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Logic Riddle Collections

 
 
cmellon
 
Reply Sat 11 Jun, 2005 03:22 am
Hi,

Is this a forum to post riddles to audience? Let me start with a very easy one first. If this is answered, I will post another riddle in the same thread and so on. Check back the thread every now and then to see if the latest riddle has been answered and if there's a new riddle. If latest riddle hasn't been answered, no new riddles will be posted.

All riddle is logical and no trick. Not involving too much math calculation either, so it's suitable for people of all background.

Here is riddle #1:

You have two jars. The first jar is a 3-litre jar, and the other one is a
5-litre jar. Your task is to get 4-litre water from a river. You have nothing else other than the two jars to do the task.

You can't approximate water in the jar. For example, you can't approximate 2-litre water in a 3-litre jar. In the 3-litre jar situation, all you know is that when you fill the jar full, the content is 3 litre.

How do you do it?
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Don1
 
  1  
Reply Sat 11 Jun, 2005 06:01 am
First, fill up the three litre jug. Pour the three litres into the five litre container. Refill the three litre jug and once again pour it into the five litre container until it is full. The three litre jug now contains one litre.

Empty the five litre container and then pour the one litre of water into it. Now, fill the three litre jug up again and pour it into the five litre container. The container will now contain the desired four litres.
0 Replies
 
whimsical
 
  1  
Reply Sat 11 Jun, 2005 09:12 am
No new riddle was posted to begin with. Wink

Whim
0 Replies
 
cmellon
 
  1  
Reply Sat 11 Jun, 2005 09:26 am
Riddle #2: Three people with four hats
Very nice... now onto the 2nd riddle. This riddle looks long and complicated, but it is actually quite a simple story. Try to read the whole story:

Three people were caught by a wizard and was about to be turned into frogs. The three pleaded the wizard to spare their lives.

So the wizard, being a riddler, promise to free them if they can answer his riddle.

The three people were told to stand on a stairs (see pic below). The first person (A) stands at the top of the stairs, the second person (B) stands at the middle of the stairs, and the last person (C) stands at the bottom of the stairs.

__A__
|
|__B__
|
|__C__


All people is facing down. So A can see B and C. But B can only see C, but not A. C can see no one.

The wizard has a bag containing 4 hats: 2 whites, and 2 blacks. The wizard will randomly pick three hats and put it on top of each of the three people's head. Since the wizard randomly picks only 3 hats out of 4 hats, those three hats could be:

2 blacks, 1 white or
2 whites, 1 black

The wizard blinfolded the three people, then randomly draws 3 hats, then put each hat on their head, then open the blindfold. On the count of 3 seconds, if anyone from the three people can answer the color of the hat on top of his own head correctly, the three people will be free. If the answer is wrong, they will immediately die. So nobody will answer unless he is absolutely sure with his own answer.

1 second, nobody answered. 2 second, still nobody answer. Then suddenly the person in the middle (B) says the color of his own hat. He is confident his answer is correct and it's indeed correct.

The question is.... why or how come B can answer?
0 Replies
 
markr
 
  1  
Reply Sat 11 Jun, 2005 10:51 am
Since A didn't know the color of his own hat, the color of B's hat is different than the color of C's hat. If they were the same color, A would have known the color of his own hat.
0 Replies
 
cmellon
 
  1  
Reply Sat 11 Jun, 2005 11:00 am
markr wrote:
Since A didn't know the color of his own hat, the color of B's hat is different than the color of C's hat. If they were the same color, A would have known the color of his own hat.


Correct answer in general, but may confuse some others. May be clarified a bit further using color examples. Like what colors A see, and what color B see, and what color B says he is wearing.
0 Replies
 
carditel
 
  1  
Reply Sat 11 Jun, 2005 11:25 am
If "b+c" have the same colour hat "a" will know his is the opposite colour.
If "a" says nothing, "b" will know "a" can see two different hats, so "b" knows his is the opposite of "c".
0 Replies
 
whimsical
 
  1  
Reply Sat 11 Jun, 2005 11:28 am
You need to solve it giving the colors too.

Whim
0 Replies
 
carditel
 
  1  
Reply Sat 11 Jun, 2005 11:33 am
"b+c" have black, "a" knows he has white.
"b+c" have white and black, "b" knows if his was black "a" would have said white, so his must be white.
0 Replies
 
cmellon
 
  1  
Reply Sat 11 Jun, 2005 11:48 am
Too many smart people on this boad.... Smile

Here is third riddle for the day... if this one is answered very soon, next riddle will have to wait at least one day...... Razz

The third riddle is exactly the same story with the second riddle. However, this one instead of drawing 3 hats from a possible 4 hats, the wizard draws 3 hats from a possible 5 hats. The five hats are 3 whites and 2 blacks. Since the wizard draws only 3 hats randomly, the possibilites are:

3 whites or
2 whites 1 black or
2 blacks 1 white

The wizard blinfolded the three people, then randomly draws 3 hats, then put each hat on their head, then open the blindfold. On the count of 3 seconds, if anyone from the three people can answer the color of the hat on top of his own head correctly, the three people will be free. If the answer is wrong, they will immediately die. So nobody will answer unless he is absolutely sure with his own answer.

1 second, nobody answered. 2 second, still nobody answer. Then suddenly the person in the bottom (C) says the color of his own hat. He is confident his answer is correct and it's indeed correct.

The question is.... why or how come C can answer? And what color does C say he is wearing?
0 Replies
 
markr
 
  1  
Reply Sat 11 Jun, 2005 04:25 pm
If B and C both had black, A would know he has white. Therefore, at least one of B and C are white. B and C are both aware of this.

If B saw black on C, then B would know he must have white (from above). Therefore, C has white. C is aware of this.

C correctly says he has white.
0 Replies
 
cmellon
 
  1  
Reply Sat 11 Jun, 2005 08:32 pm
Correct answer by markr.... and very clear..... Smile

Here's the fourth riddle.... very easy one....

If I travel from point A to B at a speed of 20 miles per hour, and then travel back from point B to A at a speed of 30 miles per hour. What is the average speed of my whole trip and explain how you got the number.
0 Replies
 
carditel
 
  1  
Reply Sun 12 Jun, 2005 12:35 am
A to B is 30 miles journey takes 1 1/2 hrs
B to A is 30 miles journey takes 1 hr
total journey 2 1/2 hours total distance 60 miles
average speed 24 mph
0 Replies
 
cmellon
 
  1  
Reply Sun 12 Jun, 2005 10:31 am
Correct answer by carditel....

Here's the fifth riddle:

There is one big family trying to cross a river with only 1 boat. The boat can only load 2 objects, whether it's human or animal.

The family trying to cross the river consists of
1 dad
1 mom
2 sons
2 daughters
1 maid
1 fierce dog

If any of the son is left alone without the dad with him at the same place, the mom will kill the son.

If any of the daughter is left alone without the mom with her at the same place, the dad will kill the daughter

If the dog is left without the maid at the same place, the dog will kill everyone else.

Only the dad, the mom, or the maid can steer the boat.

Question: How can the whole family, including the dog, cross the river?
0 Replies
 
lem
 
  1  
Reply Tue 14 Jun, 2005 10:23 pm
That's one violent family Shocked

I take the conditions as "if any of the sons are left with mom but without dad at the same place they will be killed", and likewise with mom and daughters. In other words sons can be left without dad for as long as mom is not around. Otherwise it is unsolvable. Here's my script:

1. Maid with Dog crosses (dad,s1,s2,mom,d1,d2 -- maid,dog)
2. Maid Returns (dad,s1,s2,mom,d1,d2,maid -- dog)
3. Maid with Daughter1 cross (dad,s1,s2,mom,dot2 -- dot1,maid,dog)
4. Maid returns with Dog (dad,s1,s2,mom,d2,maid,dog -- d1)
5. Mom with Daughter 2 cross (dad,s1,s2,maid,dog -- mom,d1,d2)
6. Mom returns (dad,s1,s2,mom,maid,dog -- d1,d2)
7. Mom and Dad cross (s1,s2,maid,dog -- dad,mom,d1,d2)
8. Dad returns (dad,s1,s2,maid,dog -- mom,d1,d2)
9. Maid and Dog cross (dad,s1,s2 -- mom,d1,d2,maid,dog)
10. Mom returns (dad,s1,s2,mom -- d1,d2,maid,dog)
11. Mom and Dad Cross (s1,s2 -- dad,mom,d1,d2,maid,dog)
12. Dad returns (dad,s1,s2 -- mom,d1,d2,maid,dog)
13. Dad and Son1 cross (s2 -- dad,s1,mom,d1,d2,maid,dog)
14. Maid and dog returns (s2,maid,dog -- dad,s1,mom,d1,d2)
15. Maid and son2 cross (dog -- dad,s1,s2,mom,d1,d2,maid)
16. Maid returns (maid, dog -- dad,s1,s2,mom,d1,d2)
17. Maid and dog cross ( -- dad,s1,s2,mom,d1,d2,maid,dog)
0 Replies
 
cmellon
 
  1  
Reply Mon 20 Jun, 2005 01:24 am
Correct answer by Lem.

Here is another one:

Four people try to cross a bridge at night. They only have 1 flashlight. The bridge can only have two people at one time.

First person can cross the bridge in 5 minutes. Second person in 10 minutes. Third person in 20 minutes. And last person in 25 minutes.

When a slower person cross the bridge together with a faster person, the time it takes to cross the bridge is the slower person's time. For example, if a 5 minute person cross the bridge with a 25 minute person, it takes 25 minutes to cross the bridge, since the faster person (the 5 minute guy) needs to accompany the slower person (the 25 minute guy) with flashlight.

The flashlight's battery can only last 1 hour. How will all 4 people cross the bridge?
0 Replies
 
carditel
 
  1  
Reply Mon 20 Jun, 2005 02:15 pm
1. 5 min person and 25 min person-------25 min
2. 5 min person returns----------------------5 min
3. 5 min person and 20 min person-------20 min
4. 5 min person returns----------------------5 min
5. 5 min person and 10 min person-------10 min

Total time 60 mins all persons have crossed.
0 Replies
 
markr
 
  1  
Reply Mon 20 Jun, 2005 09:55 pm
carditel wrote:
1. 5 min person and 25 min person-------25 min
2. 5 min person returns----------------------5 min
3. 5 min person and 20 min person-------20 min
4. 5 min person returns----------------------5 min
5. 5 min person and 10 min person-------10 min

Total time 60 mins all persons have crossed.

That adds up to 65 minutes.

5/10: 10 min
5: 5 min
20/25: 25 min
10: 10 min
5/10: 10 min
Total is 60 minutes. The key his having the two slowest travel together.
0 Replies
 
carditel
 
  1  
Reply Mon 20 Jun, 2005 11:40 pm
I had had a hard day.
0 Replies
 
cmellon
 
  1  
Reply Fri 24 Jun, 2005 10:11 pm
Wow.... nobody can answer this yet for so long? Very Happy
0 Replies
 
 

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