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How to I use the standard normal table to get the following Z value?

 
 
Reply Sun 27 Jan, 2019 12:01 am
So I am given that P(X≤31.5)=0.05 and according to the textbook, after standardizing and using this standard normal table we get

(31.5−mean)/(standard deviation)=−1.645.

Can someone explain to me how they got -1.645 from 0.05? I udnerstand that the left side is just plugging in X into the formula, but how did we turn 0.05 into -1.645?
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Type: Question • Score: 1 • Views: 507 • Replies: 1
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engineer
 
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Reply Sun 27 Jan, 2019 06:09 am
@FelixTruffle,
If you look in your textbook or a z score calculator website, you see that a P value of .05 gives you a z score of -1.645. This website has a calculator and an explanation.
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