Probability - select 10 cards WITH replacement

I tried to attempt some but do not now if I am doing them right...

Select 10 cards from a standard 52-card deck, with replacement, so that independence is achieved. Compute the following binomial probabilities:

(a) at least four of the cards are clubs.
Attempt: .14599+.05839+.1622+.003+.3.862+2.861+9.536=

(b) exactly two of the cards are clubs.
Attempt = .2815

(c) at most five cards are clubs.

(d) at least one card is a club.
Attempt: (4/52)(4/52)(4/52)(4/52)(4/52)(4/52)(4/52)(4/52)(4/52)(4/52) =

(e) exactly three of the cards are 5’s