The probabilities that there will be a certain number of white balls in the bag after the first step are:
Prob. of '0': 0.319309
Prob. of '1': 0.420144
Prob. of '2': 0.207344
Prob. of '3': 0.047849
Prob. of '4': 0.005148
Prob. of '5': 0.000206
(source:
http://stattrek.com/online-calculator/hypergeometric.aspx)
The probabilities that there will be a certain number of white balls in the bag after the first step,
and then we will subsequently draw a white ball on the second step are:
Probability 0 are in the bag, and we draw a white one: 0.319309*(0/5) = 0
Probability 1 is in the bag, and we draw a white one: 0.420144*(1/5) = 0.084029
Probability 2 are in the bag, and we draw a white one: 0.207344*(2/5) = 0.082938
Probability 3 are in the bag, and we draw a white one: 0.047849*(3/5) = 0.028709
Probability 4 are in the bag, and we draw a white one: 0.005148*(4/5) = 0.004118
Probability 5 are in the bag, and we draw a white one: 0.000206*(5/5) = 0.000206
The probability that we will ultimately draw a white ball is this second set of figures, all added together, which is 0.2.
So markr's sleight-of-hand approach gets him to the right answer in the end.