we artificially define situation(Ⅰ) as basic particle with positive unit electrical charge, then, situation (Ⅱ) would be basic anti particle with negative unit electrical charge. Namely, “anti” is just relative. Situation(Ⅲ) would be basic neutral particle with electrical neutrality.
Now, consider the track of a smooth circle mentioned above again. It would be:
(Ⅳ) Superposition of two circular travelling waves go in opposite direction, namely, Superposition of two neutral layers. It would also be basic neutral particle with electrical neutrality.

At this moment, we can talk about the micro standard for the determination of some X4 states:
If we define basic particle made up of two right handed layers as in the state of X4 = +1, then, basic particle made up of two left handed layers will be in the state of X4 = -1, namely, the anti particle. Namely, “anti” is just relative. Basic particle made up of one right handed layer and one left handed layer will be in the superposition states of X4 = +1 and X4 = -1. Basic particle made up of two neutral layers is in the state of X4 = +1 or X4 = -1, which means its anti state is itself.
The micro standard is also applicable for the determination of the X4 states of the layer itself.
And so on, the micro standard principle is also applicable to the determination of the states of X4 = +2,+3,+4,+5……+n and their counter part X4 = - 2,-3,-4,-5……-n.
So, if we define proton “particle”, then electron actually is a kind of “anti particle”, while positron is a kind of “particle”.

Watch the context in counter way, it appears that the chirality of layer determines the contrary of four dimensional space. Inversion of the chirality of layer leads to the inversion of four dimensional space. Inversion of four dimensional space leads to the inversion of unit electrical charge.

Note:
Maybe, equation①②③ is not necessarily the accurate-enough equations to describe the real wave function distribution fields of basic particles, but it still can demonstrate some properties and has no contradiction to facts:
1. Under such a model, unit electrical (charge) interaction between basic particles will be just the determination of probability method of existence each other, and only has something to do with distance (∝1/x or say∝|1/x|²= 1/x²).
2.Since the value of three dimension spacial momentum P does not affect the result of integration in equation①②③, that means the relative motion of basic particles do not affect the volume of unit electrical charge.

Additions:
Below are some predictions based on the above context:
1. When the circle kind standing wave mentioned in the above context broken, it will transform into a kind of released photon. So, the flying track of leased photon in flat space should have three types: straight line, straight right handed helical line, straight left handed helical line.
2. In micro, the anti photon of a released photon is itself in case of straight line track. But in case of straight helical track, the anti photon of a released photon is its counter part with inverted chirality. But in macro, namely, in respect of space and time effect, they are all the same and in the state of X4 =∞.




X4 Theory of Photon (Ⅳ)
Photon VS Wavicle

This chapter starts from a strange topic: Analysis of Probability Wave Speed
The speed of probability wave of a free particle could be calculated as below:
If v is the moving speed of the particle, then, the speed of the corresponding probability wave:
u = γλ = (E/h)( h/P) = E/P =(mc²-m0c²)/ mv

= c²/v – (c²/v)√1-(v²/c²) = c²/v – (c/ v)√c²-v²
Here c is light speed.
When v → c, Lim u = c,
When v → 0 , Lim u = 0,
When 0< v < c, v²< c², v ^4 < v²c²,
So, v ^4 - 2 v²c²< -v²c²
So, v ^4 - 2 v²c²+ c ^4 < c ^4 - v²c²
So, (c²- v²) ^2 < c²(c²- v²)
So, c²- v²< c√c²-v²

So, v²> c²- c√c²-v²

So, v > c²/v – (c / v)√c²- v²
So, v > u
Since the frequencyγand wavelengthλof probability wave are meaningful in physics, their product, the wave speed u should be meaningful in physics too. And we got one strange phenomenon: the moving speed of a free particle (except photon) is always not in conformity with the wave speed of the associated probability wave. How to understand it?
Below is a try to answer this question in logic.
1. A “particle” (except photon) is actually a “wavicle” which has two aspects: the particle characteristic / or say the certain aspect as well as probability (wave) characteristic / or say the uncertain aspect.
2. For a released photon, seems that those two aspects merged. The question here is that which aspect disappears? The wave property of light wave is obviously not that kind of probability wave. So we can estimate primarily that it’s the probability (wave) characteristic / or say the uncertain aspect disappears.
Next we turn to X4 Theory. In X4 Theory we expect that X4 = +2, +3, +4, +5…+n… represent the states similar to X4 = +1. We can imagine that they are certain matter states (worlds) similar to but different from X4 = +1 matter states(world). And 0 < X4 < ∞ is the relevant probability (wave) state of that matter world. A particle is actually a “wavicle”. While light / released photon has only one state X4 = ∞. It demonstrates that it’s the probability (wave) characteristic / or say the uncertain aspect disappears as well as that the wave property of light wave is not that kind of probability wave.
So, what’s a photon? An appropriate solution is that photon is a section of electromagnetic wave.
Something interesting is: considering a photon appears in a 3D space point, and it also propagates ahead in the form of (electromagnetic) wave. That means light speed in photon frame is also c.


X4 Theory of Photon (Ⅴ)
The Mass Space
First, there is a question, why the energy equation for a released photon is E = hγ in Quantum and need not to take the number of crests(n of λ, here n is a natural number) into account?
But a released photon is just that of a section of electromagnetic wave, its energy E should ∝the number of crests(n of λ) no matter what method is used to calculate.
It imply that all released photons have the same number of crests(n of λ)? Temporarily suppose it is and see what will happen.
Next, we refer to the chapter X4 Model of Unit Electrical Charge and play a game of Geometry.
We unfold the standing wave (suppose |X4| = 1), namely make its radius r →∞, and it turns into two released photons.(Pay attention please, it’s only a game of Geometry and might not be the real physical course of transformation)
We watch the game in counter way, it’s two released photons turn into a standing wave.
And we got: standing wave which constitute all kinds of basic particles have the same number of crests (nt of λt when referring to travelling waves, and ns of λs when referring to standing waves. The lower index t means travelling wave and s means standing wave in this context)

We turn to SR and talk about space at this moment temporarily.
The equation for the traditional Lorentz transformation of length contraction is: L’ = L / γ
The mass – speed equation is M = γM0
Then, ML’ = M0L so, L’ = M0L / M
Because M0 and L are constants, then: L’ ∝ 1 / M. This might be called the “mass – space equation”.
Mass M is a scalar, so the equation reflects the contraction of size in all directions due to the increase of mass.
It seems that the “mass – space equation” is a derived one. But its components “mass” and “space” are most basic physical elements. Actually, it should be a more basic equation than the equation for the traditional Lorentz transformation of length contraction and the mass – speed equation. It describes more basic natural rule.
During the course of exploration, people perhaps touch the leaves of a tree first, then the sticks, and so on the stock, at last the root. But for a tree, the root is the most basic.
From the angle of the physical substance of the object itself, perhaps the research might be more in depth and sufficient.
Moreover, when we replace the 3D space Gama factor γ with 4D space Gama factor Ý in the course of derivation above, we also can get the “mass – space equation”. That’s to say, the “mass – space equation” is also applicable to those matter worlds of |X4| = 2, 3, …, n.
It demonstrates that the three dimension physical space concept is induced by mass. Give it a nickname here: the Mass Space (Mspace). And Mspace ∝ 1/M.
Next, we try to use the basic particle model in the chapter X4 Model of Unit Electrical Charge and the temporary conclusion of same number of crests in this chapter to calculate the radius of basic particle.
Below, we calculate the central line of the helical track of layer instead of the helical track itself because the speed of light should be calculated on the central line. And the wavelengthλt should be the projective wavelength on the central line.
E = MC² = 2hγt = 2hC /λt then:
λt = 2h / MC then:
The radius of basic particle is:
r = ntλt / 2π = nth /πCM
Because nt, h, π, C are all constants, we use a constant “a” for simplicity and a = nth/πC, then:
r = a/M
Namely, r ∝1/M. In fact, it’s the same meaning as Mspace ∝ 1/M in SR above.
(note: picture and some symbol miss during cyber transition)

Li Qiang Chen
Jan 27, 2020
0 Replies
 
Setanta
 
  1  
Reply Sun 26 Jan, 2020 04:20 pm
So, this guy is just jerking off in public?
htam9876
 
  1  
Reply Tue 28 Jan, 2020 03:20 am
@Setanta,
Dear, I just want to show up the simplest / basicest equation in cosmos. haha...
Setanta
 
  1  
Reply Tue 28 Jan, 2020 06:12 am
@htam9876,
I am not your "Dear," whether you are male or female. My remark was a reference to your apparent indifference to the concept of conversation.
htam9876
 
  0  
Reply Tue 28 Jan, 2020 06:44 am
@Setanta,
Oh, I am not male nor female. I am an alien from other planet. I really don't know how to communicate with human on the earth. Sorry.
Next, is an example of the application of the mass space equation in reality.

X4 Explanation of the μ Hydrogen Phenomenon
When the electron of a Hydrogen atom is replaced with a μ particle, the atom turns to be μ Hydrogen. For detailed information, see relevant publications.
There is a phenomenon occurs: the radius of the proton in μ Hydrogen atom contracted. Why?
Below we try to use the conclusion in the mass space to explain it.
The radius of the proton in Hydrogen atom is r1 ≈ 8.768×10ˆ-16m. The mass of an electron is Me ≈ 9.1×10ˆ-31kg, while the mass of aμparticle is Mμ ≈ 200 ×9.1×10ˆ-31kg.
The mass of a proton is Mp ≈ 1.6726×10ˆ-27kg.
The reduced mass of the electron in Hydrogen atom is:
μ1 = Me Mp/ ( Me+ Mp) ≈ (9.1×10ˆ-31) ×(1.6726×10ˆ-27)/ [(9.1×10ˆ-31)+(1.6726×10ˆ-27)] ≈ 9.0951×10ˆ-31kg
The increased mass of the proton in Hydrogen atom is:
M1 = Mp+ Me -μ1 ≈ (1.6726×10ˆ-27)+ (9.1×10ˆ-31)- (9.0951×10ˆ-31) ≈1.6726×10ˆ-27kg
The reduced mass of theμparticle in μHydrogen atom is:
μ2 = Mμ Mp/ ( Mμ+ Mp) ≈ (200×9.1×10ˆ-31) ×(1.6726×10ˆ-27)/ [(200×9.1×10ˆ-31)+(1.6726×10ˆ-27)] ≈ 0.1641×10ˆ-27kg
The increased mass of the proton in μHydrogen atom rise to be :
M2 = Mp+ Mμ –μ2 ≈ (1.6726×10ˆ-27)+ (0.182×10ˆ-27)- (0.1641×10ˆ-27) ≈1.6905×10ˆ-27kg
Assume the radius of the proton inμHydrogen atom is r2, and use the relationship r ∝1/M in X4 Theory of mass space, then:
r2 = r1 (M1 / M2) = (8.768×10ˆ-16) (1.6726×10ˆ-27) / (1.6905×10ˆ-27) ≈ 8.675×10ˆ-16 m.
It decreases.
The measured radius of the proton inμHydrogen atom is r2 ≈ 8.418×10ˆ-16m.
Theory is basically in conformity with experiment.

Conclusion: It’s the rise of the increased mass of the proton leads to the contraction of the radius of the proton inμHydrogen atom.
Setanta
 
  1  
Reply Tue 28 Jan, 2020 06:46 am
@htam9876,
Conclusion: the author here is just jerking off in public.
htam9876
 
  0  
Reply Tue 28 Jan, 2020 06:49 am
@Setanta,
Conclusion: this alien really don't know how to communicate with human on the earth.
0 Replies
 
htam9876
 
  1  
Reply Tue 28 Jan, 2020 09:47 am
@htam9876,
A thread is for those who is interested in the topic and not for those who is not interested in topic.
0 Replies
 
Setanta
 
  1  
Reply Tue 28 Jan, 2020 01:05 pm
Are you trying to police this thread? Good luck . . .
htam9876
 
  0  
Reply Tue 28 Jan, 2020 07:44 pm
@fresco,
I think now it's time to reply to you, fresco.
Actually this thread is to talk about the mass space equation which has hidden in SR for one century. I think I have uploaded enough material to demonstate it: derivation from macroscopic angle as well as from microscopic angle, configuration of thought experiments ...
I don't know what the term " contextual utility" means exactly in English. But I think that a true equation in physics should not be only "description" nor only math game, it should have real physical meaning. That's why I tried to use the mass space equation to explain the u hydrogen phenominon and verified it in reality.
...........................................
Perhaps the true logic in nature is: motion in 3D space causes the increase of mass and the increase of mass causes the contraction of length in all directions.
...........................................
Regards.
0 Replies
 
 

Related Topics

Relativistic mechanics - Discussion by Granpa
Tesla's take on relativity - Discussion by gungasnake
Cesium clocks??? - Question by gungasnake
Why c, revisited still again - Question by dalehileman
Is there a relativist in the crowd - Question by dalehileman
relativity - Question by alexjlaonnae
Does light have Mass? - Question by peter jeffrey cobb
simple relativity question - Question by ralphiep
 
  1. Forums
  2. » Is the Sun Round or Thin?
Copyright © 2021 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.03 seconds on 03/01/2021 at 11:55:41