4
   

network theorem

 
 
Reply Wed 20 Aug, 2014 11:41 am
In the circuit given below, the value of R requiredfor the transfer of maximum power to the load having a resistance of 3 ohm is http://i36.photobucket.com/albums/e18/rjanand38/kite_zps5e36f5a8.jpg
a) 0
b) 3 ohm
c) 6 ohm
d) infinity

my doubt here is i got two answers
1) 0, as according to power transfer theorem load should be variable but here source resister itself is variable.
2) 6 ; source resistance = load resistance
clarify...................
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Type: Question • Score: 4 • Views: 542 • Replies: 2
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DrewDad
 
  1  
Reply Wed 20 Aug, 2014 12:11 pm
@anand raj,
To maximize power dissipated you need to maximize current, which means you want to minimize resistance.

The variable resistor can apparently me anything from zero to infinity. Setting it to zero results in a total circuit resistance of 3 ohms. Setting it to infinity results in a total circuit resistance of 9 ohms. Which maximizes current at the 3 ohm load?
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dalehileman
 
  1  
Reply Wed 20 Aug, 2014 01:07 pm
@anand raj,
Quote:
2) 6 ; source resistance = load resistance
Raj that's not ordinarily what's meant by "source resistance." In the circuit you've given us the internal resistance of the battery itself would be so-called but given no instruction to the contrary we must consider it zero, in which case of course the load gets most current at zero setting of the pot
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