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help me out in mcq's

 
 
nehaz
 
Reply Fri 30 May, 2014 08:40 am
Question 1. A medical clinic in a small city in the state of Washington wants to estimate the mean serum cholesterol level (measured in mg of cholesterol per 100 mL of blood) of teenage males. Based on the following summary data taken from a random sample of 10 teenage males from this community, compute a 90% confidence interval for the mean serum cholesterol level of teenage males in this city. Assume that the sample was taken from a normal distribution. Round your confidence limits to 2 decimal places.
Summary Data: n = 10, , s = 24.920
Choose one answer.

A. (207.15, 240.67)

B. (209.12, 238.01)

C. (210.12, 239.56)

D. (213.34, 242.83)

E. None of the above

Question2
Pschological tests are often used to determine the hostility levels in people. High scores on the HLT pschological test corresponds to high hostility levels. Suppose that 26 college students, all with equally high HLT test scores, were separated into two groups randomly. Group 1 (10 students) was treated for high hostility levels by using Method A; whereas Group 2 (16 students) was treated for high hostility levels by using Method B. Both groups were treated for a period of 5 months, at which time all 26 students were again given the HLT test. Below is the summary data on the HLT test for the two groups.
Group 1: sample mean is 79 and sample standard deviation is 7
Group 2: sample mean is 84 and sample standard deviation is 8

Compute a 95% confidence level for the difference in the means of the two treatment methods and select the best answer below. Assume that the independent random samples were taken from normal distributions and that the two population variances are equal.
Choose one answer.
A. We are 95% confident that there is no statistically significant difference in the mean treatment methods for hostility.
B. We are 95% confident that Method A is a better treatment for hostility than Method B.
C. We are 95% confident that Method B is a better treatment for hostility than Method A.
D. We are 95% confident that there is a statistically significant difference in the mean treatment methods for hostility.

Question4
A random sample of size 100 was taken from a population. A 94% confidence interval to estimate the mean of the population was computed based on the sample data. The confidence interval for the mean is: . What is the z-value that was used in the computation. Round your z-value to 2 decimal places.
To answer the question input only the actual number. Do not include units. Do not give your answer in sentence form -- just include the numerical answer rounded to exactly 2 decimal places.
Answer:

Question5

The U.S. Food and Drug Administration (FDA) performed a study that compared the carbohydrate content (as a percentage of weight) of several major brands of corn and potato chips. Fourteen brands of corn chips were sampled and 14 brands of potato chips were sampled. Data was collected and the following 95% confidence interval was computed for the difference in means. Intrepret the 95% confidence interval for the difference in the mean carbohydrate content between the Corn Chip and Potato Chip groups.
The C.I. is:
where = the average carbohydrate content as a percentage of weight in corn chips.
and = the average carbohydrate content as a percentage of weight in potato chips.
Select the best answer below.
Choose one answer.
A. We are 95% confident that there is no statistically significant difference in the average carbohydrate content as a percentage of weight between corn chips and potato chips.

B. We are 95% confident that the average carbohydrate content as a percentage of weight in corn chips is lower than the average carbohydrate content as a percentage of weight in potato chips.

C. We are 95% confident that the average carbohydrate content as a percentage of weight in corn chips is higher than the average carbohydrate content as a percentage of weight in potato chips.

D. None of these are correct.

Question6

The width of a confidence interval is defined to be the upper bound of the confidence interval minus the lower bound of the confidence interval. For example, if a confidence interval is , then the width of this confidence interval is . Assume that we are estimating the mean of a population. Assuming that the confidence coefficient, the sample mean and sample standard deviation stay the same, if we decrease the the sample size of a confidence interval from 100 to 50, then the width of that confidence interval will also decrease.
Answer:

True
or
False
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